I am using this library from Twilio to send multiple numbers SMS.
https://www.twilio.com/docs/quickstart/csharp/sms/sending-via-rest
I have a mysql database and a table (called contacts) with the following attributes:
1. Name
2. Number
Instead of using a For While loop and read the full script for each number, I want to use an array as shown in the above link.
How do I make an array in PHP with the data pulled in from the table instead of a manual insert?
From Twilio
var people = new Dictionary<string,string>() {
{"+14158675309","Curious George"},
{"+14158675310","Boots"},
{"+14158675311","Virgil"}
};
My code
$sql = "SELECT * from contacts";
$result = mysql_query($sql,$con);
var people = new Dictionary<string,string>() {
mysql_fetch_array($result)
};
I need numbers and names associated within the array.
why not :
$sql = "SELECT * from contacts";
$result = mysql_query($sql,$con);
var people = new Dictionary<string,string>()
for each($result as $contact)
{
//Add $contact['Name'], $contact['Number'] to dictionary.
//or if you use an array instead of a dictionary.
// $tab['number']=$contact['Number'];
// $tab['name']=$contact['Name'];
// array_push($people,$tab);
}
return $people;
?
Related
My system is composed of 3 components.
ios - php - mysql
If ios users select multiple 'id's,
then, ios app posts these selected 'id' request to server,
and, the server finds the data based on selected 'id's in MySQL.
and finally, the server passes these data to ios app.
These are the PHP statements I tried.
<?php
$id_0 = $_POST['0'];
$id_1 = $_POST['1'];
$id_2 = $_POST['2'];
$id_3 = $_POST['3'];
...
$id_n = $_POST['n'];
$conn = mysqli_connect('address', 'user', 'password', 'database');
$sql = "SELECT * FROM firstname WHERE id = '$id_0'";
if ($result = mysqli_query($conn, $sql)) {
$resultArray = array();
$tempArray = array();
while($row = $result->fetch_object()) {
$tempArray = $row;
array_push($resultArray, $tempArray);
}
} else {
}
mysqli_close($conn);
?>
To get multiple 'id' data, I found that I need to use loop statement.
But the problem is, the number of selected id are variable.
I think that in this code, I need two loop statement.
To get multiple data based on multiple id(the number of id are variable)
To append these data into array
I don't know how to use loop statement when the range is not defined.
How can I use loop statement in PHP, and how can I rearrange these codes?
I'm sure this question is a duplicate but I can't find an exact source.
Your current method means you need to run a whole MySQL query for each iteration.
As the query results will never change what the iteration contains, therefore; you can simply rework it to use MySQL IN to load all of your variables at once:
Step 1) Take all the values and place them in a single array.
$new = []; //new array
foreach ($_POST as $key=>$id){
// Check it is a numeric key
// Check id value is valid to avoid importing other POST values
if((int)$key == $key && (int)$id == $id){
$new[] = $id;
}
}
The above code block is nessecary to stop using values from $_POST['button'] or other posted data that should not be included. This step can be removed if you can clarify your posted data, such as saving all ids to a $_POST['id'] array itself.
Step 2) Empty the array of null/void or repeated values.
$new = array_unique($new);
Step 3) Turn the array into a string, inside the SQL
$arrayString = implode(',',$new);
Step 4) Plug the string into the SQL IN clause:
$sql = "SELECT * FROM firstname WHERE id IN (" . $arrayString . ") ORDER BY id";
Simplified and reduced:
$new = []; //new array
foreach ($_POST as $key=>$id){
if((int)$key == $key && (int)$id == $id){
$new[] = $id;
}
}
$new = array_unique($new);
$sql = "SELECT * FROM firstname WHERE id IN (" .
implode(',',$new) . ") ORDER BY id";
The SQL query above will give you an array of arrays, each one a different row. You can the order them, sort them and output them in PHP as you wish.
See also: This Q&A.
BUT
As expressed by others, you really, REALLY should be using Prepared Statements with MySQLi.
See also here, here and here to see further how to do it and WHY you should do it.
Top Tips:
Numerical columns (typical of id columns) in MySQL do not need the ' quotes.
Until you're using Prepared Statements you can typecast the variables to integers ((int)$var) to limit risk.
It is better to specify the columns you need rather than to use the * catch-all.
Your $_POST data should be an array $_POST['ids'][...].
Eat five different pieces of fruit or veg' a day.
Never trust user input!
I am working with jstree. The tree works fine.I send JSON to a PHP file with JQuery. This works fine.
$("#button3").click(function(){
//json object
var objtree = $("#container").jstree(true).get_json('#', { 'flat' : true });
var fulltree = JSON.stringify(objtree);
var myarray = $.parseJSON(fulltree);
var params = { myarray: myarray };
var paramJSON = JSON.stringify(params);
//sending to php file
$.post('update.php',{ data: paramJSON });
});
Then in the php file (update.php), I update mySQL table by: deleting all the records in $tablename ($sql1) and inserting the information gotten from the JSON ($sql2). This works fine.
<?php
$connection = mysqli_connect($servername, $user,$password,$database) or die("Error " . mysqli_error($connection));
$test = $_POST["data"];
$obj = json_decode($test, true);
$data = $obj["myarray"];
//first query
$sql1 = "DELETE FROM $tablename";
$connection ->query($sql2);
foreach($data as $val){
//second query
$sql2 = "INSERT INTO $tablename(id,parent,text) VALUES('".$val['id']."', '".$val['parent']."', '".$val['text']."')";
$result = mysqli_query($connection, $sql) or die("Error in Selecting " . mysqli_error($connection));
}
mysqli_close($connection);
?>
But what I want is not to delete everything in the table then insert them brand new. But an SQL statement to update the old values (using the id maybe?) and insert the new values.
So like:
If id exists:
update row
else:
insert new row
I am new to PHP and SQL. So my problem is knowing the PHP syntax for accessing JSON array information. So please any example would be much appreciated!
First, you'll use a PHP function to get all rows matching the given ID. if this returns one, you'll use another function to UPDATEwhere the ID == valueFromPreviousFunction, else you'll call a function to INSERT a new row.
$check = mysqli_query($connection,"SELECT * FROM `your_table_name` WHERE `id`='".$val["id"]."'");
if(mysqli_num_rows($check)==1)
{
//Update the row
$update = mysqli_query($connection,"UPDATE `table_name` SET `parent`='".$val["parent"]."', `text`='".$val["text"]."' WHERE `id`='".$val["id"]."'");
}
else
{
//Insert the row
}
There isn't a command to do what you want in a single operation.
You should either fetch all ids beforehand and run an update for each one of them separately, or use REPLACE INTO.
Be careful with REPLACE INTO, though: if a row matching a primary/unique key exists, it first deletes it and then inserts a new one rather than updating the existing row.
To get an array like this array("123","456","789"); I use the code:
$Regids = mysql_query("SELECT regid FROM $tabel WHERE active = '1'");
while($row = mysql_fetch_array($Regids))
{
$result_array[] = "\"".$row['regid']."\"";
}
$regIDs = implode(',', $result_array);
$registrationIDs = array($regIDs); // array("123","456","789");
but I would expect PHP/mySQL has a simpler/faster solution for this?
I doubt that your code produces the result you want.
// assuming the this query produces 123,456,789
$Regids = mysql_query("SELECT regid FROM $tabel WHERE active = '1'");
// $row contains: array("123")
while($row = mysql_fetch_array($Regids))
{
$result_array[] = "\"".$row['regid']."\"";
}
// $result_array now contains: array("\"123\"", "\"456\"", "\"798\"");
$regIDs = implode(',', $result_array);
// $regIDS now contains a single string: "\"123\",\"456\",\"798\"";
$registrationIDs = array($regIDs);
// registrationIDs now is an array containing a single string: array("\"123\",\"456\",\"798\"");
If you really need an array that looks like this: array("123","456","789"); it is much simpler.
$Regids = mysql_query("SELECT regid FROM $tabel WHERE active = '1'");
while($row = mysql_fetch_array($Regids))
$registrationIDs[] = $row['regid'];
and that's all.
If your mysql result contains the number as an integer instead of an string you can convert it like this:
$Regids = mysql_query("SELECT regid FROM $tabel WHERE active = '1'");
while($row = mysql_fetch_array($Regids))
$registrationIDs[] = strval($row['regid']);
Also, keep in mind that the mysql_* functions are becoming deprecated. Don't start new code with it and make plans to port your existing code to mysqli_* or PDO.
You can use PDO implementation. At first sight, it may be more difficult to understand, but once you get used to it, it reveals to be really powerful and handy (IMHO! One year ago i switched to it and i love it)!
For your example, the PDO implementation would be like this:
/*CONNECT TO DB, FIRST. $dbh contains a handler to the current DB connection*/
$stmt = $dbh->prepare("SELECT regid FROM table WHERE active = '1'");
$stmt->execute();
$Regids = $stmt->fetchAll(PDO::FETCH_COLUMN,0);
There are many formatting options you can specify, like
PDO::FETCH_COLUMN
PDO::FETCH_ASSOC
and more...These options will allow you to get the array formatted as you prefer. As you can see i got the result in just 3 simple rows.
EDIT
Note: you are not escaping PHP variables before inserting them in your Query, and your code may suffer SQL INJECTION. Be careful!! Here is a simple guide to prevent it.
(In my code, just to be clear, i avoided the problem by just putting the table name instead of $table, just to show simply how to get the result you wanted.)
try this .. use Group concat in query ...
$Regids = mysql_fetch_array(mysql_query("SELECT GROUP_CONCAT(regid) as regids FROM $tabel WHERE active = '1'"));
echo $Regids[0]['regids']; // 123,456,789
for getting result "123","456","789" try this
$Regids = mysql_fetch_array(mysql_query("SELECT GROUP_CONCAT('\"',CONCAT(regid),'\"') as regids FROM $tabel WHERE active = '1'"));
echo $Regids[0]['regids']; // "123","456","789"
hello i want to create function with returning data, for example when i have the function advert i want to make it every time show what i need, i have the table id, sub_id, name, date, and i want to create the function that i can print every time what i need advert(id), advert(name), i want to make it to show every time what i need exactly and i want to save all my result in array, and every time grab the exactly row that i want
<?php
function advert($data){
$id = $_GET['id'];
$query = mysql_query("SELECT *FROM advertisement WHERE id = $id");
while($row = mysql_fetch_assoc($query)){
$data = array(
'id' => $row['id']
);
}
return $data;
}
echo advert($data['id']);
?>
but my result every time is empty, can you help me please?
There are so many flaws in this short piece of code that the only good advice would be to get some beginners tutorial. But i'll put some effort into explaining a few things. Hopefully it will help.
First step would be the line function advert($data), you are passing a parameter $data to the method. Now later on you are using the same variable $data in the return field. I guess that you attempted to let the function know what variable you wanted to fill, but that is not needed.
If I understand correctly what you are trying to do, I would pass in the $id parameter. Then you can use this function to get the array based on the ID you supplied and it doesnt always have to come from the querystring (although it could).
function advert($id) {
}
Now we have the basics setup, we want to get the information from the database. Your code would work, but it is also vulnerable for SQL injection. Since thats a topic on its own, I suggest you use google to find information on the subject. For now I'll just say that you need to verify user input. In this case you want an ID, which I assume is numeric, so make sure its numeric. I'll also asume you have an integer ID, so that would make.
function advert($id) {
if (!is_int($id))
return "possible SQL injection.";
}
Then I'll make another assumption, and that is that the ID is unique and that you only expect 1 result to be returned. Because there is only one result, we can use the LIMIT option in the query and dont need the while loop.
Also keep in mind that mysql_ functions are deprecated and should no longer be used. Try to switch to mysqli or PDO. But for now, i'll just use your code.
Adding just the ID to the $data array seems useless, but I guess you understand how to add the other columns from the SQL table.
function advert($id) {
if (!is_int($id))
return "possible SQL injection.";
$query = mysql_query("SELECT * FROM advertisement WHERE id = $id LIMIT 1");
$row = mysql_fetch_assoc($query);
$data = array(
'id' => $row['id']
);
return $data;
}
Not to call this method we can use the GET parameter like so. Please be advised that echoing an array will most likely not give you the desired result. I would store the result in a variable and then continue using it.
$ad = advert($_GET['id']);
if (!is_array($ad)) {
echo $ad; //for sql injection message
} else {
print_r($ad) //to show array content
}
Do you want to show the specific column value in the return result , like if you pass as as Id , you want to return only Id column data.
Loop through all the key of the row array and on matching with the incoming Column name you can get the value and break the loop.
Check this link : php & mysql - loop through columns of a single row and passing values into array
You are already passing ID as function argument. Also put space between * and FROM.
So use it as below.
$query = mysql_query("SELECT * FROM advertisement WHERE id = '".$data."'");
OR
function advert($id)
{
$query = mysql_query("SELECT * FROM advertisement WHERE id = '".$id."'");
$data = array();
while($row = mysql_fetch_assoc($query))
{
$data[] = $row;
}
return $data;
}
Do not use mysql_* as that is deprecated instead use PDO or MYSQLI_*
try this:
<?php
function advert($id){
$data= array();
//$id = $_GET['id'];
$query = mysql_query("SELECT *FROM advertisement WHERE id = $id");
while($row = mysql_fetch_assoc($query)){
array_push($data,$row['id']);
}
return $data;
}
var_dump($data);
//echo advert($data['id']);
?>
I'm using PHP ADOdb and I can get the result set:
$result = &$db->Execute($query);
How do I get the field names from that one row and loop through it?
(I'm using access database if that matters.)
It will depend on your fetch mode - if you setFetchMode to ADODB_FETCH_NUM (probably the default) each row contains a flat array of columns. If you setFetchMode to ADODB_FETCH_ASSOC you get an associative array where you can access each value by a key. The following is taken from ADODB documentation - http://phplens.com/lens/adodb/docs-adodb.htm#ex1
$db->SetFetchMode(ADODB_FETCH_NUM);
$rs1 = $db->Execute('select * from table');
$db->SetFetchMode(ADODB_FETCH_ASSOC);
$rs2 = $db->Execute('select * from table');
print_r($rs1->fields); # shows array([0]=>'v0',[1] =>'v1')
print_r($rs2->fields); # shows array(['col1']=>'v0',['col2'] =>'v1')
To loop through a set of results:
$result = &$db->Execute($query);
foreach ($result as $row) {
print_r($row);
}
Small improvement to the solution posted by #thetaiko.
If you are ONLY needing the field names, append LIMIT 1 to the end of your select statement (as shown below). This will tell the server to send you a single row with column names, rather than sending you the entire table.
SELECT * FROM table LIMIT 1;
I'm working with a table that contains 9.1M records, so this minor change speeds up the query significantly!
This is a function I use to return a field array - I've stripped out some extra stuff that, for example, allows it to work with other DBs than MySQL.
function getFieldNames($strTable, $cn) {
$aRet = array();
# Get Field Names:
$lngCountFields = 0;
$strSQL = "SELECT * FROM $strTable LIMIT 1;";
$rs = $cn->Execute($strSQL)
or die("Error in query: \n$strSQL\n" . $cn->ErrorMsg());
if (!$rs->EOF) {
for ($i = 0; $i < $rs->FieldCount(); $i++) {
$fld = $rs->FetchField($i);
$aRet[$lngCountFields] = $fld->name;
$lngCountFields++;
}
}
$rs->Close();
$rs = null;
return $aRet;
}
Edit: just to point out that, as I say, I've stripped out some extra stuff, and the EOF check is therefore no longer necessary in the above, reduced version.
I initally tried to use MetaColumnNames, but it gave differing results in VisualPHPUnit and actual site, while running from the same server, so eventually
I ended up doing something like this:
$sql = "select column_name, column_key, column_default, data_type, table_name, table_schema from information_schema.columns";
$sql .= ' where table_name="'.$table.'" and table_schema="'.$database_name.'"';
$result = $conn->Execute($sql);
while($row = $result->fetchRow()) {
$out[] = strToUpper($row['column_name']);
}
I think it should work with mysql, mssql and postgres.
The benefit of doing it like this, is that you can get the column names, even if a query from a table returns an empty set.
If you need the Coloumn names even for empty tables or for joins about multiple tables use this:
$db->Execute("SELECT .......");
// FieldTypesArray - Reads ColoumnInfo from Result, even for Joins
$colInfo = $res->FieldTypesArray();
$colNames = array();
foreach($colInfo as $info) $colNames[] = $info->name;
The OP is asking for a list of fieldnames that would result of executing an sql statement stored in $query.
Using $result->fetchRow(), even with fetch mode set to associative, will return nothing if no records match the criteria set by $query. The $result->fields array would also be empty and would give no information for getting the fieldnames list.
Actually, we don't know what's inside the $query statement. Besides, setting limit to 1 may not compatible with all database drivers supported by PHP ADOdb.
Answer by Radon8472 is the right one, but the correct code could be:
$result = $db->Execute($query);
// FieldTypesArray - an array of ADOFieldObject Objects
// read from $result, even for empty sets or when
// using * as field list.
$colInfo = [];
if (is_subclass_of($result, 'ADORecordSet')){
foreach ($result->FieldTypesArray() as $info) {
$colInfo[] = $info->name;
}
}
I have the habit of checking the class name of $result, for as PHP ADOdb will return false if execution fails.