Dynamic Drop Down Menu and submenu php mysql - php

Question

I have a menu that needs to be created dynamically from the database.
need to have menu and submenu
for example (wht i want):
<ul class="dropdown">
<li>Link 1 </li>
<li>Link 2 </li>
<li>Link 3 </li>
<li>Link 4
<ul class="sub_menu">
<li>Link 4 - 1</li>
<li>Link 4 - 2</li>
<li>Link 4 - 3</li>
</ul>
</li>
<li>Link 5</li>
<li>Link 6 </li>
</ul>
below is the code i used for menu using function i want submenu as well
function listMenu(){
$ans = $this->select("cat_id,cat_name","s_category","1");
if(is_array($ans)){
foreach($ans as $val){
echo
"<li><a href=\"post-summary.php?cid=$val[0]\" >$val[1]</a></li>";
}
}
else{
echo "";
}
}
database is as follows:-
CREATE TABLE IF NOT EXISTS `s_category` (
`cat_id` int(11) NOT NULL AUTO_INCREMENT,
`cat_name` varchar(15) NOT NULL,
`cat_uid` int(2) NOT NULL,
`cat_time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`cat_parent` int(11) DEFAULT '0',
`cat_sort` int(11) DEFAULT NULL,
`cat_delete` int(1) DEFAULT '0',
PRIMARY KEY (`cat_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=13 ;

Answer 1

You need to have a column, let we name it parentId in the s_category table.
Example values in there:
catId,catName,parentId
1,Vehicles,null
2,Planes,null
3,Cars,1
4,Bicycles,1
So your structure will be like:
- Vehicles
- Cars
- Bicycles
- Planes
You'll need to get the data like this (to be considered as pseudocode):
$topLevelItems = (select catId, catName from s_category where parentId is null)
foreach($topLevelItems as $item) {
echo '$item["catName"]';
$subItems = (select catId, catName from s_category where parentId=$item['catId'])
foreach($subItems as $subItem) {
echo '$subItem["catName"]';
}
}
You need to re-write the SQL part to match your case. This will work if you have just one inner level, e.g. no sub-sub-menus. If you plan to use sub-sub-menus you'll need recursive function.

Answer 2

as far as menus are concerned storing the submenus as a comma seperated values in the database would come handy.
ie consider a table with id,menus,submenus(several submenus seperated by a comma).
function listMenu(){
$ans = $this->select("menus,submenus");
if(is_array($ans)){
foreach($ans as $val){
echo "<li><a href=\"post-summary.php?cid=$val[0]\" >$val[0]</a>"; //menus
$submenu = explode(",",$val[1]);
foreach($submenu as $values){
echo "<li><a href=\"post-summary.php?cid=$val[0]&proname=$values\" >$values</a></li>"; // submenus
}
echo "</li>";
}
}
}
try this
$con = db_connect();
$str = "select menus,submenus from your_tabel ";
$result = mysql_query($str,$con);
while($arr = mysql_fetch_array($result))
{
echo "<li><a href=\"post-summary.php?cid=$arr[0]\" >$arr [0]</a>"; //menus
$submenu = explode(",",$arr [1]);
//make sure you have several sub-menus else use a if condition here to avoid foreach error
foreach($submenu as $values){
echo "<li><a href=\"post-summary.php?cid=$arr[0]&proname=$values\" >$values</a></li>"; // submenus
}
echo "</li>";
}
this works fine for me just tested now
comment if working.
comment if not-working.

Answer 3

created your database and write function with code and change parameters
function getAllFrom($field, $table,$where = NULL, $and = NULL , $orderfield, $ordering = "DESC") {
global $con;
$getAll = $con->prepare("SELECT $field FROM $table where $where $and ORDER BY $orderfield $ordering");
$getAll->execute();
$all = $getAll->fetchAll();
return $all;}
<ul>
<?php
$allCats = getAllFrom("*", "categories", "parent = 0", "" , "cat_id", "ASC");
foreach ($allCats as $cat) { ?>
<li>
<?php
echo '<a href="categoreis.php?pagename=' . str_replace(' ', '-', $cat['name_cat']) . '&pageid=' . $cat["cat_id"] . '">
' . $cat['name_cat'] . '
</a>';
?>
<ul class="sub-menu[enter image description here][1]">
<?php
$catsub = $cat['cat_id'];
$SubCats = getAllFrom("*", "categories", "parent = {$catsub}", "" , "cat_id", "ASC");
foreach ($SubCats as $sub) { ?>
<li>
<?php
echo '<a href="categoreis.php?pagename=' . $sub['name_cat'] . '&pageid=' . $sub["cat_id"] . '">
' . $sub['name_cat'] . '
</a>';
?>
</li>
<?php }
?>
</ul>
</li>
<?php }
?>
</ul>