Radio button "yes" if checked, "no" if unchecked - php

Question

Good afternoon, I having difficulty with the radio button on a form I have created. I found a similar problem on here, but with having limited php coding experience, I was unable to correctly code it or my form. Any help would be greatly appreciated.
<?php
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$email = $_POST['email'];
$phone = $_POST['phone'];
$procedure = $_POST['procedure'];
$date = $_POST['date'];
$message = $_POST['message'];
$policybox = null;
foreach($_POST['policy'] as $policy){
if(isset($policy)){
$policybox .= "Yes\r\n";
} else{
$policybox .= "No\r\n";
}
}
$formcontent="From: $firstname $lastname \nEmail: $email \nPhone: $phone \nType of Procedure: $procedure \nDate Requested: $date \nI have read and understood the policies: $policybox \nMessage: $message";
$recipient = "sales#domainname.com";
$subject = "Appointment Form from DomainName.com";
$mailheader = "From: $email \r\n";
mail($recipient, $subject, $formcontent, $mailheader) or die("Error!");
header('Location: appointments.php');
?>
The field Im trying to get to show up is:
<div class="form_info cmsms_radio">
<div class="check_parent">
<input type="radio" name="policy" value="Yes" />
<label for="policy">I have read and understand the Refund Policy and Cancellation Policy</label>
</div>
Im sure its something small Im missing, but like I said Im not very experienced with php yet.

Answer 1

Your $_POST['policy'] variable isn't going to be an array (based on your code), therefore you do not need to iterate over it. You can simply test the form value itself.
Replace your foreach with the following:
if(isset($_POST['policy']) && $_POST['policy'] == "Yes") {
$policybox .= "Yes\r\n";
} else{
$policybox .= "No\r\n";
}