I am having bad time getting SESSION to work in PHP.
I have a form the following action:
<form action="confirm.php" method="post">
And that has a button as such:
<button type="submit" id="submit">Proceed</button>
I have got session_start(); on all my pages. After the form button, I have this code:
<?php
if(!empty($_POST['submit']))
{
$_SESSION['name'] = $_POST['name'];
$_SESSION['address'] = $_POST['address'];
$_SESSION['strtnum'] = $_POST['strtnum'];
$_SESSION['height'] = $_POST['height'];
}
?>
On confirm.php I've got this:
<?php
print_r($_SESSION);
print_r($_POST);
?>
The POST array has correct values but the SESSION array is completely empty with no variables or values at all.
I would like help understanding how fix this.
Thank you.
EDIT: I'm quite sure that the code doesn't actually reach the inside of the if statement. I added an echo in there to print an alert (yes I used ) and it doesnt work. So I'm not 100% sure that it enters the if(!empty($_POST['submit']))
<form action="confirm.php" method="post">
^^^^^^^^^^^^^^^^^^^^
Your form is being submitted to confirm.php, thats where you should handle the $_POST and fill the $_SESSION values. Instead you are trying to do it in the same page that prints the form, but thats doing no good there because its not where the form data is being submitted to.
Related
Search page looks like this
<form method="post" action="response.php">
<input type="text" name="varianta" value="var_varianta">
<input type="submit">
</form>
<?php
session_start();
$var_varianta= $_POST['varianta'];
?>
The response page has the below line code:
$filters[] = array("filterType" => "resultLimit", "filterValue" => "varianta");
How i can i enter tn the "filterValue" => "**varianta**"); the $var_varianta that is inputed in the search field
Thanks
It's not clear what you're asking, but it seems like there's some confusion. $_POST contains the values that have been submitted, not the values that a user is entering. So, $_POST variables are set on the action page, not on the page showing the form. You can't set a $_POST variable in PHP on the page showing the form and expect the action page to know about that.
If I understand your question correctly, you should use $_POST['varianta'] on the action page to access whatever was submitted.
I have a form, which redirects the user to "page1.php" after the form is submitted. What I want to do is to redirect the user to "page2.php" after the form is submitted, but I need to make sure that the POST request was sent. Example:
<form action="page1.php" method="POST">
<input type="text" name="username" />
<input type="text" name="age" />
<input type="submit" value="" />
</form>
When the user clicks on Submit, it redirects him to page1.php. I want to redirect him to page2.php, but I need to make sure that the data is sent to the server. I can't use AJAX. Is there any way to do it with cURL or something like that? Any examples?
Thanks!
I guess this works !!
In page1.php
<?php
//do establish session
//and check for the input fields obtained via $_POST
if(isset($_POST['name_of_your_field']) && !empty($_POST['name_of_your_field'])){
if(!mail($to,$subject,$message)){
header('location:form.php?msg=error');
}else{
header('location:page2.php?msg=succes');
}
}
?>
You can check if the POST request was sent with something like:
if($_SERVER['REQUEST_METHOD'] == 'POST') {
// do something...
}
You can create a hidden input in your form and send additional info about the form that is submitted, e.g. action.
Inside you will do your magic and redirect user with:
header('Location: page2.php');
exit();
In your 'page1.php' processor, add a 'header' redirect to 'page2.php'.
header("Location: page2.php");
exit;
you could do a check if query is complete
example
<?php
$query=mysqli_query(".......your query statement")or trigger_error(mysqli_error());
if($query){
header("Location:page2.php");
}
else{
die('error');
}
?>
In your situation, you can just simple check for the posted data. Like
$username = $_POST['username'];
$age = $_POST['age'];
if($username&&$age){ /* This is to check if the variables are not empty */
// redirect to page2
}
It is logical that if those are not empty, meaning they are posted. Even if they are empty, as long as you get there, that means it was posted. There is no need to check if posted or not, what needs to be checked was, if posted data was there.
I hope I made it clear. ^_^ but making sure is not bad at all. Happy coding friend.
I've been trying to do form validation without using the url. So I thought that I would create a hidden field in my form and send it over to my validation php script. What I was hoping I would be able to do is set what ever errors there are in the form to this hidden field and return it. However once I get out of the scope it destroys whatever I set. I thought $_POST had global scope? Maybe I declared I set the hidden field wrong? I have placed the code below.
<?php
include_once $_SERVER['DOCUMENT_ROOT'].'/poles/config/databaseConnect.php';
include_once $_SERVER['DOCUMENT_ROOT'].'/poles/config/functions.php';
include_once $_SERVER['DOCUMENT_ROOT'].'/poles/models/users.php';
include_once $_SERVER['DOCUMENT_ROOT'].'/poles/models/userDetails.php';
//get the refering url to be used to redirect
$refUrl = $_SERVER['HTTP_REFERER'];
if(isset($_POST['register'])){
//declare a temp error array
$tempError;
//check if the form is empty
if(empty($_POST['Email'])&&empty($_POST['Email Confirmation'])&&empty($_POST['Password'])&&empty($_POST['Password Confirmation'])
&&empty($_POST['Stage Name'])&&empty($_POST['Main Club'])){
$tempError = 'Please fill in the form.';
}else{
//set variables
}
if(!empty($tempError)){
//start a session to declare session errors
$_POST['errors'] = $tempError;
//redirect back to referring url
header('Location:'.$refUrl);
exit();
}else{
//log user in and redirect to member home page
}
}
Basic form (I excluded the input field as it would be really long)
<div class="col-md-6 well">
<span class="jsError"></span><?php if(isset($_POST['errors'])){ $errors = $_POST['errors']; } if(!empty($errors)){ echo '<p class="alert alert-danger text-center">'.$errors.'</p>'; } ?>
<form class="form-horizontal" role="form" method="post" action="controllers/registrationController.php" id="registration">
<input type="hidden" name="errors" value="<?php if(isset($_POST['errors'])){echo $_POST['errors']; } ?>">
</form>
I looked into using the $_SESSION variable method too but the stuff I found was either a bit complicated or it involved me starting a whole bunch of sessions everywhere (would make my code messy in my opinion).
$_POST is populated from the contents of the data passed by the browser to the server. When you send a Location header it causes the browser to load a new page, but since it will have no form data, nothing will be passed.
If you need to pass data from page to page then $_SESSION is the way to go. All that is required is a session_start() at the top of the pages that need access, and you can store your $_POST data like this:
$_SESSION['postdata'] = $_POST;
Retrieving it becomes
$email = $_SESSION['post']['Email'];
The alternative is to echo the data as a hidden <input> in a new form, but that will require a new form to be submitted and I get the feeling you want something seamless.
Note also that $_SERVER['HTTP_REFERER'] is not guaranteed to be accurate, or even present. You shouldn't rely on this for production code. It might work for you with your browser in your test set-up, but that's no guarantee it'll work for other browsers. Find another way.
You can achieve this by using javascript instead of a redirect, but the only way to pass data through a redirect is via the URL, the session, or cookies.
$_POST['errors'] = $tempError;
//redirect back to referring url
?>
<html><head><title></title></head><body>
<form id="temp_form">
<?php
foreach($_POST as $k=>$v) {
?><input type="hidden" name="<?php echo htmlentities($k); ?>" value="<?php echo htmlentities($v); ?>" /><?php
}
?>
</form>
<script type="text/javascript">
setTimeout(function() { document.getElementById('temp_form').submit(); },100);
</script>
</body>
</html>
<?php
die();
I have faced a problem in all of my php projects is that since i used OOP is that if there is a user submitting a form
when it goes to processing it and if it has an error i save a message in the session and redirect them to the same page
this is a sample and of course when it redirects it wipes all the fields that was there
like let's say i have a register form that had
<?php if(!empty($message)) { echo $message } ?>
<form action ="forms/register.php">
first name: <input type="text" name="first_name" />
username:<input type="text" name="username" />
<input type="submit" value = "submit" />
</form>
and this is what the code in forms/register.php
if(isset($_POST['submit'])) {
$first_name = $_POST['first_name'];
$username = $_POST['username'];
if(empty($first_name) || empty($username) {
$session -> message("please fill in all the fields");
redirect("../register.php");
} else {
// do something else like insert query
}
}
my problem is if first_name or user_name is empty and it redirects to register.php
and it echos the error message no problem in that
but the fields are empty the first_name and the user_name are empty
so the user has to fill it all again
so one of my friends suggested to save it in the session or something
so i would like to know if that is possible then how and what i mean by how so nobody would get it wrong, i mean the way not the code to just copy it and paste it
Thanks in advance
and sorry for being long and annoying
You can store whatever values you want to keep persisted in the form after the page redirects in session variables, then retrieve those values on the form page and echo them in the value attribute of the form elements.
session_start(); $_SESSION['nick'] = $_GET['nick'];
more / better examples:
http://php.net/manual/en/function.session-start.php
Not sure what issue you exactly are facing (also what $session is inside your workflow?).
However, i recommend using PHP inbuild session support.
http://php.net/manual/en/features.sessions.php
From the above link itself:
<?php
session_start();
if(isset($_SESSION['views']))
{
$_SESSION['views']=$_SESSION['views']+1;
}
else
{
$_SESSION['views']=1;
echo "Views=". $_SESSION['views'];
}
?>
Above code simply keeps track of page views. $_SESSION variable persists between page loads and you should be using the same for all your session requirements.
I'm trying to write my first PHP script (hopefully). I want to send user input from a form inside an HTML page to a PHP script and validate them inside script. then, if there is any problem with input data, return to first page and highlight wrong fields. else go to another page (something like successful).
How do i send feedback from second script to first page without using forms?
In short, you'd have something like this:
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
$errors = array();
$name = $_POST['name'];
if ($name !== 'Fred') {
$errors[] = 'Please enter "Fred"';
}
... validate more fields ...
if (count($errors) == 0) {
... form is ok ...
header('Location: everything_is_ok.php');
exit();
}
}
?>
<form action="<?php echo $_SERVER['SCRIPT_NAME'] ?>" method="POST">
Enter 'Fred': <input type="text" name="name" value="<?php echo htmlspecialchars($name) ?>" /><br />
<input type="submit" />
</form>
Basically: Have the form page submit back to itself. If everything's ok, redirect the user to another page. Otherwise redisplay the form.
Just make your Form POST to itself, then in your PHP check the values and if they are valid, don't display your form and do your submit code. If they are invalid, display the form with the values and errors displaying.
Reload the first page and send the feedback in the session, for example. If session['errors'] exist, echo them. Note you'll have to include some php tags in your html page anyway.
Use a session... here's a link to help you get started: http://www.tizag.com/phpT/phpsessions.php