PHP how to use muliple parameters and update mySQL table with them - php

Question

Im tying to update a table with the followning function in PHP. The problem is that the second parameter $work_place is not accepted and the update fails. This is my first time working with PHP and mySQL so my knowledge is a bit limited.
public function timestampOut($work_done, $work_place)
{
// clean the input to prevent for example javascript within the notes.
$work_done = strip_tags($work_done);
$work_place = strip_tags($work_place);
$userLastTimestampID = $this->getUserLastTimestampID();
$sql = "UPDATE timestamps SET timestamp_work_description = :work_done, timestamp_work_dropdown = :work_place, timestamp_out = now() WHERE timestamp_id = $userLastTimestampID[0] AND user_id = :user_id";
$query = $this->db->prepare($sql);
$query->execute(array(':work_done' => $work_done, ':user_id' => $_SESSION['user_id']));
$count = $query->rowCount();
if ($count == 1) {
return true;
} else {
$_SESSION["feedback_negative"][] = FEEDBACK_NOTE_CREATION_FAILED;
}
// default return
return false;
}

Answer 1

You just need to add work_place to the param array in your execute call, like so:
$query->execute(array(':work_done' => $work_done, ':work_place' => $work_place, ':user_id' => $_SESSION['user_id']));

Answer 2

Please read again how execute works. You would want to use it like this:
$query->execute(array(':work_done' => $work_done, ':work_place' => $work_place, ':user_id' => $_SESSION['user_id']));

Answer 3

Try to replace
$query->execute(array(':work_done' => $work_done, ':user_id' => $_SESSION['user_id']));
with
$query->execute(array(':work_done' => $work_done, ':user_id' => $_SESSION['user_id']), ':work_place' => $work_place);