Why does my script skips trhough the If statements with mysql query - php

Question

I'm trying to make a login script for a project that I have. I came accross an open source and i typed some and copy/paste some. I went through the whole thing. I found that the login Function on the if statement where it says mysql->prepare is just skipping. I do not know if it is something with the database or an error on the script.
The place where I got the script was this
http://www.wikihow.com/Create-a-Secure-Login-Script-in-PHP-and-MySQL
my test page is ertechs.t15.org is the login.php for logging in.
username is test_user#example.com and the password is 6ZaxN2Vzm9NUJT2y.
Thanks in advance.
and this is where i'm having the problem. this function
function login($email, $password, $mysqli) {
echo "Function login";
// Using prepared statements means that SQL injection is not possible.
$prep_smt = "SELECT id, username, password, salt FROM members WHERE email = ? LIMIT 1";
$smt = $mysqli->prepare($prep_smt);
if ($stmt)
{
echo "Tst passed";
$stmt->bind_param('s', $email); // Bind "$email" to parameter.
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
// get variables from result.
$stmt->bind_result($user_id, $username, $db_password, $salt);
$stmt->fetch();
// hash the password with the unique salt.
$password = hash('sha512', $password . $salt);
echo "password= =".$password;
if ($stmt->num_rows == 1) {
echo "row";
// If the user exists we check if the account is locked
// from too many login attempts
if (checkbrute($user_id, $mysqli) == true) {
echo "brute true";
// Account is locked
// Send an email to user saying their account is locked
return false;
} else {
echo "pass match";
// Check if the password in the database matches
// the password the user submitted.
if ($db_password == $password) {
echo "pass correct";
// Password is correct!
// Get the user-agent string of the user.
$user_browser = $_SERVER['HTTP_USER_AGENT'];
// XSS protection as we might print this value
$user_id = preg_replace("/[^0-9]+/", "", $user_id);
$_SESSION['user_id'] = $user_id;
// XSS protection as we might print this value
$username = preg_replace("/[^a-zA-Z0-9_\-]+/",
"",
$username);
$_SESSION['username'] = $username;
$_SESSION['login_string'] = hash('sha512',
$password . $user_browser);
// Login successful.
return true;
} else {
echo "Password Failed";
// Password is not correct
// We record this attempt in the database
$now = time();
$mysqli->query("INSERT INTO login_attempts(user_id, time)
VALUES ('$user_id', '$now')");
return false;
}
}
} else {
echo "user doesnt exist";
// No user exists.
return false;
}
echo "whatever";
}
echo "end Function Login";
}

Answer 1

$smt = $mysqli->prepare($prep_smt);
if ($stmt)
Notice the missing t in $stmt?