Here is my query i am retrieving birthday list from database using this query i want to retrieve data in asc order by dob(date of birth) i am using order by dob asc but its giving mysql syntax error.
QUERY
SELECT * FROM members
WHERE DATE_ADD(dob, INTERVAL YEAR(CURDATE())-YEAR(dob) YEAR)
BETWEEN CURDATE()
AND DATE_ADD(CURDATE(), INTERVAL 7 DAY
ORDER BY dob ASC
its working now here is one problem again the dob(date of birth) format is 1990-10-11 when i am using order by dob asc its short the data 1990-10-11 , 1991-10-09, but i want to short this by data not year like 1991-10-09, 1990-10-11
try this you are missing ) in your query
"SELECT * FROM members WHERE DATE_ADD(dob, INTERVAL YEAR(CURDATE())-YEAR(dob) YEAR) BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 7 DAY) order by date(dob) asc"
if you wan to sort by month than use order by Month(dob)
You can also try with selected field something like this
'SELECT field1, field2, DATE_FORMAT(dob, "%d-%M-%Y") AS userdob FROM members WHERE
DATE_ADD(dob, INTERVAL YEAR(CURDATE())-YEAR(dob) YEAR) BETWEEN CURDATE() AND
DATE_ADD(CURDATE(), INTERVAL 7 DAY) order by userdob asc'
You missed a )
...BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 7 DAY order by...
Related
I want to get the today count of users and yesterday's users count for that i want to write only one query how can i do that..?
these are my queries I want only one query:
SELECT COUNT(*) FROM visitors group by visited_date ORDER by visited_date DESC limit 1,1 as todayCount
SELECT COUNT(*) FROM visitors group by visited_date ORDER by visited_date DESC limit 1,0 as yesterdayCount
My expected results or only 2 columns
todayCount yesterdayCount
2 4
This should do the trick:
SELECT COUNT(CASE
WHEN visited_date = CURDATE() THEN 1
END) AS todayCount ,
COUNT(CASE
WHEN visited_date = CURDATE() - INTERVAL 1 DAY THEN 1
END) AS yesterdayCount
FROM visitors
WHERE visited_date IN (CURDATE(), CURDATE() - INTERVAL 1 DAY)
GROUP BY visited_date
ORDER by visited_date
If you know the current and previous date, then you can do:
SELECT SUM(visited_date = CURDATE()) as today,
SUM(visited_date = CURDATE() - interval 1 day) as yesterday
FROM visitors
WHERE visited_date >= CURDATE() - interval 1 day;
If you don't know the two days, then you can do something similar, getting the latest date in the data:
SELECT SUM(v.visited_date = m.max_vd) as today,
SUM(v.visited_date < m.max_vd) as yesterday
FROM visitors v CROSS JOIN
(SELECT MAX(v2.visited_date) as max_vd FROM visitors v2) as m
WHERE v.visited_date >= m.max_vd - interval 1 day
Just try this simple query
select visited_date as date, COUNT(*) as count from `visitors`
group by `visited_date` order by `visited_date` asc
It will produce output as
It will work for you.
Try this:
$sqlToday = "Select COUNT(*) FROM menjava WHERE DATE(date_submitted)=CURRENT_DATE()";
$sqlYesterday = "Select COUNT(*) FROM menjava WHERE DATE(dc_created) = CURDATE() - INTERVAL 1 DAY";
I am querying records from the last calendar month. As it is February, it should return all the records that were added on January this year.
My Query:
`SELECT * FROM table_name WHERE date >=
DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 2 MONTH)), INTERVAL 1
DAY) AND date <= DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 1
MONTH)), INTERVAL 0 DAY) AND campaign = '$campaign' ORDER BY date
ASC`
It returns some records but skips the first 9 days. It starts showing records from 10th of the previous month. What am I missing here?
check your date field type and make sure you have not mistaken it with varchar.
SELECT * FROM table_name WHERE
(MONTH(date) = (MONTH(NOW()) - 1) AND YEAR(date) = YEAR(NOW()))
OR
(MONTH(date) = 12 AND MONTH(NOW())=1 AND YEAR(date) = (YEAR(NOW()) - 1) AND campaign = '$campaign' ORDER BY date
ASC`
Try To Get Data in step by step like,
First, you should try below query.
SELECT Date, DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 2 MONTH)), INTERVAL 1 DAY) AS StartDate, DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 1 MONTH)), INTERVAL 0 DAY) AS EndDate FROM MyTable
Second, If First Step give right date then get your data by directly writing your date rather than DATE_ADD function in where clause.
Third, If These will Give you write DATA then try to fetch data using DATE_ADD function.
Replay If you will get solution.
SELECT * FROM table_name WHERE date between DATE_SUB(DATE_SUB(CURRENT_DATE,INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY),INTERVAL 1 MONTH) AND DATE_SUB(DATE_SUB(CURRENT_DATE,INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY),INTERVAL 1 DAY) AND campaign = '$campaign' ORDER BY date ASC
I am working on an event management project, I need to get upcoming event from database, can anyone help me ?
I am using
SELECT *FROM EVENTS WHERE DATE_ADD(event_date, INTERVAL YEAR(CURDATE())-YEAR(event_date) YEAR)
BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 7 DAY) LIMIT 1;
But it gives me the event upcoming within 7 days only.
I should not want to provide days.
I want to get first upcoming event , doesn't matter after or within how many days it is coming.
thank you !
Isn't this a simple where clause comparing with current date
SELECT *
FROM EVENTS
WHERE event_date > CURDATE()
ORDER BY event_date
LIMIT 1;
Wouldn't this work?
SELECT * FROM EVENTS WHERE event_date > CURDATE() ORDER BY event_date ASC LIMIT 1;
try
If column type datetime you can use CURDATE()(mysql function) or date()(php function)
"SELECT *FROM EVENTS WHERE event_date > '".date('Y-m-d H:i:s')."' ORDER BY event_date limit 1"
or
"SELECT *FROM EVENTS WHERE event_date > CURDATE() ORDER BY event_date limit 1"
If column type date
"SELECT *FROM EVENTS WHERE event_date > '".date('Y-m-d')."' ORDER BY event_date limit 1"
try below it works perfectly fine
select * from table where start_time between NOW() AND DATE_ADD(NOW(), INTERVAL 7 DAY)
you can use like this to get next 7 days data or in case you want last 7 days then instead of DATE_ADD USE DATE_SUB It will work or you can use like
start_time between NOW() AND DATE_ADD(NOW(), INTERVAL 1 WEEK)
this also works. to know more check this ref https://dev.mysql.com/doc/en/date-and-time-functions.html
thank you everyone,
I got the answer:
SELECT * FROM EVENTS
WHERE event_date > CURDATE()
ORDER BY event_date ASC LIMIT 1;
I have this code to select from my database data from current month:
SELECT * FROM daily_reports
WHERE username = '$username' and MONTH(date) = MONTH(Now())
order by date DESC
And now i want to display data from last month.
column date is type date
Try this
SELECT * FROM daily_reports
WHERE username = '$username'
and MONTH(date) = MONTH(DATE_ADD(Now(), INTERVAL -1 MONTH)) order by date DESC
This should work:-
SELECT *
FROM daily_reports
WHERE username = '$username'
and MONTH(date) = MONTH(DATE_ADD(Now(), INTERVAL -1 MONTH))
order by date DESC
SELECT
*
FROM
daily_reports
WHERE username = '$username'
AND dateColumn BETWEEN SUBDATE(CURDATE(), INTERVAL 1 MONTH) AND NOW();
ORDER BY DATE DESC
You can do many operations on dates, as shown in the fine manual.
In your case, perhaps the DATE_SUB function would be clearest:
SELECT * FROM daily_reports
WHERE username = '$username' AND MONTH(date) = MONTH(DATE_SUB(Now(), INTERVAL 1 MONTH)
ORDER BY date DESC
date BETWEEN date_format
(NOW() - INTERVAL 1 MONTH, '%Y-%m-01')
AND last_day(NOW() - INTERVAL 1 MONTH)
I am trying to call data from SQL table that is only 3 days old
My table has a lbs-date column in it and is date format. I have tried the following but get no result from the query at all
$result = mysql_query("SELECT *, DATE_FORMAT(datetime, '%y,%m,%d') FROM lbs_trace_etrack
WHERE lbs_date(datetime) = CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC")
Is there any other way I can call only the last 3 days of information from the SQL my date format is Y/M/D
SELECT *, DATE_FORMAT(lbs_date, '%y,%m,%d')
FROM lbs_trace_etrack
WHERE lbs_date >= CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC
check DATE_FORMAT. Its syntax is DATE_FORMAT(<date>,format) . Use like this :
SELECT *, DATE_FORMAT(lbs_date , '%y,%m,%d') FROM lbs_trace_etrack
WHERE lbs_date = CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC