if stamement not working against db query - php

Question

I am running the code below but can't get the if statement to work. I want to be able to remove the div if there is no content and if there is then to display it but at the moment it either removes it all if one db entry is empty instead of just removing the 1 empty row.
<?php
$con = new mysqli($DBServer, $DBUser, $DBPass, $DBName);
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
extract($_GET);
{ $result = mysqli_query($con,"SELECT * FROM links ORDER by id ");
while($row = mysqli_fetch_array($result)) {
if ($section=""){
echo"";
}
elseif ($section="a"){
echo"<div class=\"page-header\">" . $row['section'] . "\</div>";
}
echo "<div class=\"links-wrap\">
<div class=\"links-box\">
<div class=\"links-image\"><img src=\"images/links/" . $row['img1'] . "\"></div>
<div class=\"links-site-txt\">" . $row['link1'] . "</div>
<div class=\"links-desc\">" . $row['desc1'] . "</div>
</div>
<div class=\"spacer-left\"></div>
<div class=\"links-box\"></div>
<div class=\"spacer-left\"></div>
<div class=\"links-box\"></div>
</div>";}}
mysqli_close($con);
?>

Answer 1

<?php
$con = new mysqli($DBServer, $DBUser, $DBPass, $DBName);
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
extract($_GET);
{ $result = mysqli_query($con,"SELECT * FROM links ORDER by id ");
while($row = mysqli_fetch_array($result)) {
if ( $section == "" ){ //double equality for condition check
echo "";
}
else if ($section == "a" ){
echo"<div class=\"page-header\">" . $row['section'] . "\</div>";
}
echo "<div class=\"links-wrap\">
<div class=\"links-box\">
<div class=\"links-image\"><img src=\"images/links/" . $row['img1'] . "\"></div>
<div class=\"links-site-txt\">" . $row['link1'] . "</div>
<div class=\"links-desc\">" . $row['desc1'] . "</div>
</div>
<div class=\"spacer-left\"></div>
<div class=\"links-box\"></div>
<div class=\"spacer-left\"></div>
<div class=\"links-box\"></div>
</div>";}}
mysqli_close($con);
?>

Answer 2

To compare value by if or elseif == is required not =. = generally use to assign value to a variable. Change your codes like below.
$con = new mysqli($DBServer, $DBUser, $DBPass, $DBName);
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
extract($_GET);
$result = mysqli_query($con,"SELECT * FROM links ORDER by id ");
while($row = mysqli_fetch_array($result)) {
$section = $row['section'];
if ($section == ""){
echo "";
}
elseif ($section == "a"){
echo"<div class=\"page-header\">" . $row['section'] . "\</div>";
}
echo "<div class=\"links-wrap\">
<div class=\"links-box\">
<div class=\"links-image\"><img src=\"images/links/" . $row['img1'] . "\"></div>
<div class=\"links-site-txt\">" . $row['link1'] . "</div>
<div class=\"links-desc\">" . $row['desc1'] . "</div>
</div>
<div class=\"spacer-left\"></div>
<div class=\"links-box\"></div>
<div class=\"spacer-left\"></div>
<div class=\"links-box\"></div>
</div>";
}
mysqli_close($con);