PHP: Systems path to actual URL - php

Question

Before i make my question I wanna say that I have tried every related post I found from stackoverflow such as PHP - Convert File system path to URL and nothing worked for me, meaning I did not get the Url I was looking for.
I need a
function PathToUrl($path)
{
...
}
which returns the actual Url of the $path
Example usage: echo PathToUrl('../songs'); should output http://www.mywebsite.com/files/morefiles/songs.
Note: The problem with the functions i found on stackoverflow is that they dont work with path that contains ../ for example on echo PathToUrl('../songs'); i would get something similar to http://www.mywebsite.com/files/morefiles/../songs which is not what i am looking for.

Answer 1

Here you go, I made this function and it works perfectly:
function getPath($path)
{
$url = "http".(!empty($_SERVER['HTTPS'])?"s":"").
"://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
$dirs = explode('/', trim(preg_replace('/\/+/', '/', $path), '/'));
foreach ($dirs as $key => $value)
if (empty($value)) unset($dirs[$key]);
$parsedUrl = parse_url($url);
$pathUrl = explode('/', trim($parsedUrl['path'], '/'));
foreach ($pathUrl as $key => $value)
if (empty($value)) unset($pathUrl[$key]);
$count = count($pathUrl);
foreach ($dirs as $key => $dir)
if ($dir === '..')
if ($count > 0)
array_pop($pathUrl);
else
throw new Exception('Wrong Path');
else if ($dir !== '.')
if (preg_match('/^(\w|\d|\.| |_|-)+$/', $dir)) {
$pathUrl[] = $dir;
++$count;
}
else
throw new Exception('Not Allowed Char');
return $parsedUrl['scheme'].'://'.$parsedUrl['host'].'/'.implode('/', $pathUrl);
}
Example:
Let's say your current location is http://www.mywebsite.com/files/morefiles/movies,
echo getPath('../songs');
OUTPUT
http://www.mywebsite.com/files/morefiles/songs
echo getPath('./songs/whatever');
OUTPUT
http://www.mywebsite.com/files/morefiles/movies/songs/whatever
echo getPath('../../../../../../');
In this case it will throw an exception.
NOTE
I use this regex '/^(\w|\d|\.| |_|-)+$/' to check the path directories which mean that only digit, word characters, '.', '-', '_' and ' ' are allowed. An exception will be trown for others characters.
The path .///path will be corrected by this function.
USEFUL
explode
implode
array_pop
parse_url
trim
preg_match
preg_replace

Answer 2

I see an answer was already posted, however I will post my solution which allows for direct specification of the URL :
echo up('http://www.google.ca/mypage/losethisfolder/',1);
function up($url, $howmany=1) {
$p = explode('/', rtrim($url, '/'));
if($howmany < count($p)) {
$popoff = 0;
while($popoff < $howmany) {
array_pop($p);
$popoff++;
}
}
return rtrim(implode('/', $p), '/') . '/';
}
Following is a much more elegant solution for virtual paths :
$path = '/foo/../../bar/../something/../results/in/skipthis/../this/';
echo virtualpath($path);
function virtualpath($path = null) {
$loopcount = 0;
$vpath = $path;
if(is_null($vpath)) { $vpath = parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH); }
$vpath = rtrim($vpath,'/') . '/';
while(strpos($vpath,'../') !== false ) {
if(substr($vpath,0,4) == '/../') { $vpath = '/'. substr($vpath,4); }
$vpath = preg_replace('/(\/[\w\d\s\ \-\.]+?\/\.\.\/)/', '/', $vpath );
}
return $vpath;
}