json get largest number - php

I get this JSON after running query of particular customer sale history.
$output=
[
{
"customerID": 52970,
"sale": [
{
"item": "pencil",
}
],
"saleNumber": "25",
},
{
"customerID": 52970,
"sale": [
{
"item": "book",
}
],
"saleNumber": "26",
},
{
"customerID": 52970,
"sale": [
{
"item": "pen",
}
],
"saleNumber": "27",
}
]
when it comes to retrieving data such as customerID, I json decode($obj = json_decode($output)) and get the customerID as $ID = $obj->{'customerID'};
How to get the maximum saleNumber from this JSON

You could simply loop through the JSON and compare it. E.g.
$max = 0;
for($i = 0; $i < count($obj); $i++)
{
if((int)$obj[$i]->{"saleNumber"} > (int)$max)
$max = (int)$obj[$i]->{"saleNumber"};
}
// The max value should be in $max
EDIT
Also if saleNumber is the last element in the object, you shouldn't have a ','

Related

Array for subseries on highcharts Drilldown

I'm having some problems generating graphs with drilldown in Highcharts.
I'm using Highcharts to render a pie with drilldown series.
I need to transform this output json
Drilldownseries = [
{
"name": "LAZIO",
"data": [["ROMA", 28]],
"id": "LAZIO"
},
{
"name": "LAZIO",
"data": [["FROSINONE", 218]],
"id": "LAZIO"
},
{
"name": "LAZIO",
"data": [["LATINA", 212]],
"id": "LAZIO"
},
{
"name": "TOSCANA",
"data": [["FIRENZE", 2]],
"id": "TOSCANA"
},
{
"name": "TOSCANA",
"data": [["LIVORNO", 5]],
"id": "TOSCANA"
},
{
"name": "TOSCANA",
"data": [["PISA", 9]],
"id": "TOSCANA"
}
];
to
Drilldownseries = [
{
"name": "LAZIO",
"data": [["ROMA", 28], ["FROSINONE", 218], ["LATINA", 212]],
"id": "LAZIO"
},
{
"name": "TOSCANA",
"data": [["FIRENZE", 2], ["LIVORNO", 5], ["PISA", 9]],
"id": "TOSCANA"
}
];
This is the part of query that populates the array:
...
if($res3)
{
$i = 0;
while ($row = mysqli_fetch_array($res3, MYSQLI_ASSOC))
{
$row3[$i]["name"] = $row["name"];
$row3[$i]["data"] = [[$row["subname"],$row["data"]]];
$row3[$i]["id"] = $row["id"];
$i++;
};
$row3 = json_encode($row3,JSON_NUMERIC_CHECK);
};
I'd prefer to extract the array with php well formed, but should be the same tranform the json.
PHP 7.2
Highcharts 6.1.1
for benefit of all, this is my solution. Code refined should be appreciated :)
First removed square brackets in code below
$row3[$i]["data"] = [$row["subname"],$row["data"]];
then create the new array so
$repl = array();
$i = 0;
foreach ($row3 as $value) {
if (!isset($repl[$i]['id'])) {
$repl[$i]['id'] = $value['id'];
$repl[$i]['name'] = $value['name'];
$repl[$i]['data'] = [$value['data']];
} elseif (($repl[$i]['id']) <>$value['id']) {
$i++;
$repl[$i]['id'] = $value['id'];
$repl[$i]['name'] = $value['name'];
$repl[$i]['data'] = [$value['data']];
} else {
array_push($repl[$i]['data'], $value['data']);
}
}
$resultx = json_encode($repl,JSON_NUMERIC_CHECK);
thanks

create tree view like json from existing combined array

I have one combined array of order and its items combined into one array but i am trying to create json structure like order then its items list like wise.
$combinedarray[]=array('orderid'=>1,'partycode'=>10,"item"=>'abc',"price"=>250);
$combinedarray[]=array('orderid'=>1,'partycode'=>10,"item"=>'xyz',"price"=>250);
$combinedarray[]=array('orderid'=>2,'partycode'=>20,"item"=>'pqr',"price"=>250);
$combinedarray[]=array('orderid'=>2,'partycode'=>20,"item"=>'lmn',"price"=>250);
Output should be like
[
"0":[
{
"OrderNo": "1",
"partycode": "10",
"OrderDetails": [
{
"Item": "abc",
"price": 250
},
{
"Item": "xyz",
"price": 250
}
]
}
],
"1":[
{
"OrderNo": "2",
"partycode": "20",
"OrderDetails": [
{
"Item": "pqr",
"price": 250
},
{
"Item": "lmn",
"price": 250
}
]
}
]
]
This is What i Tried
$mainarray = array();
$orderarray = array();
$orderitemarray = array();
if (count(combinedarray) > 0) {
foreach (combinedarray as $obj) {
$orderarray[] = array("orderid" => $obj->orderid);
$orderitemarray[] = array("Item" => $obj->Item, "price" => $obj->price);
}
}
$mainarray[] = array_unique($orderarray);
$mainarray['OrderDetails'] = $orderitemarray;
echo json_encode($mainarray);
$mainarray = array();
foreach ($combinedarray as $x) {
$id = $x['orderid'];
unset($x['orderid']);
if (! isset($mainarray[$id])) {
$mainarray[$id]['OrderNo'] = $id;
}
$mainarray[$id]["OrderDetails"][] = $x;
}
// Now $mainarray has indexes equal to OrderNo. To count it from zero, use array_values
echo json_encode(array_values($mainarray), JSON_PRETTY_PRINT);
demo
By your given array
$combinedarray[]=array('orderid'=>1,'partycode'=>10,"item"=>'abc',"price"=>250);
$combinedarray[]=array('orderid'=>1,'partycode'=>10,"item"=>'xyz',"price"=>250);
$combinedarray[]=array('orderid'=>2,'partycode'=>20,"item"=>'pqr',"price"=>250);
$combinedarray[]=array('orderid'=>2,'partycode'=>20,"item"=>'lmn',"price"=>250);
Here is my solution for this
$new = array();
foreach($combinedarray as $r){
$new[$r['orderid']]['orderid'] = $r['orderid'];
$new[$r['orderid']]['partycode'] = $r['partycode'];
$new[$r['orderid']][] = array("item"=>$r['item'],"price"=>$r['price']);
}
$json = json_encode($new);
echo '<pre>';print_r($new);
echo $json;

How to merge MySQL query result with JSON format

Hi i am trying to merge output of MySQL result in JSON format but i confused how i can do this so guys i need your helps please tell me how i can do this work thank you.
SQL:
$result = $db->sql_query("SELECT a.*,i.member_id,i.members_seo_name
FROM ".TBL_IPB_USER." i
LEFT JOIN ".TBL_IPB_LA." a
ON a.member_id=i.member_id
WHERE i.".$column." = '".$val."' AND a.game = '".$game."'");
while( $dbarray = $db->sql_fetchrow($result) ){
$arr[] = $dbarray;
}
return ($arr);
The normal result and output with JSON format for my query is:
{
"status": 200,
"result": [
{
"member_id": "1",
"member_name": "maxdom",
"ip_address": "177.68.246.162",
"session_onlineplay": "1",
"sid": "IR63374a32d1424b9288c5f2a5ce161d",
"xuid": "0110000100000001",
"serialnumber": "9923806a06b7f700a6ef607099cb71c6",
"game": "PlusMW3",
"members_seo_name": "maxdom"
},
{
"member_id": "1",
"member_name": "maxdom",
"ip_address": "81.254.186.210",
"session_onlineplay": "1",
"sid": "IR3cd62da2f143e7b5c8f652d32ed314",
"xuid": "0110000100000001",
"serialnumber": "978e2b2668ec26e77c40c760f89c7b31",
"game": "PlusMW3",
"members_seo_name": "maxdom"
}
],
"handle": "checkUSER"
}
But i want to merge output and result like this one:
{
"status": 200,
"result": [
{
"member_id": "1",
"member_name": "maxdom",
"ip_address": [
"177.68.246.162",
"81.254.186.210"
],
"session_onlineplay": "1",
"sid": [
"IR63374a32d1424b9288c5f2a5ce161d",
"IR3cd62da2f143e7b5c8f652d32ed314"
],
"xuid": "0110000100000001",
"serialnumber": [
"9923806a06b7f700a6ef607099cb71c6",
"978e2b2668ec26e77c40c760f89c7b31"
],
"game": "PlusMW3",
"members_seo_name": "maxdom"
}
],
"handle": "checkUSER"
}
you better use php for your parser, prevent high load for database, this is sample code
$result = $db->sql_query("SELECT a.*,i.member_id,i.members_seo_name
FROM ".TBL_IPB_USER." i
LEFT JOIN ".TBL_IPB_LA." a
ON a.member_id=i.member_id
WHERE i.".$column." = '".$val."' AND a.game = '".$game."'");
$arr = array();
while( $dbarray = $db->sql_fetchrow($result) ){
$item = $dbarray;
$item['ip_address'] = array($item['ip_address']);
$item['sid'] = array($item['sid']);
$item['serialnumber'] = array($item['serialnumber']);
$index = $dbarray['member_id'];
if(isset($arr[$index]))
{
$arr[$index]['ip_address'] = array_merge($arr[$index]['ip_address'], $item['ip_address'];
$arr[$index]['sid'] = array_merge($arr[$index]['sid'], $item['sid'];
$arr[$index]['serialnumber'] = array_merge($arr[$index]['serialnumber'], $item['serialnumber']);
} else {
$arr[$index] = $item;
}
}
return array_values($arr);

How to place the json objects into array usin php?

this is my php code, to obtain json format data
if($status==1)
{
$post_id=$json_object['post_id'];
$get_postid=mysqli_query($con,"select * from User_Post where post_id='$post_id'");
if(mysqli_num_rows($get_postid)==0)
{
//For failure status if session id is wrong.
http_response_code(500);
echo json_encode(array("error_code"=>"500","error_message"=>"Sorry, post id does not exists."));
}
else
{
foreach($field_check as $values)
{
if($values=='id')
{
$row_array = array();
while ($row = $get_postid->fetch_array())
{
$row_array['id']=$row['post_id'];
$row_array['image_urls']=explode(',',$row['post_image_url']);
$storetag= explode(',',$row['Post_tagged_id']);
$has_liked="false";
$has_commented="false";
}
}
elseif($values=='tagged_users')
{
while ($row = $get_postid->fetch_array())
{
$storetag= explode(',',$row['Post_tagged_id']);
$has_liked="false";
$has_commented="false";
}
for($i=0;$i<count($storetag);$i++)
{
$user=mysqli_query($con,"select user_id, profile_image_url from Wheel_User where user_id='$storetag[$i]'");
if(mysqli_num_rows($user)==0)
{
//For failure status if session id is wrong.
http_response_code(500);
echo json_encode(array("error_code"=>"500","error_message"=>"Sorry, post id does not exists.".die()));
}
else
{
while ($row = $user->fetch_array())
{
$tagged_users[$i]['user_id']=$row['user_id'];
$array['user_id']=$tagged_users[$i]['user_id'];
$pro_image_url[$i]=$row['profile_image_url'];
$short_image_url[$i]=str_replace('_b','_t',$pro_image_url[$i]);
$short_image_url[$i]=str_replace('/images/','/thumbnails/',$short_image_url[$i]);
$array['short_image_url']=$short_image_url[$i];
}
}
array_push($row_array,$array);
}
}
}
array_push($json_response,$row_array);
echo str_replace('\/','/',json_encode($json_response));
}
}
It is returning the following objects
[
{
"id": "1111",
"image_urls": [
"https://docs.google.com/document/d/14kVqw9d2kzYIEClN-SVp2Co2mlglM9F-8HIy0ggTZ3g/edit",
"http://stackoverflow.com/questions/21762150/how-do-i-insert-data-from-a-json-array-into-mysql-database",
"https://drive.google.com/?authuser=0#my-drive",
"https://drive.google.com/?tab=mo&authuser=0#shared-with-me"
],
"0": {
"user_id": "111",
"short_image_url": "chrome://restclient/content/thumbnails/restclient_t.jpg"
},
"1": {
"user_id": "321",
"short_image_url": "chrome://restclient/thumbnails/restclient_t.jpg"
},
"2": {
"user_id": "1234",
"short_image_url": "http://54.169.40.195/wheel/wheel/service/testing/chetan/audio/c71dfe45421b2864476a0bde257f0a57e72084783ce859e26595599670904907.mp3"
}
}
]
but i want to assign name to that array like this
[
{
"id": "1111",
"image_urls": [
"https://docs.google.com/document/d/14kVqw9d2kzYIEClN-SVp2Co2mlglM9F-8HIy0ggTZ3g/edit",
"http://stackoverflow.com/questions/21762150/how-do-i-insert-data-from-a-json-array-into-mysql-database",
"https://drive.google.com/?authuser=0#my-drive",
"https://drive.google.com/?tab=mo&authuser=0#shared-with-me"
],
"tagged_users":[
"0": {
"user_id": "111",
"short_image_url": "chrome://restclient/content/thumbnails/restclient_t.jpg"
},
"1": {
"user_id": "321",
"short_image_url": "chrome://restclient/thumbnails/restclient_t.jpg"
},
"2": {
"user_id": "1234",
"short_image_url": "http://54.169.40.195/wheel/wheel/service/testing/chetan/audio/c71dfe45421b2864476a0bde257f0a57e72084783ce859e26595599670904907.mp3"
}
]
}
i don't know where i have to add this array name. Please help me solve this.
I can't assign the array name like this because $row_array also contains other data
echo str_replace('\/','/',json_encode(array("tagged_user"=>$json_response));
On second to last line this should be what you wanted:
array_push($json_response,array("tagged_users" => $row_array));
Edited to remove second part.
Try with -
array_push($row_array['tagged_users'],$array);
Or define it like -
$row_array['tagged_users'] = array();
Then all the values will be as you want.

Get total number of name field from JSON within PHP

Rather new to using json with php, bit of a last resort having searched over the net quite a bit already. I have this example ison file below, which I wish to be able to echo the total number of 'name:' fields within it so eg. 4 in the example below.
Question: How would I go about doing this?
[
{
"age": "22",
"name": "Dave"
},
{
"age": "21",
"name": "Alan"
},
{
"age": "19",
"name": "Luke"
},
{
"age": "30",
"name": "Nina"
}
]
If there will always be a name in each array then just:
echo count(json_decode($json, true));
If name may or not be present in each array then:
PHP >= 5.5.0:
echo count(array_column(json_decode($json, true), 'name'));
PHP < 5.5.0:
$count = 0;
foreach(json_decode($json, true) as $k => $v) {
isset($v['name']) ? $count++ : $count;
}
echo $count;

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