MySQL show all rows and sum at the end - php

Question

I've read through about 20 different answers regarding this question, but either I'm mis-understanding the answers, or its just not clicking. Here is my situation:
I have a table that lists ingredients for a recipe. Columns in the table are: ingredient_id, ingredient_title, ingredient_oz, ingredient_grams, ingredient_lbs (pounds), etc.
I want to list each ingredient, then after all ingredients have been listed, add a final row that sums up all the oz, grams, lbs, etc. Below is an example of the output I am trying to achieve.
Example:
INGREDIENT TITLE OZ GRAMS LBS
ingredient1 4 6 3
ingredient2 1 2 4
ingredient3 9 4 4
TOTAL 14 12 11
My first thought was simply using SUM() AS in the SQL
SELECT ingredient_title, ingredient_oz, ingredient_lbs, ingredient_grams, SUM(ingredient_oz) as oz_sum, SUM(ingredient_lbs) as lbs_sum, SUM(ingredient_grams) as grams_sum FROM ingredients
And here is the code on my page:
<!-- Beginning of table is here -->
<?php
while ($ingredientRow = $ingredients->fetch_assoc()) { ?>
<tr>
<td><?php echo $ingredientRow["ingredient_title"]; ?></td>
<td><?php echo $ingredientRow["ingredient_oz"]; ?></td>
<td><?php echo $ingredientRow["ingredient_lbs"]; ?></td>
<td><?php echo $ingredientRow["ingredient_grams"]; ?></td>
</tr>
<?php } ?>
</tbody>
<tfoot>
<tr>
<td>TOTALS</td>
<td><?php echo $ingredientRow["oz_sum"]; ?></td>
<td><?php echo $ingredientRow["lbs_sum"]; ?></td>
<td><?php echo $ingredientRow["grams_sum"]; ?></td>
</tr>
</tfoot>
</table>
<?php }?>
However all that does is return the first row (ingredient 1), and doesn't return the remaining rows or the sum. Then as I continued to read about this, I saw a low of people discussing using "group by" as well. So then I tried:
SELECT ingredient_title, ingredient_oz, ingredient_lbs, ingredient_grams, SUM(ingredient_oz) as oz_sum, SUM(ingredient_lbs) as lbs_sum, SUM(ingredient_grams) as grams_sum FROM ingredients GROUP BY ingredient_title
That returns all the rows, but again doesn't return a sum. Am I grouping by the wrong field? Do I need to group each of the fields I'm trying to sum?

Answer 1

When you run a query, you will get the data back that you ask for, so basically if you run a query to return all the rows individually - you will get those back, without the total. If on the other hand you run a query to get only the sum/totals, you won't get the individual rows of data.
There are two ways to get what you want. One is done via a query, one is done via PHP itself.
You can write a union query to get the individual rows of data, then return the sums, something like this:
SELECT
ingredient_title,
ingredient_oz,
ingredient_lbs,
ingredient_grams
FROM
ingredients
union all
SELECT
ingredient_title,
SUM(ingredient_oz) as oz_sum,
SUM(ingredient_lbs) as lbs_sum,
SUM(ingredient_grams) as grams_sum
FROM
ingredients
Which will return both.
Or you can write a quick snippet of PHP code to do the addition for you in your code based on the first part of the query:
<?php
$sql="SELECT
ingredient_title,
ingredient_oz,
ingredient_lbs,
ingredient_grams
FROM
ingredients";
//Execute query:
while($result)
{
echo $result['ingredient_title'];
echo $result['ingredient_oz'];
// etc etc. Format as needed...
$ingOz+=$result['ingredient_oz'];
$ingLbs+=$result['ingredient_lbs'];
$ingGrams+=$result['ingredient_grams'];
}
// And now the totals:
echo $ingOz;
echo $ingLbs;
// etc etc.
?>
I would personally probably use the second approach - you don't need to make the database run the query twice just to get the results - and you are already getting all the individual rows of data, therefore you may as well simply keep a simple running total in a variable to be displayed as needed.

Answer 2

Don't be afraid to run 2 separate SQL queries, because:
Grouping (for sum) works differently
Also code logic will more readable and decoupled
$query = "
SELECT
ingredient_title,
ingredient_oz,
ingredient_lbs,
ingredient_grams
FROM ingredients
";
$ingredients = $db->query($query)->fetch_all();
$query = "
SELECT
SUM(ingredient_oz) as oz_sum,
SUM(ingredient_lbs) as lbs_sum,
SUM(ingredient_grams) as grams_sum
FROM ingredients
";
$ingredientSummary = $db->query($query)->fetch_assoc();
<!-- Beginning of table is here -->
<?php
foreach ($ingredients as $ingredientRow) ?>
<tr>
<td><?php echo $ingredientRow["ingredient_title"]; ?></td>
<td><?php echo $ingredientRow["ingredient_oz"]; ?></td>
<td><?php echo $ingredientRow["ingredient_lbs"]; ?></td>
<td><?php echo $ingredientRow["ingredient_grams"]; ?></td>
</tr>
<?php } ?>
</tbody>
<tfoot>
<tr>
<td>TOTALS</td>
<td><?php echo $ingredientSummary["oz_sum"]; ?></td>
<td><?php echo $ingredientSummary["lbs_sum"]; ?></td>
<td><?php echo $ingredientSummary["grams_sum"]; ?></td>
</tr>
</tfoot>
</table>
<?php }?>

Answer 3

I think you should make it a separate query when selecting the sum. Does it make sense that it can get the sum of each row when the sum is of all the rows? By grouping you cause the SUM to sum each group, and every ingredient is a marked as a group.

Answer 4

its little late, but its easy with a roll back at the end of query
SELECT ingredient_title, ingredient_oz, ingredient_lbs, ingredient_grams
FROM ingredients
WITH ROLL BACK
here some examples from other site
https://www.mysqltutorial.org/mysql-rollup/