If in PHP, a program outputs a <div>, which has a :before part to it, which my code should choose the attributes for. As my code has multiple instances where the :before should have different attributes, I cannot just edit the .css file or create a <style> tag at the top.
I have tried to create a new <style> tag before each <div>, but all the attributes end up being the same last <style> (Yes, I know why). So my current thinking is to be able to edit the :before from within the <div style=""> but I can't seem to be able to get :before to be changed there.
Does anyone know how to either edit the :before part within the tag's style = "" if that is even possible or another solution to this?
My current hypothesis (which didn't work for the fact that the first letter in CSS stands for Cascading) :
$array = [["text" => "Example 1", "colour" => "#880000"],["text" => "Example 2", "colour" => "#008800"]
foreach($array as $current){
echo '<style>
div.before{
color: '.$current["colour"].';
}
</style>';
echo '<div><p>'.$current["text"].'</p></div>'
}
(Note: In the actual code it is coming from a database)
If you are using PHP to determine styling I would strongly advise creating a custom stylesheet that you conditionally control.
HTML
<link rel='stylesheet' type='text/css' href='css/style.css' />
<link rel='stylesheet' type='text/css' href='css/custom_style.php' />
CSS
<?php
header("Content-type: text/css; charset: UTF-8");
$brandColor = "#990000";
$linkColor = "#555555";
$CDNURL = "http://cdn.blahblah.net";
#header {
background: url("<?php echo $CDNURL; ?>/images/header-bg.png") no-repeat;
}
a {
color: <?php echo $linkColor; ?>;
}
ul#main-nav li a {
color: <?php echo $linkColor; ?>;
}
?>
Example Source http://css-tricks.com/css-variables-with-php/
Based on your code I would assign a class to the div depending on the color. You will need to replace the # with a letter for CSS to read it.
$array = [["text" => "Example 1", "colour" => "#880000"],["text" => "Example 2", "colour" => "#008800"]
foreach($array as $current){
$className = str_replace('#', 'C', $current["colour"]);
echo '<style>';
echo 'div.'.$className.':before {
color: '.$current["colour"].';
}';
echo '</style>';
echo '<div class="'.$className.'"><p>'.$current["text"].'</p></div>'
}
Related
The last few days I've been experimenting with defining CSS stylesheet that is configuring the page to be printed out.
This is my final solution, which is working (at least what I can see in the html output):
home.php being called initially:
<?php
$_SESSION['pageWidth'] = 20;
$_SESSION['pageHeight'] = 15;
$_SESSION['pageOrientation'] = "landscape";
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width,minimum-scale=1">
<?php
echo "<style type='text/css' media='print'>
.card {
clear: both;
page-break-before: always;
}
.no-print, .no-print *
{
display: none !important;
}
#page : left{
margin: 0.5cm;
}
#page : right{
margin: 0.5cm;
}
#page : top{
margin: 1.5cm;
}
/* https://docs.w3cub.com/css/#page/size */
#page {
size: " . $_SESSION['pageWidth'] + 2.5 ."cm " . $_SESSION['pageHeight'] + 2.5 . "cm " . $_SESSION['pageOrientation'] . " !important;
}
</style>";
?>
</head>
During using integrated php files (called by include "cardGenerator.php";), the session_variables are updated with other values (width, height and maybe orientation, depending on the content).
Unfortunately, even my initial set values are ignored by browsers even though in the browser session, it looks all good:
I've been trying it with chrome, edge and firefox - all of them ending up in ignoring the #page{size: } statement.
Does anybody have an idea or same experiences with browsers?
I've been doing this:
put variable values into session to overwrite these value from any php file at any time and to integrate it into css
put css <style> </style> section into header of home.php which is the "leading" php
trying to print out from chrome, edge, firefox
trying with different width/height values
checked many solutions in stackoverflow
During studying some additional material, I've realized that defining a width and a height actually leads to kind of a landscape/portrait. So this information is obsolete. My working code:
<?php
echo "<style type='text/css' media='print'>
.card {
clear: both;
page-break-before: always;
}
.no-print, .no-print *
{
display: none !important;
}
#page : left{
margin: 0.5cm;
}
#page : right{
margin: 0.5cm;
}
#page : top{
margin: 1.5cm;
}
/* https://docs.w3cub.com/css/#page/size */
#page {
size: " . $_SESSION['pageWidth'] + 2.5 ."cm " . $_SESSION['pageHeight'] + 2.5 . "cm !important;
}
</style>";
?>
So, hopefully, this helps other with similar issues. As well as my approach on passing PHP variables into a stylesheet.
I am building a system where the requirement says no links to CSS are allowed. They do allow to place all CSS content within the style element.
I am using DOMDocument to build the XML/XHTML.
The CSS stylesheets are around 320 lines so I would pefer to construct them in separate CSS files and solve the insertion of the CSS content in the DomDocument build.
Question:
What is the best way of inserting an external CSS file content
and get it in place between the DOMDocument built style element?
Index.php
<?php
$xml = new DomDocument('1.0', 'UTF-8');
$xml->formatOutput = true;
$html = $xml->createElement('html');
$xml->appendChild($html);
$head = $xml->createElement('head');
$html->appendChild($head);
//
$style = $xml->createElement(
'style',
'css-content....' // The CSS content from external file should be inserted here.
);
$style->setAttribute('type', 'text/css');
$head->appendChild($style);
echo $xml->saveXML();
Main.css
body {
background-color: pink;
}
Wanted result
<?xml version="1.0" encoding="UTF-8"?>
<html>
<head>
<style type="text/css">
body {
background-color: pink;
}
</style>
</head>
</html>
Try something along these lines:
Add
$css = file_get_contents('main.css');
and change $style to:
$style = $xml->createElement('style', $css);
and it should work.
I need to add the same icon to each of the li class that are generated automatically by a PHP script that Im using in a customized widget, in a Wordpress site.
This is the script Im using in a wordpress widget to display some child pages.
<?php
$ancestor_id=24;
$descendants = get_pages(array('child_of' => $ancestor_id));
$incl = "";
foreach ($descendants as $page) {
if (($page->post_parent == $ancestor_id) ||
($page->post_parent == $post->post_parent) ||
($page->post_parent == $post->ID))
{
$incl .= $page->ID . ",";
}
}?>
<ul>
<?php wp_list_pages(array(
"child_of" => $ancestor_id,
"include" => $incl,
"link_before" => "",
"title_li" => "",
"sort_column" => "menu_order"));?>
</ul>
The code for the icon (has already a class asigned) that I need to be used is..
<img class='sideicons' src="http://accountabletest.com/wp-content/uploads/2013/12/iconSidebar1.jpg" alt="" >
How can I make each <li> generated to include the same icon?
use css, the rules you need are list-style-type and list-style-icon
Sounds like to do it in PHP would probably be more trouble than it's worth... How about javascript or jquery?
$('li').each(function(i,el){
$(this).prepend('<img src="path/to/image.ico" />');
})
If you need to change the existing source of an image, target with something like $('li img')
Change .prepend() to attr('src','your/new/image.jpg')
Why you are not using CSS? It is easier way to do. just assign a class to your ul and add a background image to li tags.
like:
<ul class="list">
<?php wp_list_pages(
array(
"child_of" => $ancestor_id,
"include" => $incl,
"link_before" => "",
"title_li" => "",
"sort_column" => "menu_order"
)
);?>
</ul>
<style>
ul.list li {
background: url(http://accountabletest.com/wp-content/uploads/2013/12/iconSidebar1.jpg) no-repeat left center;
padding-left: 10px;
}
</style>
I have a menu that is image based (one yellow and one blue, for example). I designed the buttons in Illustrator and then converted to PNG files. Right now, I'm using CSS for hovering affects.
So when I hover over the image, it changes. So this is good (because it works), but its far from perfect (that's why I'm here)... One of my buttons in CSS looks like this:
.home_menu, .about_menu, .video_menu, .demo_menu, .contact_menu {
float: left;
margin-bottom: 10px;
margin-top: 10px;
margin-left: 10px;
width: 100px;
height: 34px;
display: block;
}
.home_menu {
background: transparent url('../images/buttons/home_but.png');
}
.home_menu:hover {
background-image: url('../images/buttons/home_but_hov.png');
}
The HTML is like started out like so:
<div id="main_menu">
</div>
So basically I'm changing the CSS background image for each class.
Two questions. First, I'm trying to get each menu to be the blue version when on that page. So I wrote a PHP function to do this (in a class), just in case I want to avoid JavaScript. It looks like this:
// Display table and loop through links and images from array
public function print_navigation($image_dir, $ds, $page_nav, $page_nav_alt, $menu) {
$current_file = explode('/', $_SERVER['PHP_SELF']);
$current_page = $current_file[count($current_file) - 1];
$current_page;
//$i = 0;
foreach ($page_nav as $key => $value) {
$menu_output .= '<a href="';
$menu_output .= $key;
$menu_output .= '" id="';
$menu_output .= $menu[$key];
$menu_output .= '" style="background: transparent url(';
if ($current_page == $key) {
$menu_output .= $image_dir . $ds . $page_nav_alt[$key];
}
else {
$menu_output .= $image_dir . $ds . $page_nav[$key];
}
$menu_output .= ');"';
$menu_output .= '></a>';
$i++;
}
echo $menu_output;
}
It seems to work for the Home page ($home variable), but not for the others. I have variables like this (arrays and variables in another file, truncated for brevity):
$menu = array(
$home => 'home_menu',
...);
$page_nav_ylw = array(
$home => $home_but_ylw,
...);
$page_nav_blu = array(
$home => $home_but_blu,
...);
Then I have all the images in variables, referenced to in the arrays, eg, $home_but_ylw refers to the PNG for that button.
The PHP function is a bit odd, because I use the $key for two arrays, which I'm sure is bad. But I'm having a hard time getting it to work otherwise.
Second question is: is there any reason I can't add JavaScript (like jQuery) right on top of this to get me the hover effects so that I can remove it from the CSS? Ideally I'd like to display the buttons with a PHP loop that also handles current page and then do the hover affects with jQuery.
Sorry for the long post. Hope it makes sense.
Thanks in advance!
If you were planning on serving your pages dynamically then I think jQuery would be a much better option. However, if your links are going to separate pages then try something this:
function printNav($Page = "home"){
$HTML = "";
$HTML .= "";
$HTML .= "";
$HTML .= "";
$HTML .= "";
echo $HTML;
}
On each separate page:
<div id="main_menu">
<?php printNav("home"); ?>
</div>
CSS:
.ActiveNav {
background-image: url('../images/buttons/blue_bg.png');
}
.MenuItem {
float: left;
margin-bottom: 10px;
margin-top: 10px;
margin-left: 10px;
width: 100px;
height: 34px;
display: block;
}
.HomeMenuItem {
background: transparent url('../images/buttons/home_but.png');
}
.HomeMenuItem:hover {
background-image: url('../images/buttons/home_but_hov.png');
}
EDIT: If you wanted a different image for each button - I would suggest using a generic button background and hover and putting the text and icons on top of it.
Based on this answer, I was able to find a work around to my problem:
PHP menu navigation
Basically, I used the GET method to get the selected class. This worked nicely. I consolidated my CSS, and was able to get this thing working.
Here is what it turned out like, for one link:
<?php $class = $_GET['selected_tab']; ?>
<div id="main_menu">
<a href="index.php/?selected_tab=home" id="home_menu" title="Home"
class="<?php if(strcmp($class, 'home') == 0) {echo 'selected';} ?>"></a>
CSS like so:
#home_menu {
background: transparent url('../images/buttons/home_but.png');
}
#home_menu:hover, #home_menu.selected {
background-image: url('../images/buttons/home_but_hov.png');
}
Next step is to convert to jQuery.
Thanks Mike GB for your help but it wasn't quite what I was looking for.
I want to generate tooltip based on a dynamically changing background image in css.
This is my my_css.php file.
<?php
header('content-type: text/css');
$i = $_GET['index'];
if($i == 0)
$bg_image_path = "../bg_red.jpg";
elseif ($i == 1)
$bg_image_path = "../bg_yellow.jpg";
elseif ($i == 2)
$bg_image_path = "../bg_green.jpg";
elseif ($i == 3)
$bg_image_path = "../bg_blue.jpg";
?>
.tooltip {
white-space: nowrap;
color:green;
font-weight:bold;
border:1px solid black;;
font-size:14px;
background-color: white;
margin: 0;
padding: 7px 4px;
border: 1px solid black;
background-image: url(<?php echo $bg_image_path; ?>);
background-repeat:repeat-x;
font-family: Helvetica,Arial,Sans-Serif;
font-family: Times New Roman,Georgia,Serif;
filter:alpha(opacity=85);
opacity:0.85;
zoom: 1;
}
In order to use this css I added
<link rel="stylesheet" href="css/my_css.php" type="text/css" media="screen" />
in my html <head> tag of javascript code. I am thinking of passing different values of 'index' so that it would generate the background image dynamically. Can anyone tell me how should I pass such values from a javascript ? I am creating the tooltip using
var tooltip = document.createElement("div");
document.getElementById("map").appendChild(tooltip);
tooltip.style.visibility="hidden";
and I think before calling this createElement, I should set background image.
You seem to be asking two completely independent questions.
First, the way to pass a parameter would be in your <link> tag:
<link rel="stylesheet" href="css/my_css.php?index=3" type="text/css" media="screen" />
When the page loads, the browser will request the css/my_css.php?index=3 page from your server and use the CSS that gets returned.
However, you're also asking about setting this value with JavaScript. That suggests that you want the CSS to change throughout the request. In that case, PHP is absolutely the wrong technology to be using.
Instead, consider adding classes like:
.tooltip-background-1 {
background-image: url(../bg_red.jpg);
}
Then you do not need any dynamic content in the CSS file. Just include all four (or more) rules at once, and use JavaScript to change which class applies to the element.
Finally, if you goal is simply to choose a random background color, you could just let PHP choose the random value, eliminating any need for a parameter or for JavaScript and PHP to interact at all.
I suggest you for improve a part of the code use that:
$bg_image_path = '../bg_';
switch($i)
{
case 0: $bg_image_path .= 'red.jpg'; break;
case 1: $bg_image_path .= 'yellow.jpg'; break;
case 2: $bg_image_path .= 'green.jpg'; break;
case 3: $bg_image_path .= 'blue.jpg'; break;
}
instead of specifying the background image in the css file, try just doing it all with JavaScript. So remove the background-image from the css file and remove all the php and remove the colour (if that is what you want to change when the background image changes), basically anything you need to change, remove from the css and change it with JavaScript.
Then use some code like this:
<html>
<head>
<script type="text/javascript">
var i = 0;
var cols = new Array(8);
cols[0] = "FFFFFF";
cols[1] = "EEEEEE";
cols[2] = "DDDDDD";
cols[3] = "CCCCCC";
cols[4] = "BBBBBB";
cols[5] = "AAAAAA";
cols[6] = "999999";
cols[7] = "888888";
cols[8] = "777777";
var imgs = new Array(8);
img[0] = "img1.jpg";
img[1] = "img2.jpg";
img[2] = "img3.jpg";
img[3] = "img4.jpg";
img[4] = "img5.jpg";
img[5] = "img6.jpg";
img[6] = "img7.jpg";
img[7] = "img8.jpg";
img[8] = "img9.jpg";
function change()
{
document.getElementById("div").bgColor = cols[i];
document.body.background = img[i];
i++;
if(i > 8)
{
i=0;
}
}
</script>
</head>
<body onLoad="setInterval('change()',1000)">
<div id="div">Tooltip</div>
</body>
</html>
This code loops through the array of colors and background images, it will change once per second. It changes the color of the divs background and the backgrounds image.