php mysql select something and get columns from other tables - php

Question

I'm using prepared statements and I need to "select" other table, apart from these two, to get data but I get this:
Fatal error: Call to a member function bind_param() on a non-object in C:\xampp\htdocs\views\user\referral.php on line 16
If I add in SELECT table1.* , table.* , "theothertable.*"
$stmt = $mysqli->prepare("SELECT friends.*, rc_usuario.* // or just *
FROM friends
INNER JOIN rc_usuario ON rc_usuario.id = friends.friendID
WHERE friends.userID = ?");
$stmt->bind_param('s', $connectedUserID);
This is working fine, I get what i need, but I also need to get data from another table and I can't make other select because i need it all in a while to print all the data together.
The question is, can I SELECT something like that from 2 tables and also get data from other table/s?
Thank YOU!
EDIT: Add the new statement:
if ($stmt = $mysqli->prepare("SELECT friends.*, members.*, account_type.*
FROM friends
INNER JOIN members ON members.id = friends.friendID
INNER JOIN account_type ON account_type.name = members.acc_type
WHERE friends.userID = ? AND members.acc_type = ?")) {
$stmt->bind_param('is', $connectedUserID, $connectedAcc_type);
$stmt->execute();
} else echo $mysqli->error;

Answer 1

You can join more tables by using another INNER JOIN, like as follows;
INNER JOIN rc_usuario ON rc_usuario.id = friends.friendID
INNER JOIN rc_another ON rc_another.col = friends.coljoin
Just make sure you select all the columns you want in the joined table.
It might also help to run your prepare statement in an if, like this;
if($stmt = $mysqli->prepare("SELECT ...")) { // ... where the rest of your query is
$stmt->bind_param('s', $connectedUserID);
$stmt->execute();
}
else {
echo $mysqli->error;
}
which will give you an idea of any problems with the SQL syntax.
Hope this helps.