PHP MySQL How to skip displaying a field - php

Question

I have the table MYTABLE that contains the fields: ID, PASSWORD, COL1, COL2, COL3, DATE
I would like to fetch and display all records in an html table but skipping ID and PASSWORD fields...
I'm using the following code which isn't working:
$query = "SELECT * FROM MYTABLE WHERE 1";
$results = mysql_query($query, $conn) or die(mysql_error());
echo "<tr>";
while ($r = mysql_fetch_assoc($results)) {
foreach ($r as $item) {
// let's not display ID and password
if ($r == 'ID' || $r == 'PASSWORD') continue; // this is the line that I want to figure out
echo "<td>$item</td>";
} // end for loop
} // end while
unset($item);
echo "</tr>";
Obviously there's more than 1 way to do it, for example I can replace the foreach loop with a for loop:
for ($i=0;$i<=6;$i++) {
if ($i == 0 || $i == 1 ) continue;
echo "<td>$r[$i]</td>";
} // end for
This will skip ID and PASSWORD fields but I don't want to use it, because I'm running the code on more than one table (table name is fetched from html select tag) and these tables may not have the same number of fields/columns (but they will always have ID and PASSWORD).
I can also do it with SQL statement (I don't want to), but then I'll have to query into a temp, drop the ID,PASSWORD columns and then fetch from the temp table. (by the way is there a compelling reason as to why I SHOULD in fact do it with SQL rathen than PHP?)

Answer 1

foreach ($r as $k => $item) {
// let's not display ID and password
if ($k == 'ID' || $k == 'PASSWORD') continue;
echo "<td>$item</td>";
}
This meets exactly your request.
I hope this result now useful to you, and after that, you evolve from it.

Answer 2

I would suggest you do it this way:
$query = "SELECT COL1, COL2, COL3, DATE FROM MYTABLE WHERE 1";

Answer 3

Try this:
$query = "SELECT * FROM MYTABLE WHERE 1";
$results = mysql_query($query, $conn) or die(mysql_error());
echo "<tr>";
while ($r = mysql_fetch_assoc($results)) {
foreach ($r as $key => $item) {
// let's not display ID and password
if (!in_array($key, array('PASSWORD', 'ID'))) {
echo "<td>$item</td>";
}
} // end for loop
} // end while
echo "</tr>";

Answer 4

Let it easy..
<?php
$query = "SELECT COL1, COL2, COL3, DATE FROM MYTABLE WHERE ..whatever..";
$result = mysql_query($query);
if ($result) {
while ($row = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>".$row["COL1"]."</td>";
echo "<td>".$row["COL2"]."</td>";
echo "<td>".$row["COL3"]."</td>";
echo "<td>".$row["DATA"]."</td>";
echo "<tr>";
}
}
?>