PHP Multi Dimensional Array Sorting - php

Question

Edit : I need it to do only in Array Sort, As i am using procedure and sending it into json,
Here is my Table Structure,
SQL Fiddle
I want to display as
alpha london
alpha newyork
beta delhi
beta sydney
I mean, the second coloumn (name) should be in Ascending Order and the third coloumn (place) should be in Descending Order.
How i want is
alpha london
alpha newyowk
beta delhi
beta sydney
The Name should be in Asc Order and then to the right, the Place should be in Desc Order
What i have tried so far is
How can i do this ??
<?php
include ('conn.php');
$sql="SELECT * FROM test";
$result=mysql_query($sql);
$rows=mysql_fetch_array($result);
while($rows=mysql_fetch_array($result))
{
foreach($result as $k=>$v)
{
echo $k;
}
}
?>
It displays the result as Invalid argument supplied to for each. What is the mistake i am doing and how can achieve my output

Answer 1

To fix the sorting, just add ORDER BY name, place
Then there's several more issues preventing this from working:
You shouldn't call mysql_fetch_array outside the loop (this would discard the first row, alpha london in your example).
You need to iterate over $rows, not $result (this is where the "invalid argument" error is coming from).
You're not echoing the value; only the key. So you wouldn't be displaying the name and place at all; only the words "name" and "place".
You might want to do something like this to fix these:
<?php
include('conn.php');
$sql = "SELECT * FROM test ORDER BY name, place";
$result = mysql_query($sql);
while ($rows = mysql_fetch_array($result)) {
foreach ($rows as $k => $v) {
echo "$k is $v. ";
}
echo "<br/>";
}
?>

Answer 2

So why don't you do an order in your query itself like
SELECT * FROM test order by name;

Answer 3

You can do this only modifying query.
Use this query:
SELECT * FROM test ORDER BY name ASC, place DESC

Answer 4

For your error, you are using wrong variable as foreach.
Replace this -
foreach($result as $k=>$v)
{
echo $k;
}
with this -
foreach($rows as $k=>$v)
{
echo $k;
}
Buy why are using foreach inside while loop. You can get your values like -
while($rows = mysql_fetch_array($result)) {
echo $rows['name'].' '.$rows['place'].'<br/>';
}
and don't use mysql_* function. Use instead mysqli_*
And for your expected output, try using following query -
SELECT * FROM `test` order by name asc, place desc

Answer 5

This is the kind of thing you can fix using array_multisort.
Try the below example (which I have not tested yet, but ought to work)
<?php
include ('conn.php');
$sql="SELECT * FROM test";
$result=mysql_query($sql);
$totals = array();
$row = array();
$places = array();
while($row=mysql_fetch_array($result)){
$totals[] = $row
$names[] = $row['name'];
$places[] = $row['place'];
}
array_multisort( $names, SORT_ASC, $places, SORT_DESC, $totals );
// now you can use $totals, which is sorted as you want
print_r( $totals );