I want to calculate EXACT past 30 days time period in php from now (for example 30 aug 14 23:06) to 30 days back (for example 1 aug 14 23:06). I wrote this where current datetime goes in $d1 and past 30 days datetime goes in $d2 but somehow i am not getting correct results. Any idea?
$url=$row["url"];
$pageid=getPageID($url);
$date=date('y-m-d g:i');
$d1=strtotime($date);
$d2=date(strtotime('today - 30 days'));
Thanks
The problem is likely caused by the malformed date() call. The first argument passed to date() should be the format (as shown in the Docs) and the second should be an optional timestamp.
Try this:
$d2 = date('c', strtotime('-30 days'));
PHPFiddle
As a short aside, the whole snippet can be simplified as follows:
$url = $row["url"];
$pageid = getPageID($url);
$date = date('y-m-d g:i');
$d1 = time();
$d2 = date('y-m-d g:i', strtotime('-30 days'));
You can also use the DateTime class's sub() method together with an DateInterval:
$now = new DateTime();
$back = $now->sub(DateInterval::createFromDateString('30 days'));
echo $back->format('y-m-d g:i');
if you would like to get out put as 2014-08-01 then try the below code. thanks
$date = '2014-08-30 23:06';
$new_date = date('Y-m-d G:i', strtotime($date.' - 29 days'));
echo "30 days back is " . $new_date;
From your brief description and example given, I believe that you want the date to be 30 days back and time to be the same as of now. The below code will serve this purpose. Thanks.
<?php
$date=date('y-m-d g:i');
$time=date('g:i');
echo "Todays date:" . $date. "<br>";
$d2 = date('y-m-d', strtotime('-30 days'));
echo "30 days back:" . $d2 . ' ' .$time;
?>
Try:
echo date("Y-m-d h:i:s",strtotime('-30 days'));
For more detail click here
Very simple two lines of code
$date = new DateTime();
echo $date->modify('-30 day')->format('y-m-d g:i');
I know you said with PHP, however, I can't imagine not getting the records from a DB. If you want to do so from the DB,use:
$sql='SELECT * FROM myTable WHERE date > CURRENT_DATE - INTERVAL 30 DAY';
$pdo->query($sql);
Very simple one lines of code:
echo (new DateTime())->modify('-30 day')->format('y-m-d g:i');
In the example below, it makes no sense if the variable $date is not
used anywhere else!
$date = new DateTime();
echo $date->modify('-30 day')->format('y-m-d g:i');
Sample answer is
$dateBack30Days=date('Y-m-d g:i', strtotime('-30 days'));
Related
i want to find out the date after days from the given time.
for example. we have date 29 may 2015
and i want to cqlculate the date after 2 days of 25 may 2015
$Timestamp = 1432857600 (unix time of 29-05-2015)
i have tried to do it with following code but it is not working
$TotalTimeStamp = strtotime('2 days', $TimeStamp);
Missed the + - strtotime('2 days', $TimeStamp); .
Add the + to + 2 days.
Use date & strtotime for this - You can try this -
echo date('d-m-Y',strtotime(' + 2 day', strtotime('2015-05-16')));
$Timestamp & $TimeStamp are not same(may be typo). For your code -
$Timestamp = strtotime(date('Y-m-d'));
$TotalTimeStamp = strtotime('+ 2 days', $Timestamp);
echo date('d-m-Y', $TotalTimeStamp);
Php does have a pretty OOP Api to deal with date and time.
This will create a \DateTime instance using as reference the 25 May 2015 and then you can call the modify method on that instance to add 2 days.
$date = new \DateTime('2015-05-25');
$date->modify('+2 day');
echo $date->format('Y-m-d');
You may find this resource useful:
http://code.tutsplus.com/tutorials/dates-and-time-the-oop-way--net-35395
You can also just add seconds to your timestamp if you have a timestamp ready:
$NewDateStamp = $Timestamp + (60*60*24 * 2);
In the above, sec * min * hours = day -- or 86400 seconds. * 2 = 2 days.
In PHP 5 you can also use D
<?php
$date = date_create('2015-05-16');
date_add($date, date_interval_create_from_date_string('2 days'));
echo date_format($date, 'Y-m-d');
?>
OR
<?php
$date = new DateTime('2015-05-16');
$date->add(new DateInterval('2 days'));
echo $date->format('Y-m-d') . "\n";
?>
I had gone through various stackoverflow solutions and other blogs but still it doesn't fix my problem.
Let's say that the date today is: 2013-12-28 and I want to get the date after 1 month and it is supposed to display 2014-01-28.
$date = date('o-m-d');
$final = date('o-m-d', strtotime("+1 month", $date));
echo $final;
Above is my code. It returns 02/01/1970.
I have also tried the mktime method but still it displays the 1970 output.
What am I doing wrong?
BTW. I am working this on a hosted server.
Thanks ahead. :)
Use DateTime function modify
$date = new DateTime( 'o-m-d' );
echo $date->modify( '+1 month' )->format('o-m-d');
If you want the current date +1 month use:
$final = date('o-m-d', strtotime("+1 month"));
Or with a given date:
$date = date('o-m-d');
$final = date('o-m-d', strtotime($date . " +1 month"));
echo $final;
If you want to use the second parameter of strtotime it has to be a timestamp.
Go the OOP way..
<?php
$date = new DateTime('2013-12-28');
$date->add(new DateInterval('P1M'));
echo $date->format('Y-m-d'); //prints 2014-01-28
I'm really stuck with adding X minutes to a datetime, after doing lots of google'ing and PHP manual reading, I don't seem to be getting anywhere.
The date time format I have is:
2011-11-17 05:05: year-month-day hour:minute
Minutes to add will just be a number between 0 and 59
I would like the output to be the same as the input format with the minutes added.
Could someone give me a working code example, as my attempts don't seem to be getting me anywhere?
$minutes_to_add = 5;
$time = new DateTime('2011-11-17 05:05');
$time->add(new DateInterval('PT' . $minutes_to_add . 'M'));
$stamp = $time->format('Y-m-d H:i');
The ISO 8601 standard for duration is a string in the form of P{y}Y{m1}M{d}DT{h}H{m2}M{s}S where the {*} parts are replaced by a number value indicating how long the duration is.
For example, P1Y2DT5S means 1 year, 2 days, and 5 seconds.
In the example above, we are providing PT5M (or 5 minutes) to the DateInterval constructor.
PHP's DateTime class has a useful modify method which takes in easy-to-understand text.
$dateTime = new DateTime('2011-11-17 05:05');
$dateTime->modify('+5 minutes');
You could also use string interpolation or concatenation to parameterize it:
$dateTime = new DateTime('2011-11-17 05:05');
$minutesToAdd = 5;
$dateTime->modify("+{$minutesToAdd} minutes");
$newtimestamp = strtotime('2011-11-17 05:05 + 16 minute');
echo date('Y-m-d H:i:s', $newtimestamp);
result is
2011-11-17 05:21:00
Live demo is here
If you are no familiar with strtotime yet, you better head to php.net to discover it's great power :-)
You can do this with native functions easily:
strtotime('+59 minutes', strtotime('2011-11-17 05:05'));
I'd recommend the DateTime class method though, just posted by Tim.
I don't know why the approach set as solution didn't work for me.
So I'm posting here what worked for me in hope it can help anybody:
$startTime = date("Y-m-d H:i:s");
//display the starting time
echo '> '.$startTime . "<br>";
//adding 2 minutes
$convertedTime = date('Y-m-d H:i:s', strtotime('+2 minutes', strtotime($startTime)));
//display the converted time
echo '> '.$convertedTime;
I thought this would help some when dealing with time zones too. My modified solution is based off of #Tim Cooper's solution, the correct answer above.
$minutes_to_add = 10;
$time = new DateTime();
**$time->setTimezone(new DateTimeZone('America/Toronto'));**
$time->add(new DateInterval('PT' . $minutes_to_add . 'M'));
$timestamp = $time->format("Y/m/d G:i:s");
The bold line, line 3, is the addition. I hope this helps some folks as well.
A bit of a late answer, but the method I would use is:
// Create a new \DateTime instance
$date = DateTime::createFromFormat('Y-m-d H:i:s', '2015-10-26 10:00:00');
// Modify the date
$date->modify('+5 minutes');
// Output
echo $date->format('Y-m-d H:i:s');
Or in PHP >= 5.4
echo (DateTime::createFromFormat('Y-m-d H:i:s', '2015-10-26 10:00:00'))->modify('+5 minutes')->format('Y-m-d H:i:s')
If you want to give a variable that contains the minutes.
Then I think this is a great way to achieve this.
$minutes = 10;
$maxAge = new DateTime('2011-11-17 05:05');
$maxAge->modify("+{$minutes} minutes");
Use strtotime("+5 minute", $date);
Example:
$date = "2017-06-16 08:40:00";
$date = strtotime($date);
$date = strtotime("+5 minute", $date);
echo date('Y-m-d H:i:s', $date);
As noted by Brad and Nemoden in their answers above, strtotime() is a great function. Personally, I found the standard DateTime Object to be overly complicated for many use cases. I just wanted to add 5 minutes to the current time, for example.
I wrote a function that returns a date as a string with some optional parameters:
1.) time:String | ex: "+5 minutes" (default = current time)
2.) format:String | ex: "Y-m-d H:i:s" (default = "Y-m-d H:i:s O")
Obviously, this is not a fully featured method. Just a quick and simple function for modifying/formatting the current date.
function get_date($time=null, $format='Y-m-d H:i:s O')
{
if(empty($time))return date($format);
return date($format, strtotime($time));
}
// Example #1: Return current date in default format
$date = get_date();
// Example #2: Add 5 minutes to the current date
$date = get_date("+5 minutes");
// Example #3: Subtract 30 days from the current date & format as 'Y-m-d H:i:s'
$date = get_date("-30 days", "Y-m-d H:i:s");
one line mysql datetime format
$mysql_date_time = (new DateTime())->modify('+15 minutes')->format("Y-m-d H:i:s");
One more example of a function to do this: (changing the time and interval formats however you like them according to this for function.date, and this for DateInterval):
(I've also written an alternate form of the below function.)
// Return adjusted time.
function addMinutesToTime( $dateTime, $plusMinutes ) {
$dateTime = DateTime::createFromFormat( 'Y-m-d H:i', $dateTime );
$dateTime->add( new DateInterval( 'PT' . ( (integer) $plusMinutes ) . 'M' ) );
$newTime = $dateTime->format( 'Y-m-d H:i' );
return $newTime;
}
$adjustedTime = addMinutesToTime( '2011-11-17 05:05', 59 );
echo '<h1>Adjusted Time: ' . $adjustedTime . '</h1>' . PHP_EOL . PHP_EOL;
Without using a variable:
$yourDate->modify("15 minutes");
echo $yourDate->format( "Y-m-d H:i");
With using a variable:
$interval= 15;
$yourDate->modify("+{$interval } minutes");
echo $yourDate->format( "Y-m-d H:i");
I have $adate; which contains:
Tue Jan 4 07:59:59 2011
I want to add to this date the following:
$duration=674165; // in seconds
Once the seconds are added I need the result back into date format.
I don't know what I'm doing, but I am getting odd results.
Note: both variables are dynamic. Now they are equal to the values given, but next query they will have different values.
If you are using php 5.3+ you can use a new way to do it.
<?php
$date = new DateTime();
echo $date->getTimestamp(). "<br>";
$date->add(new DateInterval('PT674165S')); // adds 674165 secs
echo $date->getTimestamp();
?>
Just use some nice PHP date/time functions:
$adate="Tue Jan 4 07:59:59 2011";
$duration=674165;
$dateinsec=strtotime($adate);
$newdate=$dateinsec+$duration;
echo date('D M H:i:s Y',$newdate);
Given the fact that $adate is a timestamp (if that's the case), you could do something like this:
$duration = 674165;
$result_date = strtotime(sprintf('+%d seconds', $duration), $adate);
echo date('Y-m-d H:i:s', $result_date);
// add 20 sec to now
$duration = 20;
echo date("Y-m-d H:i:s", strtotime("+$duration sec"));
Do this:
$seconds = 1;
$date_now = "2016-06-02 00:00:00";
echo date("Y-m-d H:i:s", (strtotime(date($date_now)) + $seconds));
$current_time_zone = 150;
date("Y-m-d H:i:s",strtotime(date("Y-m-d H:i:s"))+$current_time_zone);
I made this example for a timezone, but if you change some parts it may help you out:
$seconds_to_add = 30;
$time = new DateTime();
$time->setTimezone(new DateTimeZone('Europe/London'));
$time2 = $time->format("Y/m/d G:i:s");
$time->add(new DateInterval('PT' . $seconds_to_add . 'S'));
$timestamp = $time->format("Y/m/d G:i:s");
echo $timestamp;
echo '========';
echo $time2;
Result:
2018/06/17 3:16:23========2018/06/17 3:15:53
It would be easier with DateTime::modify
(new DateTime($str))->modify("+$duration seconds"); //$str is the date in string
I have trouble with strtotime() to resolve my problem of add dynamic data/time value in the current time
This was my solution:
$expires = 3600; //my dynamic time variable (static representation here)
$date = date_create(date('Y-m-d H:i:s')); //create a date/time variable (with the specified format - create your format, see (1))
echo date_format($date, 'Y-m-d H:i:s')."<br/>"; //shows the date/time variable without add seconds/time
date_add($date, date_interval_create_from_date_string($expires.' seconds')); //add dynamic quantity of seconds to data/time variable
echo date_format($date, 'Y-m-d H:i:s'); //shows the new data/time value
font: https://secure.php.net/manual/en/datetime.add.php (consult Object Oriented style too, the Elzo Valugi solution)
(1) https://secure.php.net/manual/en/function.date.php
Given a time, how can I find the time one month ago.
strtotime( '-1 month', $timestamp );
http://php.net/manual/en/function.strtotime.php
In php you can use strtotime("-1 month"). Check out the documentation here: http://ca3.php.net/strtotime
We can achieve same by using PHP's modern date handling. This will require PHP 5.2 or better.
// say its "2015-11-17 03:27:22"
$dtTm = new DateTime('-1 MONTH', new DateTimeZone('America/Los_Angeles')); // first argument uses strtotime parsing
echo $dtTm->format('Y-m-d H:i:s'); // "2015-10-17 03:27:22"
Hope this adds some more info for this question.
<?php
$date = new DateTime("18-July-2008 16:30:30");
echo $date->format("d-m-Y H:i:s").'<br />';
date_sub($date, new DateInterval("P1M"));
echo '<br />'.$date->format("d-m-Y").' : 1 Month';
?>
PHP 5.2=<
$date = new DateTime(); // Return Datetime object for current time
$date->modify('-1 month'); // Modify to deduct a month (Also can use '+1 day', '-2 day', ..etc)
echo $date->format('Y-m-d'); // To set the format
Ref: http://php.net/manual/en/datetime.modify.php
This code is for getting 1 month before not 30 days
$date = "2016-03-31";
$days = date("t", strtotime($date));
echo date("Y-m-d", strtotime( "-$days days", strtotime($date) ));
These answers were driving me nuts. You can't subtract 31 days and have a sane result without skipping short months.
I'm presuming you only care about the month, not the day of the month, for a case like filtering/grouping things by year and month.
I do something like this:
$current_ym = date('ym',strtotime("-15 days",$ts));