PDO Update 1 column multiple rows with array - php

Question

I am struggling to workout a good method to update one column of my wcx_options table.
The new data is sent fine to the controller but my function isn't working at all.
I assumed i could loop through each column by option_id updating with the values from the array.
The database:
I update the option_value column with the new information via a jQuery AJAX Call to a controller which then calls a function from the backend class.
So far i have the following code:
if(isset($_POST['selector'])) {
if($_POST['selector'] == 'general') {
if($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest' && isset($_POST['token'])
&& $_POST['token'] === $_SESSION['token']){
$site_name = $_POST['sitename'];
$site_url = $_POST['siteurl'];
$site_logo = $_POST['sitelogo'];
$site_tagline = $_POST['sitetagline'];
$site_description = $_POST['sitedescription'];
$site_admin = $_POST['siteadmin'];
$admin_email = $_POST['adminemail'];
$contact_info = $_POST['contactinfo'];
$site_disclaimer = $_POST['sitedisclaimer'];
$TimeZone = $_POST['TimeZone'];
$options = array($site_name, $site_url, $site_logo, $site_tagline, $site_description, $site_admin, $admin_email,$contact_info, $site_disclaimer, $TimeZone);
// Send the new data as an array to the update function
$backend->updateGeneralSettings($options);
}
else {
$_SESSION['status'] = '<div class="error">There was a Problem Updating the General Settings</div>';
}
}
}
This is what i have so far in terms of a function (It doesnt work):
public function updateGeneralSettings($options) {
$i = 1;
foreach($options as $option_value) {
$where = array('option_id' => $i);
$this->queryIt("UPDATE wcx_options SET option_value='$option_value' WHERE option_id='$where'");
$i++;
}
if($this->execute()) {
$_SESSION['success'] = 'Updated General Settings Successfully';
}
}

Answer 1

With the given DB-layout i'd suggest to organize your data as assiciative array using the db fieldnames, like:
$option = array(
'site_name' => $_POST['sitename'],
'site_url' => $_POST['siteurl'],
// etc.
'timeZone' => $_POST['TimeZone']
);
And than use the keys in your query:
public function updateGeneralSettings($options) {
foreach($options as $key => $value) {
$this->queryIt("UPDATE wcx_options SET option_value='$value' WHERE option_name='$key'");
if($this->execute()) {
$_SESSION['success'] = 'Updated General Settings Successfully';
}
}
}
(However, are you sure, you do not want to have all options together in one row?)

Answer 2

Change your query, you try to use an array as where condition. In the syntax you used that won't work. Just use the counter as where condition instead of define a $where variable. Try this:
public function updateGeneralSettings($options) {
$i = 1;
foreach($options as $option_value) {
$this->queryIt("UPDATE wcx_options SET option_value='$option_value' WHERE option_id='$i'");
$i++;
}
if($this->execute()) {
$_SESSION['success'] = 'Updated General Settings Successfully';
}
}