Loop through database query - php

Question

I would like to show the results of one database table by the use of a variable fetched from another database table like this:
mysql_select_db($database_Connection, $Connection);
$query_Recordset_bids = "SELECT * FROM bids WHERE bidder = '$userName'";
$Recordset_bids = mysql_query($query_Recordset_bids, $Connection) or die(mysql_error());
while ($row_Recordset_bids = mysql_fetch_array($Recordset_bids)) {
$totalRows_Recordset_bids = mysql_num_rows($Recordset_bids);
mysql_select_db($database_Connection, $Connection);
$query_Recordset_jobs = "SELECT * FROM jobs WHERE userID = '".$row_Recordset_bids['jobID']."'";
$Recordset_jobs = mysql_query($query_Recordset_jobs, $Connection) or die(mysql_error());
$row_Recordset_jobs = mysql_fetch_assoc($Recordset_jobs);
$totalRows_Recordset_jobs = mysql_num_rows($Recordset_jobs);
}
And then I want the output showed in the following table:
<?php if($totalRows_Recordset_jobs == 0)
echo "You have never submitted a job offer!";
else {
?>
<table width="440" border="0" cellpadding="1" cellspacing="1" id="tablejobs">
<tr>
<th width="40" bgcolor="#779BDC" scope="col">ID</th>
<th width="90" bgcolor="#779BDC" scope="col">Destination</th>
<th width="85" bgcolor="#779BDC" scope="col">Cargo</th>
<th width="85" bgcolor="#779BDC" scope="col">Due Date</th>
<th width="75" bgcolor="#779BDC" scope="col">Bid</th>
<th width="65" bgcolor="#779BDC" scope="col">Status</th>
</tr>
<?php do { ?>
<tr>
<td height="22" bgcolor="#798890" scope="col"> <?php echo $row_Recordset_jobs['userID']; ?></td>
<td bgcolor="#798890" scope="col"> <?php echo $row_Recordset_jobs['destination']; ?></td>
<td bgcolor="#798890" scope="col"> <?php echo $row_Recordset_jobs['cargo']; ?></td>
<td bgcolor="#798890" scope="col"> <?php echo $row_Recordset_jobs['due_date']; ?></td>
<td bgcolor="#798890" scope="col"> <?php echo $row_Recordset_jobs['bids']; ?> kr.</td>
<td bgcolor="#798890" scope="col"> <?php echo $row_Recordset_jobs['status']; ?></td>
</tr>
<?php } while ($row_Recordset_jobs = mysql_fetch_assoc($Recordset_jobs)); ?>
</table>
<?php
}
?>
But there is only one row shown in the table even though there are 2 or more results that match the select query.
So how do I loop through the first database table to get multiple matching variables (jobID) that I can use to my select statement to the second database table, which should show multiple results?

Answer 1

I suggest you to simply learn about joins. :)
You can also use a join on different databases aslong as both databases are available with the same connection/credentials.
I am not sure if I got you right that you have two databases for your tables.
If you have only one database its simple:
$query = 'SELECT *
FROM bids b
LEFT JOIN jobs j ON b.jobID = j.UserID
WHERE b.bidder = "$userName"';
Incase you have two databases use this and insert names of your two databases for <namedb1> and <namedb2>.
However, note that this is not the smartest thing to do because you cannot use any indizes, transactions, constraints or table-locks over different databases.
(As mentioned by Jay Blanchard in the comments)
$query = 'SELECT *
FROM <namedb1>.bids b
LEFT JOIN <namedb2>.jobs j ON b.jobID = j.UserID
WHERE b.bidder = "$userName"';
http://dev.mysql.com/doc/refman/5.1/en/join.html