Display array rows only if a file path has a certain extension - php

Question

I have an array, which contains amongst other things a file path to a video file. There are various file formats .avi, .mp4 etc etc.
Now I only want to display the rows where the file path's file extension is .mp4.
Currently I'm using a function to extract the file extension, but I'm having trouble doing this on the fly while displaying the rows.
An example of the file path: c:\TempVideoDir\Office-P-cam01-20140826-083016.avi
The function im using to get the file ext:
function get_fileext($filename) {
$cut_fileext = (explode('.', $filename));
$just_fileext = $cut_fileext[1];
echo $just_fileext;
}
Which works fine.
Now I'm querying the database to get the filepath along with other details about the file, and I only want to display the rows where the file path contains a .mp4 file.
I've tried everything I could thing of/find on Google etc but this is what I currently have:
$stmt->execute();
$result = $stmt->fetchAll();
foreach($result as $row) {
if (in_array((get_fileext($row["Filename"])== "mp4"), $result)) {
echo " blah blah
I dont have the option of adding the file extension into the database table as this is backed up automatically by a piece of equipment.
So, whadoyareckon? is it possible to do it on the fly like this?
Any help is much appreciated!
Thanks

Answer 1

I dont think you can use in_array() like that. Its searching the entire index of the array, so when it looks ate $result[] its never going to find $row['filename'] with only an ext.
try this:
//looping through $result array
foreach($result as $row) {
//check if $row['filename'] has a string with a mp4 extension.
if (get_fileext($row["Filename"])== "mp4") {
echo "Row has a filename with the mp4 extension';
also as someone else pointed out fix your get_fileext() method to return something.
function get_fileext($filename) {
$cut_fileext = (explode('.', $filename));
$just_fileext = $cut_fileext[1];
return $just_fileext;
}

Answer 2

Your function isn't returning a value. It's emitting the value to the output:
function get_fileext($filename) {
$cut_fileext = (explode('.', $filename));
$just_fileext = $cut_fileext[1];
echo $just_fileext;
}
So there's no way for anything invoking that function to see that result. Instead, return the value:
function get_fileext($filename) {
$cut_fileext = (explode('.', $filename));
$just_fileext = $cut_fileext[1];
return $just_fileext;
}
That way the invocation of the function itself evaluates to the returned value, allowing you to use the function in your logic.

Answer 3

You could consider adjusting your database query to only return rows with ".mp4" files.
Change your query to have something like:
filepath = "%.mp4"
In MySQL the % operator is a wildcard, so this will match any strings ending in ".mp4"