How to do this more efficiently - php

Currently I'm using this code:
<?php
/*
Clean, Simple, Minimal.
*/
$pages = array('home', 'login', 'register', 'logout', 'test');
if (isset($_GET['p']))
{
$page = $_GET['p'];
if (in_array($page, $pages))
{
include('pages/' . $page . '.php');
}
}
else {
echo 'Hi';
}
?>
I want this to be as secure and efficent as possible, I've seen multiple versions of this. I wasn't sure how to do what i really wanted, i wanted it so, if the requested file .php exists in /pages/ it'll show it, else throw error. But last time i did that i was vulnerable to LFI.

Related

How to place include in other place

I make some function in php, but I am getting stuck
if (isset($_GET['page']) )
{
$open = __DIR__.'/../view/html/'.$_GET['page'].'.php';
if (file_exists($open)){
include $open; //<<<<can i//
}
else {
"echo "The file not found";
}
}
If true, I want to include that file in another place, but how?
I am trying to put the code in where I want, but the __DIR__ is not working as I expected. I don't know how to fix it to become right. Solution cannot be found in the tutorial.
I would use:
if( isset( $_GET['page'] ) ) {
switch( strtolower( $_GET['page') ) ) {
case 'download':
include '../download.php';
break;
case 'blog':
include '../blog.php';
break;
// ... And so on
default:
echo 'File not found';
}
} else {
echo 'No file specified';
}
This way you have full control over which files can be included!
You have to do like this.
Use file_get_contents()
if (file_exists($open)){
file_get_contents($open);
}
The answer to your question is yes, that will work. Whether or not you should use readfile(), file_get_contents() or include depends on the contents of the file. If you have php code in that file, you need either include or require. But this actually brings up another problem.
As mentioned in the comments by #anonymous, you are exposing yourself to an LFI attack. To resolve this, pages should be defined as a whitelisted array. You should then check if the page is in the whitelisted array. If it is not, do not attempt to open that file.
$pages = array(
'page1',
'page2'
);
Then you can make a reference and check if it exists.
if(in_array($_GET['page'], $pages)){
//now check for the file
$open = __DIR__.'/../view/html/'.$_GET['page'].'.php';
if(file_exists($open)){
include $open;
}
} else {
//page does not exist, redirect them elsewhere.
header('Location: http://example.com/404.php');
}

Creating links to embed page

I have created an index.php that serves as a template with a content box. I also have home.php, about.php, and contact.php which only contain the content to fill that content box. This is the code I use to embed pages into that content box:
<?php
if(!$_GET[page]){
include "home.php"; // Page to goto if nothing picked
} else {
include $_GET[page]."php"; // test.php?page=links would read links.php
}
?>
The home page works fine but I am not sure what code to use in the main menu to link to the other pages. I am having a very hard time getting an answer, so I think I may be searching with the wrong terms, which is why I am asking here.
On the main menu for the website, what code do I use in the links so that they get home.php, about.php, or contact.php?
I made the following test:
$page = "test.php?page=links";
$link = explode("=", $page);
echo $link[1].".php"; //gets links.php
So, your code should looks like:
<?php
if(isset($_GET[page])){
$page = $_GET[page];
$link = explode("=", $page);
include $link[1].".php"; // test.php?page=links would read links.php
} else {
include "home.php"; // Page to goto if nothing picked
}
?>
Saludos.
if(!$_GET[page]){
include "home.php"; // Page to goto if nothing picked
} else {
include $_GET[page].".php"; // test.php?page=links would read links.php
}
It was just missing the '.' before the 'php'.
You should use Quotes for arrays though to avoid a Notice (Undefined constant)
Be careful though, you should verify that $_GET['page'] only contains sites you want to make accessible. Otherwise an attacker could just read any file on your server.
if(array_key_exists('page', $_GET)) {
$page = preg_replace('~[^a-z]~', '', $_GET['page']);
include __DIR__ . '/' . $page . '.php';
} else {
include __DIR__ . '/home.php';
}
Better solution (but you have to manually add all the pages):
$page = (array_key_exists('page', $_GET) ? $_GET['page'] : 'home');
switch($page) {
case 'about':
case 'links':
case 'whatever':
include __DIR__ . '/' . $page . '.php';
break;
default:
include __DIR__ . '/home.php';
break;
}
About
?<key>=<value> in the url.
You look up a value in the $_GET-array by using the key.

Detect and display current page as marked link

until today I've been using following function
function menu_active($pagename)
{
$active = basename($_SERVER['PHP_SELF'], ".php");
if ($active === $pagename) echo "id='active' ";
}
And in HTML
<?php menu_active('page_name'); ?>
to detect which page is active to mark it as current page, but when I changed my page display method it doesn't work anymore. So I wonder how to change the function to make it work. I've tried to declare $pagename as filename.inc.php in the script below, but no use.
I'm using this script to display pages
$pages_dir = 'pages';
if (!empty($_GET['p']))
{
$pages = scandir($pages_dir, 0);
unset($pages[0], $pages[1]);
$p = $_GET['p'];
if (in_array($p . '.inc.php', $pages))
{
include ($pages_dir . '/' . $p . '.inc.php');
}
else
{
echo 'Error';
}
}
else
{
include ($pages_dir . '/home.inc.php');
}
I appreciate any help, feedback or logic and ideas of how to do this right.
Instead of checking which script is running, check $_SERVER['REQUEST_URI']. This will give you the relative URL as requested by the client.

Secure Include php

Is this secure including? Or is it possible to use some RFI/LFI or what's it called?
$request_uri = explode('/', $_SERVER['REQUEST_URI']);
$script_name = explode('/', $_SERVER['SCRIPT_NAME']);
for ($i = 0; $i < sizeof($script_name); $i++) {
if ($request_uri[$i] == $script_name[$i])
{
unset($request_uri[$i]);
}
}
$command = array_values($request_uri);
if (file_exists('controllers/' . $command[0] . '.php')) {
include 'controllers/' . $command[0] . '.php';
}
update:
if (isset($_GET['p'])) {
$pages = array('home', 'login', 'register');
$page = filter_var($_GET['p'], FILTER_SANITIZE_URL);
if (in_array($page, $pages) && file_exists($page . '.php')) {
include ($page . '.php');
} else {
include ('404.php');
}
}
else {
include ('home.php');
}
Well, if you make sure that $command[0] only contains alphanumeric characters (and possibly underscores and hyphens), that could be made somewhat secure.
Something like the following might do the job:
if (!ctype_alnum($command[0])) {
// Hacking attempt!
exit;
}
But it's still a bad idea to include files based on user input. A better idea would be to use a lookup table that maps URIs to controllers, and use autoload to include the relevant files. That way, there's a strong separation between user input and the include.
Your code feeds any arbitrary string provided by the user to PHP's include; this is bad and pretty much a textbook example of https://www.owasp.org/index.php/Server-Side_Includes_(SSI)_Injection
What problem are you trying to solve that requires this?

dynamic include methods

Among the following include methods which is the best to practice and why?
$page = $_GET['page'];
Method 1
$pages = array('home', 'blog', 'about');
if( in_array($page, $pages) )
{
include($page.'.php');
{
else
{
die('Nice Try.');
}
Method 2
if($page = 'home'){
include('home.php');
}else if($page = 'blog'){
include('blog.php');
}else if($page = 'about'){
include('about.php');
}
Method 3
if(str_replace("http://", "gth://", $page) == $page){
include_once $page;
}else{
die('Nice Try.');
}
or any other solutions? I dont prefer method 1 and 2 as it always needs to be updated everytime i add a new page.
extending/maintaining the first way is easiest, second way is worse. third way is no way to go, as it relies on user input to require pages... it is going to be a security hole
I believe that the first one is the best of the lot. You can try the second one, but it's for the freshers. And the third one is a BIG NO, because any fresher hacker could hack your "if" condition, & more loopholes will start creeping in.
As for your problem, on adding a new page to the array, every time a new page is created, for the first method, I have one solution:-
Let's say you're putting all the new pages in one folder "abc". Now just write one file code as the following, to read all the files / pages existing in that folder:-
<?php
$page = $_GET['page'];
$pages = array();
/**
* If you are using all the pages existing in the current folder you are in,
* then use the below variable as:-
* $path = ".";
*/
$path = 'abc/'; // Change the Path here, related to this Folder name
$handle = opendir($path);
while (($file = readdir($handle)) !== false) {
$pages[] = $file;
}
closedir($handle);
if( in_array($page, $pages) ) {
include($page.'.php');
}
else {
die('Nice Try.');
}
?>
So you see that the array is getting filled up dynamically, without the need to mention all the pages you create every time. And you are using the first method only. And keep the including pages in one separate folder, which you will need to include every time, in other main pages.
Hope it helps.

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