How view image from database by using php - php

Question

I am using localhost. I insert image in database blob. I am trying for show image. But I am fail. Image does not show. Database have three field id,name,image. Trying this code.
uimage.php
<?php
mysql_connect("localhost","root","");
mysql_select_db("task_database");
$image=mysql_query("SELECT * FROM image WHERE id=1");
$image=mysql_fetch_assoc($image);
$image=$image['image'];
header("Content-type: image/jpeg");
echo $image;
?>
and using this code in index.php page:
echo "Image Uploaded.<p />Your image:<p /><img src=uimage.php>";
But image did not show. Please help me.
My Full Code here: http://codepad.org/hJ8qucml

Answer 1

The easiest type of handling images in PHP-based websites is to save the images with the its id as name in a separated folder and just saving the id in database!
i really recommend you this type of working with images!

Answer 2

These are quick examples and you should validate any data being passed that is being used in a query. Check out Mysqli.
Using inline base64 encoding:
<?php
mysql_connect("localhost","root","");
mysql_select_db("task_database");
$result=mysql_query("SELECT name, myimg FROM image WHERE id=1");
$image=mysql_fetch_row($result);
$imagesrc=$image[1];
echo '<img src="data:image/jpeg;base64,'.base64_encode($imagesrc).'"/>';
Using PHP file to call the image:
<img src="image.php?id=<?php echo $id; ?>" />
image.php
<?php
mysql_connect("localhost","root","");
mysql_select_db("task_database");
$result=mysql_query("SELECT name, myimg FROM image WHERE id=1");
$image=mysql_fetch_row($result);
$imagesrc=$image[1];
header('Content-Type: image/jpeg');
echo $imagesrc;
?>