Show picture from database don´t work - php

Question

I wnt to show some pictures i have in a mysqli database, they are stored as blob.
But all i get is a A4 page with wierd text..
this is my code that i use too show(i connect to my database above this code):
echo "<table border=1>\n";
/*echo " <tr>\n";
echo " <th>Bild</th><th>Namn</th><th>Betygsättning</th>\n";
echo " </tr>\n";*/
while ($rad = mysqli_fetch_array($sql_result)) {
echo "<tr>";
echo "<td>";?> <img src="<?php echo $rad["Bild"]; ?>" height="100" width="100"> <?php echo "</td>";
echo "<td>"; echo $rad["Namn"]; echo "</td>";
echo "</tr>";
}
echo "</table>\n";

Answer 1

If you really want to embed the image to the generated html you should write it as this here:
echo "<td>";?> <img src="data:image/jpeg;base64,<?php echo base64_encode($rad["Bild"]); ?>" height="100" width="100"> <?php echo "</td>";
Here again with a little more clean code:
echo "<table border=\"1\">\n";
while($rad = mysqli_fetch_array($sql_result)) {
echo " <tr>\n";
echo " <td>\n";
echo " <img src=\"data:image/jpeg;base64," . base64_encode($rad["Bild"]) . "\" height=\"100\" width=\"100\" />\n";
echo " </td>\n";
echo " <td>" . $rad["Namn"] . "</td>";
echo " </tr>\n";
}
echo "</table>\n";
It seem that you forgot also to close your img tag.

Answer 2

echo '<table border=1>';
/*echo " <tr>\n";
echo " <th>Bild</th><th>Namn</th><th>Betygsättning</th>\n";
echo " </tr>\n";*/
while ($rad = mysqli_fetch_array($sql_result)) {
echo '<tr>
<td><img src="'.$rad["Bild"].'" height="100" width="100"></td>
<td>'.$rad["Namn"].'</td>
</tr>';
}
echo '</table>';
That should do it. While you are in a block of php code you can concatonate on it like above.