This question already has answers here:
PHP Dynamic Variable Name
(2 answers)
Closed 8 years ago.
I have a for script:
<?php for($i=1; $i<10; $i++):?>
<?php if($this->item->nuotrauka{$i}):?>
<div class="vobsmall">
<img src="<?php echo $this->item->nuotrauka{$i}; ?>"/>
<?php echo $this->item->nuotrauka{$i}; ?>
</div>
<?php endif; ?>
<?php endfor; ?>
There's 9 variables like $this->item->nuotrauka1, $this->item->nuotrauka2 etc.
As you can see here I'm trying to call these variables using {i} as number of object variable. Hovewer the code above returns single char from variable and not full variable as I want. How should I write {i} here to get what I want ?
Try this:
echo $this->item->{"nuotrauka".$i};
Related
This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Reference Guide: What does this symbol mean in PHP? (PHP Syntax)
(24 answers)
Closed 2 years ago.
Inside the body of an html document I have something like this:
<?=str_replace(' ', '_', $result[0]['something'])?>
This works perfectly fine. In the same document I have this:
<?php if(!empty($result[0]['something'])) { echo "Hello"; } else { echo " "; }?>
Which also works fine, but it slightly bothers me that I am using <?= in one place and <?php in another. When I try to change the if code to become:
<?=if(!empty($result[0]['something'])) { echo "Hello"; } else { echo " "; }?>
or
<?= if(!empty($result[0]['something'])) { echo "Hello"; } else { echo " "; }?>
Both result in a Parse error: syntax error, unexpected 'if' (T_IF) in....
I've attempted to find some documentation on the respective differences between <?php and <?= as a php opening tag but all I get is data on short tags - which this is not. Can someone explain this behavior for me?
<?= is like <?php echo. You can't echo an if statement.
This question already has answers here:
What is the difference between client-side and server-side programming?
(3 answers)
Closed 4 years ago.
I am trying to add if statemenet into $html variable. But it see php as a html tag. how can add this statement. Thanks
$html = '
<?php if (x=y):?>
<div>
Help me )
</div>
<?php endif ?>
';
Try following
$html = '';
if(x==y):
$html .= '<div> Help me )</div>';
endif;
You can do without closing php tags.
Edited
After #MichałSkrzypek comment I have edited and fix mistake in if statement
What you are trying to do is impossible. If you would want to echo the var, you would put <?php inside of <?php, which must result in an error. Only add
<div>
Help me )
</div>
to a var.
This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 5 years ago.
for my issue i'll try to be as brief as possible
what am trying to do is reference a page with a specific id in the HTML anchor link with PHP as the below
<body>
<?php $linkName = "Second Page"; ?>
<?php $id = 5; ?>
<?php echo $linkName?><br>
and it works fine
now what am trying to do is to make the $id part more dynamic by making looping the number from 1 to 10 and also providing 10 links
the code is
</head>
<body>
<?php $linkName = "Second Page"; ?>
<?php $id = 5; ?>
<?php
for ($i=0; $i < 10 ; $i++) {
echo "<a href='secondPage.php?id=<?php echo $i;?'>Link1</a>";
};
?>
</body>
however what i did notice as the below images indicates when i hover on the links i noticed that i refer to a strange link
and when i cliched on it it takes me to the following link with an id that i did not want as below
http://localhost/PHP_Course/secondPage.php?id=%3C?php%20echo%201;?
i tried researching the subject and i tried escaping the quotation but it does not seem to resolve the problem
Any help please ??
<?php and ?> tags indicate to the PHP preprocessor that anything inside them is code and needs to be parsed, everything outside is just text PHP doesn't touch.
Inside the <?php tag, "<?php" string has no special meaning, so is printed. You do not need to open and close tags all the time, try this:
</head>
<body>
<?php
$linkName = "Second Page";
$id = 5;
for ($i = 0; $i < 10 ; $i++) {
echo "<a href='secondPage.php?id=$i;'>Link1</a>";
};
?>
</body>
You're echoing a string in PHP, and using <?php... inside that string.
Solution:
echo "<a href='secondPage.php?id=" . $i . "'>Link1</a>";
id=$i will also work, because you can include variables directly in double-quoted strings.
You're echoing the PHP code itself as a string. You don't need to put PHP code inside of PHP code. Just concatenate the values you want to echo:
echo 'Link1';
because you already started an echo statement so you don't need to add another PHP starting and ending tags. just check my code below and try it.
<?php
for ($i=0; $i < 10 ; $i++) {
echo "<a href='secondPage.php?id=".$i."'>Link1</a>";
} ;
?>
This question already has answers here:
How can I combine two strings together in PHP?
(19 answers)
Closed 7 years ago.
Hi I am trying to produce a <td> which also contains an <a> link which will redirect to a function in my controller which also echos the id of my data. Here is my code so far:
<?php
if ($this->session->userdata("username")==$info->U_username) {
echo '<td>EDIT</td>';
}
?>
This code produces an error Disallowed Key characters. Any help or comment is highly appreciated.
For concatenating strings PHP has . operator.
echo '<td>EDIT</td>';
You need to add the result of base_url() to the string you want to output, e.g.:
echo '<td>EDIT</td>';
Either you need to concatinate instead to use php multiple time .use like this
<?php
if ($this->session->userdata("username")==$info->U_username){
echo "<td><a href='".base_url()."'/gamestalker/edit_content/'".$info->C_id."'>EDIT</a></td>";
}
?>
or don't include html into php tags like this
<?php
if ($this->session->userdata("username")==$info->U_username){ ?
<td>EDIT</td>
<? }
?>
You need string concatenation. In PHP you use . for that.
Also codeigniter's base_url can take an argument:
<?php
if ($this->session->userdata("username")==$info->U_username){
echo '<td>EDIT</td>';
}
?>
This question already has answers here:
What is the "?" symbol in URL used for in php?
(7 answers)
Closed 9 years ago.
Sorry if this is a stupid question but I want to include two variables in an href
the href is not in a form
<div class="button">
View
</div>
int he page I am sending it to i have a Get method
if (isset($_GET['Name']) && isset($_GET['pid'])) {
$id2 = $_GET['Name'];
$id = $_GET['pid'];
Summary
I want to include $id in the a href so i will be able to get both name and id in the page product.php
You can append as many URL parameters as you like using &:
<a href="<?php fetchdir($ipages); ?>product.php?Name=<?php echo $name; ?>&id=<?php echo $id; ?>" ...
product.php?Name=$name&pid=$pid
You can use & to add two or more GET parameters to a URL.
One good way to build a property encoded is to use the http_build_query function, this will ensure that the data sent in the request is properly encoded.
<?php
$qstr = http_build_query(array("Name"=>$row["Name"], "id"=>$row["pid"]));
?>
<a href="<?php fetchdir($ipages) ?>product.php?<?= $qstr ?>">
This of course can also be done inline
<a href="<?php fetchdir($ipages) ?>product.php?<?= http_build_query(array("Name"=>$row["Namw"], "id"=>$row["pid"])) ?>">