Posting an array into a php document - php

Question

I want to be able to post an array containing...
$food = array (
'food_1' => 'ice cream ',
'food_2' => 'pizza'
);
<input type="text" id="in_foods[]" value="<?=$food;?>" />
to another page but it does not seem to be working. what am I doing wrong?

Answer 1

A cleaner solution will be to:
1- convert the array into a string using the implode function:
$foods = implode(',',$foods);
2- Place it in the input text field to be submitted:
<input type="text" id="foods" value="<?=$food;?>" />
3- On the other page convert the string back to an array:
$foods = explode(',',$_POST['foods'])
Try ;)

Answer 2

You can't just post a data structure like that. You should be getting a notice saying you're trying to convert an array to string.
Consider putting your array into a session instead. That way it stays as an array between calls.
session_start();
$_SESSION['food'] = $food;

Answer 3

Try with this code :
<?php
$food = array (
'food_1' => 'ice cream ',
'food_2' => 'pizza'
);
$food = implode(",", $food);
?>
<input type="text" id="in_foods[]" value="<?=$food;?>" />

Answer 4

As $food is an array.
<input type="text" id="in_foods[]" value="<?
if (isset($food)) { echo $food['food_1'].', '.$food['food_2']; } ?>"
/>
If size of $food array is not defined then you can use implode function to make it as single string and can echo it.

Answer 5

I guess you wan't to tick foods you like out of a predefined list of foods or something like this. In this case an <input type="text"> field is not the right choice. Use <input type="checkbox"> instead (or a <select multiple>).
$foodOptions = array('burger', 'vergtables', 'berries')
foreach($foodOptions as $foodOpt) {
$checked = in_array($foodOpt, $foods)?' checked':null;
echo '<input type="checkbox" value="' , $foodOpt , '" name="in_foods[]"', $checked ,'><br>';
}