I use ajax type for send data to php file and get response and show. In my php file i have
while($i<14){ echo $i.'<br />'; $i++;}
that return 14 replay.
So, my webpage when call data with ajax method, after some secounds, show all 14 results. But i want get live response from my ajax file.
So i want my webpage show :
1
...
and then
1
2
....
etc
This is my Ajax code that return all response together in shower div.
I want get live responses. for any responses that sent from php file
function update_table(uptype){
$("#shower").html("Loading...");
var dataString = 'type=' + uptype;
$.ajax({
type: "POST",
url: "motor.php",
data: dataString,
cache: false,
success: function(html) {
$("#shower").html(html);
}
});
return false;
}
What you are asking is not possible with your current setup.
Think of an ajax-call to a PHP-script is like visiting a website like www.example.com/yourscript.php
PHP will then server-side render a code which is sent to your web-browser. This is a one call and one answer operation. PHP will not dynamically add elements to the website. Neither will it then be able to dynamically send answers to your ajax-call. What you have to do to solve this is storing the progress of the PHP script somewhere, and do several calls to get a update on the status.
Related
I've read all the articles but cant seem to get my ajax response into a PHP variable. Please can you advice. I want to assign rowid to a PHP variable.
$(document).on('click', '#updateid', function() {
var vallab = $('#idval').val();
var rowid;
$.ajax({
url:'a.php',
type: 'POST',
async: false,
data: {labid: vallab},
success: function(data){
// console.log(data);
rowid = data;
}
});
console.log(rowid);
return rowid;
});
my a.php code is below
<?php
# Fetch the variable if it's set.
$lab_id = (isset($_POST["labid"])) ? $_POST["labid"] : null;
echo $lab_id;
?>
I am getting the response back with the id, and want to use it on that page
I want to pass rowid into a PHP function so I need to get the value of rowid.
Please can you advice?
I cant seem to get my ajax response into a PHP variable
Well, the AJAX response came FROM a PHP file, right? So why don't you do whatever you need to do with the response right in that PHP file?
$.ajax({
url:'THIS IS YOUR PHP FILE',
type: 'POST',
data: {THIS IS THE DATA YOU SEND TO PHP},
success: function(data){
console.log(data); //THIS IS THE RESPONSE YOU GET BACK
}
});
You can't use it. Javascript is a scripting language which run in browser when the dom is loaded and elements are visible.
PHP is a serverside language and run on server before the page is loaded.
You need to understand the lifecycle of your application. Your php code executes once, it runs the full script from top to bottom when the page loads. At the point the script starts if can only access the post that came with the request (e.g if you clicked submit on a form then the 'action' of the form receives the post). Any number of things can happen in your script, but once it's finished the php is gone, and so is the post (in basic terms). So you no longer have any access to the php which created this page.
Ajax allows you to update a section of your page - it sends a request to your sever and runs some php code - you must understand that this is a new and separate request, so the new post submission only exists in the lifecycle of this new execution and is in now way linked to the page that has already finished loading. Now you could ask Ajax to call your original script, but that wouldn't affect your page at all because the page does not reload. What you would get is a strange looking response which you (probably) couldn't do anything useful with.
Ajax allows small specific changes to the page, so when you get your response (which I assume you get in a format you want since you don't ask about it and you have a console.log) you then need to do something with jQuery/javascript. Instead of returning rowid write a javascript function like :
function printRowId(rowid) {
$('#your html div id here').text('Row id is ' + rowid);
}
and then call it in your response:
$.ajax({
url:'a.php',
type: 'POST',
async: false,
data: {labid: vallab},
success: function(data){
// console.log(data);
rowid = data;
}
});
printRowId(rowid);
return rowid;
You can use Ajax to update your data, update your database and then reflect the changes on the current page, but you cannot use it to pass directly to the php that has already finished executing
This question already has an answer here:
Wordpress: call to plugin php file via ajax
(1 answer)
Closed 6 years ago.
So I'm making a Wordpress site and want to send data (css styles dynamically created by jQuery) to PHP. The reason for this (not fully relevant to this question) is to write the data as a .css file that is loaded at the beginning of every page--making it so there's no visible 'change' of styles when js executes (well, only the first time the page is loaded). I'm sure there's probably a better way to do this.
But back to the main part (sending data from jQuery to a .php). I'm executing a js script (on "front-page.php") that does this:
jQuery(function($){
$(window).on("load", function() {
$.ajax({
type: "POST",
url: "create-style.php",
data: { style : styleString },
dataType: "json",
success: function () {
console.log("success");
}
});
});
});
The console says 'success', so I assume data is getting passed to create-style.php.
create-style.php's write function does this
$file = 'new-style.css';
$style = $_POST['style'];
file_put_contents($file, $style, LOCK_EX);
Now the first thing I tried was having the function included in Wordpress's functions.php. I don't know a lot about Wordpress or web development in general, but it seems intuitive that this wouldn't work since probably the php files get executed before the js (so how could it get the data?)
In an attempt to solve this I rewrite the create-style.php as a cron using wp_schedule_single_event to fire when someone visits the site, with a slight delay:
add_action('write_style_cron', function(){
// the above writing function
});
wp_schedule_single_event(time() + 10, 'write_style_cron'); // give it a slight delay to make sure jQuery happens
However, no $_POST data gets written to the file and doing any tests shows it's empty. I've done a lot of tests and know that:
cron functionality is basically working
the writing function works with test values
$_POST is showing as completely empty and I get an "Undefined index" error in the /wp-cron.php?doing_wp_cron
$.ajax is firing success
there are no other php / js errors
Thanks for reading this very long post. Been searching the internet all day for solutions and decided it might be best to just ask. I'd much appreciate any ideas.
Try using this code:
jQuery(function(){
$('#yourFormName').on('submit', function (e) { //on submit function
e.preventDefault();
$.ajax({
type: 'post', //method POST
url: 'create-style.php', //URL of page where to pass values
data: $('#yourFormName').serialize(), //seriallize is passing all inputs values of form
success: function(){
console.log("success");
},
});
}
});
I have been staring at this problem for the past 2 hours and can't seem to fathom it, even after validating that everything loads correctly when scouring the console.
I basically have two sliders on my page which will eventually populate results in a table, every time I change my slider I send an array of two values to my AJAX script:
function update_results(values)
{
$.ajax({
type: "GET",
url: "./app/core/commands/update_results.php",
data: { query : values },
cache: false,
success: function(data) {
// eventually some success callback
}
});
}
The browser successfully finds update_results.php but it does not perform the logic on the page ( I assume it has found the page as the 404 error does not appear in my console. )
At this point in time the script is extremely bare-bones as I'm obviously trying to establish communication between both files:
<?php
$vals = $_GET['values'];
echo $vals;
In this case $vals is never echoed to the page, am I missing something in my AJAX? I know the values enter the function as alerted them out before attaching the PHP script.
Ajax Calls are suffering from Browser Cache. If your browser thinks, that he already knows the content of update.php, he will return the cached content, and not trigger the script. Therefore your
modified code might simply not get executed. (Therefore your insert query wasn't executed)
To ensure this is not happening in your case, it is always a good idea to pass a parameter (timestamp) to the script, so your browser thinks it's another outcome:
function update_results(values)
{
$.ajax({
type: "GET",
url: "./app/core/commands/update_results.php?random_parameter=" + (new Date().getTime());
data: { query : values },
cache: false,
success: function(data) {
// eventually some success callback
}
});
}
This will ensure that - at least - the browser cache is refreshed once per second for update_results.php, no matter what browser cache-settings or server-side cache advices are telling.
when Ajax is done, the success callback is triggered and the output of you php script is saved in data.
you can handle the data like this:
$.ajax({
type: "GET",
url: "./app/core/commands/update_results.php",
data: { query : values },
cache: false,
dataType: "text",
success: function(data) {
document.write( data )
}
});
PHP, running at server, is unaware of what happening at the front-end browser and it simply respond to ajax request as any other normal http request. So the failure of SQL query has nothing to do with javascript, which only responsible for sending ajax request and receiving and handling the response. I guess there's some errors in your php script.
I have found many threads regarding this issue, but unfortunately I couldn't get it running. Problem is I don't know much about JQuery.
I am trying to make an Ajax call using JQuery in order to fetch multiple records from a mysql database. I have the following function :
function updateWebpage ()
{
$.ajax({
url: './sale/api.php', //the script to call to get data
data: "", //you can insert url argumnets here to pass to api.php
//for example "id=5&parent=6"
dataType: 'json', //data format
success: function(rows) //on recieve of reply
{
for (var i in rows)
{
var row = rows[i];
var username = row[0];
var stateId = row[1];
$('#output').append("<b>id: </b>"+username+"<b> stateId: </b>"+stateId)
.append("<hr />");
}
}
});
};
My api.php is executing a mysql query with something like this:
$array = retrieveUsersInfo('%'); //fetch result
echo json_encode($array);
My main issue, is how to debug an issue like this? Since ajax is calling asynchronously another file, I cannot view any errors. From my firefox debugger, I can see that the $.ajax function is entered, but success is not.
Thanks in advance.
a couple things to try.
hit the api url directly in a browser (not through ajax) and make sure it returns the valid response.
add an error: function(err){} to your jquery ajax call. this method will get called if there is something other than a 200 response back from the server.
I use Chrome's developer tools more than firefox/firebug. It has a Network tab in it that shows me all the communication between the client and the server. You should see a call out to your api in that tab.
just off hand, i think you need to make sure the mime-type is set to text/json in your php file.
Sorry for maybe incorrect title for the topic, but this is the best that I came up with.
So, I'm building admin panel for a website.
I have a page, and in some part of the page, i'd like to refresh it and load another form.
let's say add a schedule, and somewhere down on the page I'd like to have this form displayed as soon as the link is clicked.
when a user saves it, I'd like that form to disappear and and in stead of that to have a list displaying all of the schedules.
I don't want to use frames - I'm not a supporter of frames. The panel is built using PHP.
Maybe this might be achived with Ajax? If yes -> How? any link to good example or tutorial.
yes this will be solved with ajax.
Here is a code example when the page is supposed to refresh
$('#button').click(function() {
$.ajax({
url: 'path/to/script.php',
type: 'post',
dataType: 'html', // depends on what you want to return, json, xml, html?
// we'll say html for this example
data: formData, // if you are passing data to your php script, needed with a post request
success: function(data, textStatus, jqXHR) {
console.log(data); // the console will tell use if we're returning data
$('#update-menu').html(data); // update the element with the returned data
},
error: function(textStatus, errorThrown, jqXHR) {
console.log(errorThrown); // the console will tell us if there are any problems
}
}); //end ajax
return false; // prevent default button behavior
}); // end click
jQuery Ajax
http://api.jquery.com/jQuery.ajax/
Script explained.
1 - User clicks the button.
2 - Click function initiates an XHR call to the server.
3 - The url is the php script that will process the data we are sending based on the values posted.
4 - The type is a POST request, which needs data to return data.
5 - The dataType in this case will be html.
6 - The data that we are sending to the script will probably be a serialization of the form element that is assigned to the variable formData.
7 - If the XHR returns 200, then log in the console the returned data so we know what we are working with. Then place that data as html inside the selected element (#update-menu).
8 - If there is an error have the console log the error for us.
9 - Return false to prevent default behavior.
10 - All done.