UPDATE and Increment column value POD - php

I'm trying to sum/add another value to the actual value in the database but this is not working. Any suggestions?
$suplies=15;
$user_id="100234";
$sql = "UPDATE table SET suplies=suplies+".$suplies." WHERE user_id=?";
$q = $conn->prepare($sql);
$q->execute(array(':suplies'=>$suplies,':user_id'=>$user_id));


Just use the named placeholder all through out.
$sql = "UPDATE table SET suplies = suplies + :suplies WHERE user_id = :user_id";

Related

I am trying update multiple rows using values is this correct?

$query = "UPDATE INTO Sanctions SET (idNumber, lastName,firstName, section,sanction,expireDate) VALUES('$idNumber','$lastName', '$firstName','$section','$sanction', '$dueDate') WHERE id= '$id'";

Wrong
$query = "UPDATE INTO Sanctions
SET (idNumber, lastName,firstName, section,sanction,expireDate)
VALUES('$idNumber','$lastName', '$firstName','$section','$sanction', '$dueDate')
WHERE id= '$id'";
Correct way:
$query = "UPDATE Sanctions
SET idNumber = '{$idNumber}',
lastName = '{$lastName}', ....
WHERE id = '{$id}'";
The INTO command is not valid for UPDATE query. You need to assign the table equals to (=) values for every column you want to edit.
Notes:
These query are not well secured, please use prepared statement insted. :)

PHP MySQL Update Query not working with vars

$ID = trim($_GET["uid"]);
$Name = trim($_GET["name"]);
$result = $mysqli->query("UPDATE `Benutzer` SET `R_NAME`='$Name' WHERE `ID` = '$ID'");
The Result returns fine, but the Database is not updated. If I replace the vars with static values the Database IS updated.

Use mysqli prepare statement.
$stmt = $mysqli->prepare("UPDATE Benutzer SET R_NAME = ? WHERE ID = ?");
$stmt->bind_param($Name,$ID);
$stmt->execute();
$stmt->close();

Follow these steps:
Remove "trim" & use "mysql_escape_string".
Echo Check the values of Name & ID. Once you are getting them then follow up with the 3rd step.
Concatinate the sql string as shown by removing the tild operators:
$result = $mysqli->query("UPDATE Benutzer SET R_NAME ='".$Name."' WHERE ID = '".$ID."'");

What we pass in the query arguments is a string or we can say query in the form of string. you can change the query like below.
$result = $mysqli->query("UPDATE `Benutzer` SET `R_NAME`='".$Name."' WHERE `ID` = '".$ID."'");

SQL Multiple Statements

I am using php and mysql to update rows in my DB. I have 4 update statements in a row, yet only the last one works. I have confirmed that the statements work if they are used alone, but when I have them executed one after another only the last one executed works. I am receiving no error messages. Any help? Thanks!
$sql = "UPDATE comlog SET name='$name1', message='$message1' WHERE id=1";
$sql = "UPDATE comlog SET name='$name2', message='$message2' WHERE id=2";
$sql = "UPDATE comlog SET name='$name3', message='$message3' WHERE id=3";
$sql = "UPDATE comlog SET name='$name', message='$message' WHERE id=4";
In the above code, only the row with id 4 is being updated.

The answer is simple.
You are declaring the same variable for EACH sql string.
You need to declare it something like:
$sql1 = "";
$sql2 = "";
$sql3 = "";
$sql4 = "";

Updating SQL using PHP - Error

Right so i have php code to update a SQL table. If i replace $_GET['emailID'] with a number say 1 the database IS updated. But otherwise no update. What seems to be wrong here
Table: emails
Fields: mailbox, emailID
$query = 'UPDATE `emails` SET `mailbox`=\'trash\' WHERE `emailID`='.(int)$_GET['emailID'];

Do like this
$query = "UPDATE `emails` SET `mailbox`='trash' WHERE `emailID`=".intval($_GET['emailID']);

Can you try this,
$query = 'UPDATE `emails` SET `mailbox`=\'trash\' WHERE `emailID`="'.(int)$_GET['emailID'].'" ';

Value of attribut must be selected by single quotes. Try this:
$query = "UPDATE `emails` SET `mailbox` = 'trash' WHERE `emailID` = '" . intval($_GET['emailID']) . "'";

$query = "UPDATE `emails` SET `mailbox`='trash' WHERE `emailID`= ".$_GET['emailID'];
Try this one sure it will work

PHP SQL Views counter using PDO prepare()

I have a variable $id which gives me the id of the current article and this can help me to make an update query in my database on current article.
This is my code:
$vizualizari = $current_views+1;
$sql1= "UPDATE detalii_cantari SET viz = viz WHERE id = {$id};";
$q1 = $dbh->prepare($sql1);
$q1->execute(array(':viz'=>$vizualizari));
I don't get any errors but my code is still not working...

Your correct code is here:
$vizualizari = $current_views+1;
$sql1= "UPDATE detalii_cantari SET viz = :viz WHERE id = {$id}";
$q1 = $dbh->prepare($sql1);
$q1->execute(array(':viz'=>$vizualizari));
; from the end of sql is not needed here and viz = viz must become viz = :viz because of PDO.

It seems you have to get rid of the previous query and make it in a single statement
$sql = "UPDATE detalii_cantari SET viz = viz + 1 WHERE id = ?";
$stm = $dbh->prepare($sql);
$stm->execute(array($id));

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