I am echoing a MySQL table to HTML table, but some of my database fields are empty. When a database field is empty, how can I specify an alternate text (rather than it just showing blank?
The following works perfect (with blank cells):
<?php
include("../config.php");
$link = mysqli_connect("$db_host" , "$db_user" , "$db_password" , "$db");
mysqli_select_db($link, $db);
$result = mysqli_query($link,"SELECT * FROM the_table");
echo "<table border='1'>
<tr>
<th>Name</th>
<th>Email</th>
<th>Phone</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['phone'] . "</td>";
echo "</tr>";
}
echo "</table>";
?>
I think the answer should look something like this (but it doesn't work):
if (empty($row['name'])) {
echo "<td>Not Specified</td>";
} else {
echo "<td>" . $row['name'] . "</td>";
}
Suggestions?
I think this should work:
if ($row['name'] == null) {
echo "<td>Not Specified</td>";
} else {
echo "<td>" . $row['name'] . "</td>";
}
Try:
if(empty($row['name']) || $row['name'] == "")
See http://php.net/manual/en/function.empty.php for the empty documentation. Maybe your result contains spaces? Then use the trim function as commented on your question.
Related
I am using this code to get that data from SQL Server database using PHP
<?php
foreach ($dbDB->query($query) as $row) {
echo "<tr>";
echo "<td>" . $row['Country'] . "</td>";
echo "<td>" . $row['OrderNumber'] . "</td>";
echo "<td>" . $row['Region'] . "</td>";
echo "<td>" . $row['ShipDate'] . "</td>";
echo "<td>" . $row['ProducedDate'] . "</td>";
echo "</tr>"; }
?>
I am trying to replace these multiple lines but storing the columns' names in a string for example $_POST['SelectedColumns'].
The values coming into post as comma separated string, For example : Country,OrderNumber,Region,ShipDate,ProducedDate
I have tried this solution but still not working for me.
<?php
$ser="********";
$db="******";
$user="******";
$pass="******";
$query = 'SELECT '.$_POST['SelectedColumns'].' FROM reporting.REPORT_ALL';
$dbDB = new PDO("odbc:Driver=ODBC Driver 13 for SQL Server;Server=*******;Database=******;Port=1456", $user, $pass);
$row = $_POST["SelectedColumns"];
$rows = explode(",",$row);
/*Here I have the another html code independent of this part */
foreach ($dbDB->query($query) as $dataRow) {
echo "<table>";
echo "<tr>";
foreach ($rows as $r ) {
echo "<td>" . $dataRow[$r] . "</td>"; }
echo "</tr>";
echo "</table>"; }
?>
Any suggestions please ?
I wanted to fetch the data from the database and wants to store into an array and after storing the data into the array i want to access particular index of the array.
I'm a java developer need to do this in php (which I don't know much).
Basically there are 250 strings in a table i wanted to fetch those 250 strings into and array and wants to access some particular row.
for example :
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
**$uname100 = $row[100]; // this is not getting assigned to $uname100 variable**
**echo $row[100]; // here this is not printing**
**echo $uname100; // not even this printing**
mysqli_close($con);
?>
Please check the bold part in the code and help me out. I'm new to php so please dont panic over this.
And also wanted to do something like this :
$ctr=0;
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
$uname[$ctr++] = $row['FirstName']; // AND USING THIS OUTSIDE LOOP
}
echo $uname[90];
Use array construction
$counter=0;
$data = array();
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
$data[] = $row['FirstName'];
$counter++;
}
print_r($data);
First solution
$counter=0;
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
$counter++;
$varName='uname'.$counter;
$$varName=$row['FirstName'];
}
echo echo $uname100;
You cannot access the variable $row[100] outside the while loop.
Also $row will not contain an index 100.
It will be containing only $row['FirstName'] or $row['LastName'] inside the while loop
Answer for second part:
$uname = array();
$ctr=0;
while($row = mysqli_fetch_array($result)) {
....
....
$uname[$ctr++] = $row['FirstName']; // AND USING THIS OUTSIDE LOOP
}
if(isset($uname[90])) echo $uname[90];
<html>
<head>
<meta http-equiv = "content-type" content = "text/html; charset = utf-8" />
<title>Using file functions PHP</title>
</head>
<body>
<h1>Web Development - Lab05</h1>
<?php
require_once("settings.php");
$dbconnect = #mysqli_connect($host, $user, $pswd, $dbnm);
if($dbconnect->connect_errno >0)
{
die('Unable to connecto to database [' . $db->connect_error . ']');
}
$queryResult = "SELECT car_id, make, model, price FROM cars";
echo "<table width='100%' border='1'>";
echo "<tr><th>ID</th><th>Make</th><th>Model</th><th>Price</th></tr>";
//initiate array
$displayrow= mysqli_fetch_array($queryResult);
//initiate while loop to iterate through table
while($displayrow)
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['Make'] . "</td>";
echo "<td>" . $row['Model'] . "</td>";
echo "<td>" . $row['Price'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($dbconnect);
?>
</body>
</html>
This is doing my head in, I cannot figure out why it will not display the actual data apart from the Table header. No matter what I used.
I have tried mysqli_fetch_array, mysqli_fetch_row, mysqli_fetch_assoc but nothing works.
Help and explanation why it was not displaying the data would be much appreciated :)
First: You aren't running a query, you are only putting the query text in a variable. You need to use mysqli_query.
Second: You should add mysqli_fetch_array to the loop.
For example:
while($displayrow = mysqli_fetch_array($queryResult))
{
}
Otherwise you are only getting the first row.
Third: Array keys are case sensitive. There is no $row['ID'], as Jeribo pointed out, it is $row['car_id'] as referenced in your query. $row['Make'] is not the same as $row['make'].
Please Precision to names of field in Query ( car_id,make,...)
while($displayrow= mysql_fetch_assoc($queryResult) )
{
echo "<tr>";
echo "<td>" . $displayrow['car_id'] . "</td>";
echo "<td>" . $displayrow['make'] . "</td>";
echo "<td>" . $displayrow['model'] . "</td>";
echo "<td>" . $displayrow['price'] . "</td>";
echo "</tr>";
}
If you want to query outside you still have to set it in the loop:
$result = $db->query($queryResult)
while($row = $result ->fetch_assoc()){
...
}
a Good Tutorial is shown here: http://codular.com/php-mysqli
$row needs to be initialized so why don't you try:
while($row = mysqli_fetch_array($queryResult))
{
....
}
You have to get the result set first and then try fetching array from result set
<?php
require_once("settings.php");
$dbconnect = #mysqli_connect($host, $user, $pswd, $dbnm);
if($dbconnect->connect_errno >0)
{
die('Unable to connecto to database [' . $db->connect_error . ']');
}
$query = "SELECT car_id, make, model, price FROM cars";
$resultSet=mysqli_query($dbconnect,$query)
echo "<table width='100%' border='1'>";
echo "<tr><th>ID</th><th>Make</th><th>Model</th><th>Price</th></tr>";
//initiate array
$displayrow= mysqli_fetch_array( $resultSet);
//initiate while loop to iterate through table
while($displayrow)
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['Make'] . "</td>";
echo "<td>" . $row['Model'] . "</td>";
echo "<td>" . $row['Price'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($dbconnect);
?>
http://www.w3schools.com/php/func_mysqli_fetch_array.asp
I have no idea how to explain myself which is why the question isn't even a question. I need to have a table dynamically created from data on mysql (which I've done) but I need to be able to have input in the cells under some of the headings (responsibility, organization, independent work...) When this data is submitted, I need it to be student specific. In other words, when I pull up Johnny Rotten's data, I need to be able to see all the comments under those headings that were submitted (yes this is for teaching). The number of students can vary which is why i need the whole thing to be dynamic. If this is not possible, please let me know. AND if you haven't figured it out already, I am brand new and self-taught!
Here's what I have...
<?php
include 'connect.php';
if ($db_found) {
$SQL = "SELECT * FROM studentlist WHERE teacher1='smith' OR teacher2 ='smith' OR
teacher3='smith' ORDER by homeroom";
$result = mysql_query($SQL);
echo "<table border='1'>
<tr>
<th>Student</th>
<th>Homeroom</th>
<th>Responsibility</th>
<th>Organization</th>
<th>Independent Work</th>
<th>Collaboration</th>
<th>Initiative</th>
<th>Self Regulation</th>
</tr>";
while ($row = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['student'] . "</td>";
echo "<td>" . $row['homeroom'] . "</td>";
echo "<td>" . "" . "</td>";
echo "<td>" . "" . "</td>";
echo "<td>" . "" . "</td>";
echo "<td>" . "" . "</td>";
echo "<td>" . "" . "</td>";
echo "<td>" . "" . "</td>";
echo "</tr>";
}
echo "</table>";
}
mysql_close($connect);
?>
i am passing images file names via textarea to php script to find information about each image in mysql db .The problem is i am trying to output those image file names that not found in mysql db and inform the user which image file names not found in mysql. my current code fails to output those missing records in db but it correctly outputs information about those images found in db. could any one tell me what i am doing wrong ?
foreach ($lines as $line) {
$line = rtrim($line);
$result = mysqli_query($con,"SELECT ID,name,imgUrl,imgPURL FROM testdb WHERE imgUrl like '%$line'");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
//echo $result;
if($result == 0)
{
// image not found, do stuff..
echo "Not Found Image:".$line;
}
while($row = mysqli_fetch_array($result))
{
$totalRows++;
echo "<tr>";
echo "<td>" . $row['ID'] ."(".$totalRows. ")</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['imgPURL'] . "</td>";
echo "<td>" . $row['imgUrl'] . "</td>"; echo "</tr>";
}
};
echo "</table>";
echo "<br>totalRows:".$totalRows;
You can use mysqli_num_rows() in mysqli
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result))
{
$totalRows++;
echo "<tr>";
echo "<td>" . $row['ID'] ."(".$totalRows. ")</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['imgPURL'] . "</td>";
echo "<td>" . $row['imgUrl'] . "</td>";
echo "</tr>";
}
} else {
echo "<tr><td colspan='4'>Not Found Image:".$line.'</td></tr>';
}
You want to use mysqli_num_rows
if(mysqli_num_rows($result)) {
// Do your while loop here
}
Use mysqli_num_rows to compare the number of rows in the result set.