How do I get proper data while saving to mysql database? - php

Question

I have a form made that appears to be connected to a mysql database. When I enter information into the form and submit it, it registers in the database as "0000-00-00" and the data is returned as "0000-00-00". None of the actual data is showing up. Any Ideas?
connection.php:
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = 'root';
$db = 'sm_residents';
$conn = mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db($db);
?>
Create.php:
<?php
include ('connection.php');
$FirstName= $_POST['inputFirstName'];
$LastName= $_POST['inputLastName'];
$Address= $_POST['inputAddress'];
$Birthday= $_POST['inputBirthday'];
$FormerResidence= $_POST['inputFormerResidence'];
$Career= $_POST['inputCareer'];
$Education= $_POST['inputEducation'];
$SpecialInterests= $_POST['inputSpecialInterests'];
if ($_FILES["file"]["error"] > 0) {
} else {
if (file_exists("upload/" . $_FILES["file"]["name"])) {
} else {
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
}
}
Picture= $_FILES["file"]["name"];
mysql_query("INSERT INTO residents (`ID`,`FirstName`,`LastName`,`Address`,`Birthday`,`FormerResidence`,`Career`,`Education`,`SpecialInterests`,`Picture`)
VALUES(NULL,'$FirstName','$LastName','$Address','$Birthday','$FormerResidence','$Career','$Education','$SpecialInterests','$Picture')") or die(mysql_error());
?>
<script> window.location = "index.php"; </script>
Index.php:
<?php
include ('connection.php');
if(isset($_POST['submit'])) {
echo "Please Fill Out The Form";
//header ('Location: create.php');
} else {
//echo "User Has Been Added";
//header('Location: create.php');
}
?>
<h1>Add A Resident</h1>
<form action="create.php" method="post" enctype="multipart/form-data">
<div class="form-group">
<label for="inputFirstName">First Name</label>
<input type="text" class="form-control" id="inputFirstName" placeholder="First Name">
</div>
<div class="form-group">
<label for="inputLastName">Last Name</label>
<input type="text" class="form-control" id="inputLastName" placeholder="Last Name">
</div>
<div class="form-group">
<label for="inputAddress">Address</label>
<input type="text" class="form-control" id="inputAddress" placeholder="Address">
</div>
<div class="form-group">
<label for="inputBirthday">Birthday</label>
<input type="date" class="form-control" id="inputBirthday">
</div>
<div class="form-group">
<label for="inputFormerResidence">Former Residence</label>
<input type="text" class="form-control" id="inputFormerResidence" placeholder="Former Residence">
</div>
<div class="form-group">
<label for="inputCareer">Career</label>
<input type="text" class="form-control" id="inputCareer" placeholder="Career">
</div>
<div class="form-group">
<label for="inputEducation">Education</label>
<input type="text" class="form-control" id="inputEducation" placeholder="Education">
</div>
<div class="form-group">
<label for="inputSpecialInterests">Special Interests</label>
<input type="text" class="form-control" id="inputSpecialInterests" placeholder="Special Interests">
</div>
<div class="form-group">
<label for="inputFile">File input</label>
<input type="file" id="inputFile">
</div>
<button type="submit" class="btn btn-default">Submit</button>
</form>

Answer 1

I'll make this an answer: (or a BIG 90% / 95% partial at best)
None of the actual data is showing up
There aren't even any named elements for the inputs, so nothing is going to go through, they're all IDs.
<input type="text" class="form-control" id="inputFirstName" placeholder="First Name">
which should read as
<input type="text" name="inputFirstName" class="form-control" id="inputFirstName" placeholder="First Name">
^^^^^^^^^^^^^^^^^^^^^
then do the same for the others by "naming" them as I did above.
PHP is looking for named elements, not IDs which cannot be relied upon.
This also doesn't have a name <input type="file" id="inputFile">
change to: <input type="file" name="file" id="inputFile">
as per $_FILES["file"]
Use error reporting
while placing the following underneath your opening <?php tag:
error_reporting(E_ALL);
ini_set('display_errors', 1);
which will throw many Undefined index warnings with your present code.
Also as pointed out by Barmar in his comment, you're missing a $ for Picture= $_FILES["file"]["name"]; unless that was a typo, it should read as:
$Picture= $_FILES["file"]["name"];
In regards to it registers in the database as "0000-00-00" make sure your column is of the correct type to accomodate a DATE.

Answer 2

Try formatting first your Birthdate:
$Birthday = date("Y-m-d", strtotime($_POST['inputBirthday']));