Each table (table1 & table2) has its own DATETIME field.
I'm trying to catch id's of the two tables and order them by their DATETIME field.
Example:
Table 1 Table 2
------------ -------------
id | datetime1 id | table1id | datetime2
------------------------ -----------------------
1 | 2014-09-21 20:31:26 1 | 2 | 2014-09-21 20:31:29
2 | 2014-09-21 20:31:27 2 | 3 | 2014-09-21 20:31:30
3 | 2014-09-21 20:31:28
Table 3
------------
id | user
------------------------
2 | phil
3 | nathalie
My output isn't ordered properly with this query:
SELECT *
FROM (
SELECT
1 AS selection,
table1.id, table1.datetime1,
table2.datetime2
table3.user
FROM Table1
LEFT OUTER JOIN table2
ON table1.id = table2.table1id
LEFT OUTER JOIN table3
ON table1.id = table3.id
UNION ALL
SELECT
2 AS selection,
table1.id, table1.datetime1,
table2.datetime2
table3.user
FROM Table1
INNER JOIN table2
ON table1.id = table2.table1id
INNER JOIN table3
ON table1.id = table3.id
) AS query
ORDER BY table1.datetime1 DESC, table2.datetime2 DESC
Desired data:
from table 2 id: 2, 1,
from table 1 id: 3, 2, 1
So: 2, 1, 3, 2, 1
////EDIT
To people who could be struggling with long and complex MySQL request, please try it in PhpmyAdmin! It will tell you the error!
////EDIT
What you really need to do is to consider your schema more carefully. Consider naming the date time columns the same and then running a query like this - http://sqlfiddle.com/#!2/a3b4c/7/0
SELECT selection, id, datetimefoo, user FROM (
SELECT
1 AS selection,
table1.id, table1.datetimefoo,
table3.user
FROM table1
LEFT OUTER JOIN table2
ON table1.id = table2.table1id
LEFT OUTER JOIN table3
ON table1.id = table3.id
UNION
SELECT
2 AS selection,
table1.id, table1.datetimefoo,
table3.user
FROM table1
INNER JOIN table2
ON table1.id = table2.table1id
INNER JOIN table3
ON table1.id = table3.id
) AS T2
ORDER BY datetimefoo DESC
In the SQL fiddle this produces the results closer to what you're looking for. I am still not sure why you need the INNER JOINS on the second query though - there is nothing that you're doing here whcih requires them.
Here is another method that does not require a changing of the column names, but requires an alias for the sortable columns - http://sqlfiddle.com/#!2/ec4bc/3/0
SELECT * FROM (
SELECT
1 AS selection,
table1.id, table1.datetimefoo AS sort_date, -- alias on first table's date
table2.datetimebar,
table3.user
FROM table1
LEFT OUTER JOIN table2
ON table1.id = table2.table1id
LEFT OUTER JOIN table3
ON table1.id = table3.id
UNION
SELECT
2 AS selection,
table1.id, table1.datetimefoo,
table2.datetimebar AS sort_date, -- alias on second table's date
table3.user
FROM table1
INNER JOIN table2
ON table1.id = table2.table1id
INNER JOIN table3
ON table1.id = table3.id
) AS T2
ORDER BY sort_date DESC
I believe you are over-complicating a rather straight-forward task:
SELECT *
FROM (
SELECT 1 AS selection, table1.id as id, table1.datetime1 as date FROM Table1
UNION ALL
SELECT 2 AS selection, table2.id as id, table2.datetime2 as date FROM Table2
) AS query
ORDER BY date DESC
Related
I would like to add some kind of "tolerance" to the following query. That means, that I can specify a value which expresses how many of the four (sub) selects return rows > 0. So if this value is 2, I only want to join these two tables. Is there a way to realize that?
SELECT distinct(user_id) FROM
(SELECT user_id FROM table1 WHERE ...) as t1
INNER JOIN
(SELECT user_id FROM table1 WHERE ...) as t2
ON t1.user_id=t2.user_id
INNER JOIN
(SELECT user_id FROM table1 WHERE ...) as t3
ON t1.user_id=t3.user_id
INNER JOIN
(SELECT user_id FROM table1 WHERE ...) as t4
ON t1.user_id=t4.user_id
EDIT:
Possible results for each sub-query could be as follows:
t1 t2 t3 t4
0 0 0
1 1 1 1
2 2 2 2
3 3
If all these sub results are joined it would result in: 1,2.
If I add a tolerance factor of 1, I want my result to be 0,1,2 as only one "0" is missing. If the factor was 2, the result would be 0,1,2,3 because two "3" and one "0" are missing. I hope this makes it clearer.
If i had understood your problem, you can add a variable in your sub-select and filter after:
SELECT distinct(user_id) FROM
(SELECT user_id, 1 as table_from FROM table1 WHERE ...) as t1
INNER JOIN
(SELECT user_id, 2 as table_from FROM table1 WHERE ...) as t2
ON t1.user_id=t2.user_id
INNER JOIN
(SELECT user_id, 3 as table_from FROM table1 WHERE ...) as t3
ON t1.user_id=t3.user_id
INNER JOIN
(SELECT user_id, 4 as table_from FROM table1 WHERE ...) as t4
ON t1.user_id=t4.user_id
WHERE table_from <= 2;
The solution was to union all sub selects and count them like follows:
SELECT distinct(user_id), sum(t) as tolerance FROM (
SELECT user_id, 1 as t FROM table1 WHERE ... GROUP BY...
UNION ALL
SELECT user_id, 1 as t FROM table1 WHERE ... GROUP BY...
UNION ALL
SELECT user_id, 1 as t FROM table1 WHERE ... GROUP BY...
UNION ALL
SELECT user_id, 1 as t FROM table1 WHERE ... GROUP BY...
) as x GROUP BY ... HAVING tolerance <= 2
Then you can specify how many sub selects should return something (here: 2).
This question already has answers here:
SQL Inner-join with 3 tables?
(12 answers)
Closed 5 years ago.
I have a problem ...
In table1 I have an id, I have to compare that id in table2, then fetch the second id that is in table2 and compare it to table3 and get as a result a datum.
Example
TABLE1
ID NAME ECC...
1 Jhon
2 Frank
TABLE2
ID ID2 ECC..
1 4
2 8
TABLE3
ID NAME
4 Sea
8 Hello
If I look for id 1, the result must be Sea
If I look for id 2 the result must be Hello
Thanks!
SELECT Table3.NAME
FROM Table1
INNER JOIN Table2
ON Table1.ID = Table2.ID
INNER JOIN Table3
ON Table3.ID = Table2.ID2
WHERE Table1.ID = 1 -- Your Search here
You should use joins.
Your query will look like :
SELECT t3.name
FROM table3 t3
LEFT JOIN table2 t2 ON t3.id = t2.id2
LEFT JOIN table1 t1 ON t2.id2 = t1.id
WHERE t1.id = <your_number>
select Table2.Id,Table3.Name from Table1 inner join Table2 on Table2.ID2 = Table3.Id
Query:
SELECT a.name As Name FROM table3 a JOIN
(SELECT b.id2 AS id FROM table1 a JOIN table2 b ON a.id = b.id)b
ON a.id = b.id where b.id = <your id number (1,2) Anything>
Should be something like this:
select table3.name as name3
from table3
where table3.ID = table2.ID2
and table2.ID = table1.ID
and table1.ID = <YOURNUMBERHERE>
Table 1 : Main_Family_Member
ID | Name
1 | Mahesh
2 | Rahul
3 | Jay
Table 2 : Family_Members
ID | MainMember | Name
1 | 1 | 'Arun'
2 | 1 | 'Nitin'
3 | 2 | 'Pratik'
Want Result :
Name
Mahesh
Arun
Nitin
Rahul
Pratik
You can achieve this by doing a UNION ALL of the two tables along with proper ordering. Note that it is necessary to union the two tables joined, because we need to know whether a main family member has any members. In case he does not have any member, your sample output implies that you don't want to display that main family member at all.
SELECT t.Name
FROM
(
SELECT DISTINCT t1.ID, t1.Name, 0 AS position
FROM
(
SELECT t1.ID, t1.Name
FROM Main_Family_Member t1
INNER JOIN Family_Members t2
ON t1.ID = t2.MainMember
WHERE t2.ID IS NOT NULL
) t1
UNION ALL
SELECT t2.ID, t2.Name, 1 AS position
FROM
(
SELECT t2.MainMember AS ID, t2.Name
FROM Main_Family_Member t1
INNER JOIN Family_Members t2
ON t1.ID = t2.MainMember
WHERE t2.ID IS NOT NULL
) t2
ORDER BY ID, position, Name
) t
Demo here:
SQLFiddle
SELECT Main_Family_Member.Name, Family_Members.Name
FROM Main_Family_Member
INNER JOIN Family_Members
ON Main_Family_Member.ID = Main_Family_Member.MainMember;
SELECT Main_Family_Member.Name, Family_Members.Name
FROM Main_Family_Member
INNER JOIN Family_Members
ON Main_Family_Member.ID = Main_Family_Member.MainMember;
You will need to perform a INNER JOIN on the two tables. This would return all the rows in the first table that meet the conditions plus all rows on the second table that join with the first table on the unique fields.
SELECT Main_Family_Member.Name , Family_Members.Name FROM Main_Family_Member INNER JOIN Family_Members ON Main_Family_Member.ID = Family_Members.MainMember WHERE Main_Family_Member.ID = 1 OR Main_Family_Member.ID = 2
SELECT Main_Family_Member.Name,Family_Members.Name FROM Main_Family_Member
INNER JOIN Family_Members ON Main_Family_Member.ID=Family_Members.MainMember
I have 5 tables that I need to connect to get the necessary data.
Table1
id | number
1 | 1
2 | 5
Table 2
id | number | user_id
1 | 1 | 9
2 | 5 | 8
Table 3
id | name |
8 | john |
9 | jane |
Table 4
id | email
6 | johndoe#example.com
Table 5
id | table4_id | table3_id
1 | 6 | 8
Table 1 is my main table and I want to add the name and email from table 3 and 4 respectively to my select query of table 1, but in order to do so, I would need to use table 2 and 5 to connect them as there is no direct relationship between table 1 and table 3 and 4. I only know how to join 3 tables and not 5 tables and it seems confusing to me on how to proceed with this.
I followed the link here to join Table 1,2 and 3. But I don't know how to proceed with table 4 and 5.
This is the query I tried:
SELECT table1.number, table2.number, table2.user_id, table3.id, table3.name,
table4.id, table4.email, table5.table4_id, table3_id
FROM table1
LEFT JOIN table2
INNER JOIN table3
//this query will work if I don't include this 2 inner joins
INNER JOIN table4
INNER JOIN table5
ON table3.id = table5.table3_id
ON table5.table4_id = table4.id
//
ON table2.user_id= table3.id
ON table2.number = table1.number;
ERROR: (if included the inner join for table 4 and 5)
Error Code: 1064. You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'ON table2.user_id= table3.id
The right Syntax is select .. from .. join .. on .. join ..on ....
SELECT table1.number, table2.number, table2.user_id, table3.id, table3.name, table4.id, table4.email, table5.table4_id, table3_id
FROM table1
LEFT JOIN table2 ON table2.number = table1.number
INNER JOIN table3 ON table2.user_id= table3.id
INNER JOIN table5 ON table3.id = table5.table3_id
INNER JOIN table4 ON table5.table4_id = table4.id
Try with the below structure. I made it from the structure you given in question
select t1.number, t2.number, t2.user_id, t3.id, t3.name,t4.id, t4.email, t5.t4_id, t3_id
from table5 as t5
join table4 as t4 on t5.table4_id = t4.id
join table3 as t3 on t5.table3_id=t3.id
join table2 as t2 on t2.user_id = t3.id
join table1 as t1 on t2.number=t1.number
Try Below code. Hope this will work.
Select t3.name,t4.email,t1.number,t2.user_id
from table3 t3 JOIN table5 t5 ON t3.id=t5.table3_id
JOIN table4 t4 ON t4.id=t5.table4_id
JOIN table2 t2 ON t2.user_id=t3.id
JOIN table1 t1 ON t1.number=t2.number;
I have 2 tables as follows:
table1
ID Name Test
A011 John 1
A012 Lynda 1
A013 Micheal 1
A014 Jack 0
A021 Joe 1
A015 Paul 0
table2
ID Done
A011 1
A012 1
I want to select all rows from table1 that have an ID where the 3 first letters are equal to A01, and the test field is 1, and also the ID is not present in table2.
I tried this query:
SELECT a.* FROM table1 a LEFT JOIN table2 b ON a.ID = b.ID
WHERE a.test = 1 AND b.ID IS NULL
The result from that is 2 rows with ID A013 and A021. I tried to use LEFT(ID,3) to get the ID with A01, however, I couldn't achieve what I want.
How can I filter only the records where the ID starts with A01?
Try this, it will give you the desired result
SELECT t1.* FROM table1 t1 LEFT JOIN table2 t2 ON t1.userid = t2.userid WHERE LEFT(t1.userid , 3) LIKE '%A01%' AND t1.userid NOT IN (SELECT userid from table2)
SELECT * FROM table1
WHERE test = 1
AND ID LIKE "AO1%"
AND ID NOT IN (SELECT ID from table2)