how to display checkin table in one row - php

Question

I have a table that looks like this.
pers_id pers_name pers_date pers_date_attend_ind
431 Bacon 1/14/2013 N
431 Bacon 1/27/2013 N
431 Bacon 1/28/2013 N
431 Bacon 2/17/2013 N
I'd like to display it in php like
<date 1> <date 2> <Date 3>
Bacon N N N
I'm at a loss for how to do that.

Answer 1

Assume your $rows variable will looks after fetching results like this:
$rows = array(0 => array('pers_id' => 431, 'pers_name' => 'Bacon', 'pers_date' => '1/14/2013', 'pers_date_attend_ind' => 'N'),
1 => array('pers_id' => 431, 'pers_name' => 'Bacon', 'pers_date' => '1/27/2013', 'pers_date_attend_ind' => 'N'),
2 => array('pers_id' => 431, 'pers_name' => 'Bacon', 'pers_date' => '1/28/2013', 'pers_date_attend_ind' => 'N'),
3 => array('pers_id' => 431, 'pers_name' => 'Bacon', 'pers_date' => '2/17/2013', 'pers_date_attend_ind' => 'N'),
);
Then I played with this array to make it look like this:
Array
(
[431] => Array
(
[name] => Bacon
[dates] => Array
(
[1/14/2013] => N
[1/27/2013] => N
[1/28/2013] => N
[2/17/2013] => N
)
)
)
using foreach loop:
foreach($rows as $value)
{
$array[$value['pers_id']]['name'] = $value['pers_name'];
$array[$value['pers_id']]['dates'][$value['pers_date']] = $value['pers_date_attend_ind'];
}
Now it looks much better for your table(s) preparation. I created a function what returns a table(s) as you set in your question based on this modified array.
function generate_table($array)
{
$html = '';
foreach($array as $value)
{
$html .= '<table>'; // start table inside the loop. It will looks better due to each member may have different number of date count.
$html .= '<tr>';
$html .= '<td> </td>';
foreach($value['dates'] as $k => $v)
{
$html .= '<td>' . $k . '</td>';
}
$html .= '</tr>';
$html .= '<tr>';
$html .= '<td>' . $value['name'] . '</td>';
foreach($value['dates'] as $v)
{
$html .= '<td>' . $v . '</td>';
}
$html .= '</tr>';
$html .= '</table>';
}
return $html;
}
This function looks a bit nasty, but it works. It's on you to improve this function if you want.
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Answer 2

What you want is a simple SELECT query to get all pers_date and pers_date_attend_ind for one person and limit it to three results only.
SELECT `pers_date`, `pers_date_attend_ind` FROM `table` WHERE `pers_id` = 431 ORDER BY `pers_date` DESC LIMIT 3
Then just fetch the results and print them with php.

Answer 3

Unfotunately mysql doesn have magic function to transform values wich are variables to column names , But in your case you should have an extra column (date_number i have added it in demo) which count the number of dates added.
here is aproach to it:
select `pers_name`,
max(case when `date_number` = 1 then `pers_date_attend_ind` end) as date1,
max(case when `date_number` = 2 then `pers_date_attend_ind` end) as date2,
max(case when `date_number` = 3 then `pers_date_attend_ind` end) as date3,
max(case when `date_number` = 4 then `pers_date_attend_ind` end) as date4
from Table1
HERE demo to play with