PHP IF ELSE condition and Foreach - php

Question

I have a small issue trying to compare data from 3 arrays, one of them is the source and the other 2 are the conditions.
the scenario is the next:
$array1 = array('code' => '123', 'code' => '124', 'code' => '125', 'code' => '126', 'code' => '127');
$array2 = array(
array('code1' => '123', 'country' => 'US', 'listed' => '0'),
array('code1' => '124', 'country' => 'US', 'listed' => '1'),
array('code1' => '125', 'country' => 'US', 'listed' => '1')
);
$array3 = array(
array('code2' => '123', 'country' => 'US', 'listed' => '1'),
array('code2' => '126', 'country' => 'US', 'listed' => '0'),
array('code2' => '127', 'country' => 'US', 'listed' => '1')
);
$final = array_merge($array1,$array2,$array3);
foreach ($final as $f) {
if ($f['code'] == $f['code1']) {
if ($f['listed'] > 0) {
$finalListed = $f['listed'];
}
} elseif ($f['code'] == $f['code2']) {
if ($f['listed'] > 0) {
$finalListed = $f['listed'];
}
}
$newFinalArray = array(
'code' = $finalCode,
'listed' = $finalListed,
'country' = $finalCountry
);
}
So what i need is to check first if the code from $array1 exist in $array2 and if if the code from $array2 is listed if not check on $array3 and so on.
So if the code exist on $array2 and listed is 1 update database with this values if not check $array3 if exist and listed is 1 update with the values if not update the values from $array2
The idea is that $array2 is from 1 site and $array3 is from another, so, if is not in 1 is the second if are in both keek from $array2
The problem is that i cannot get it sort, i have tried array_combine but this combines only 2 arrays and the parameters need to be exactly.
With array merge i get the 3 arrays into one, then on foreach and on apply if conditions it say that the variable is undefined.

Answer 1

First of all I see a lots of issue in the way arrays are declared by you
Ex -
$array1 = array('code' = > '123', 'code' = > '124', 'code' = > '125', 'code' = > '126', 'code' = > '127');
is nothing but
$array1 = array('code' => '127'); //because of same index it will only consider the last value
However I have modified your arrays and tried to prepare a solution which might be useful for you. Check it once below.
<?php
$array1 = array('123', '124', '125', '126', '127');
$array2 = array(array('code' => '123', 'country' => 'US', 'listed' => '0'), array('code' => '124', 'country' => 'US', 'listed' => '1'), array('code' => '125', 'country' => 'US', 'listed' => '1'));
$array3 = array(array('code' => '123', 'country' => 'US', 'listed' => '1'), array('code' => '126', 'country' => 'US', 'listed' => '0'), array('code' => '127', 'country' => 'US', 'listed' => '1'));
function compareSitesAndUpdate($array1, $array2, $array3) {
foreach($array1 as $code) {
if(isCodeExistsInArray($code,$array2)) {
echo $code . ' is in array2 and listed <br />';
}
else { // ;( Not in Array2 check in Array3
echo $code . ' not listed in array2 - checking in array3 <br />';
if(isCodeExistsInArray($code,$array3)) {
echo $code . ' is in array3 and listed <br />';
}
else {
echo $code . ' not listed in array3 also - do whatever you want to do <br />';
}
}
}
}
//Note $earray is always expected to be in the format of $array2/$array3
//And key of $array2 and $array3 should always be 'code' - Not necessary to change the keys are they are two diff arrays
function isCodeExistsInArray($ecode, $earray) {
foreach($earray as $code_array) {
if($ecode == $code_array['code']) { //code match found - now check if it is listed
if($code_array['listed'] == 1) { //Got what we need - return TRUE and Break
return TRUE;
}
}
}
return FALSE; //any other case return False;
}
compareSitesAndUpdate($array1, $array2, $array3);
?>

Answer 2

Why don't you try something like this:
foreach($array1 as $key => $code){
if(in_array($code, $array2) {
echo 'Value is in the array! :D ';
}
else {
if(in_array($code, $array3) {
echo 'Value is in array3! :D';
}
}

Answer 3

Suppose that you have the same key for codes in both arrays: $array2 and $array3, i.e.:
$array1 = array(
'123',
'124',
'125',
'126',
'127'
);
$array2 = array(
array('code' => '123', 'country' => 'US', 'listed' => '0'),
array('code' => '124', 'country' => 'US', 'listed' => '1'),
array('code' => '125', 'country' => 'US', 'listed' => '1')
);
$array3 = array(
array('code' => '123', 'country' => 'US', 'listed' => '1'),
array('code' => '126', 'country' => 'US', 'listed' => '0'),
array('code' => '127', 'country' => 'US', 'listed' => '1')
);
Then:
$newFinalArray = array_filter(array_merge($array2, $array3), function($el){
if($el['listed'] > 0 && in_array($el['code'], $GLOBALS['array1'])) {
return true;
}
});