Can not store data in two tables - php

I am trying to store data in two tables, using two different queries.
one of them is working fine but other one is not saving anything . These two queries are part of full page script. The frist queries in both the cases are part of the scripts and working fine.
the 2nd queries are written by me to make another records of user clicks.
Table structure for actcontest .. table name is actcontest not act_contest, this was copy/paste mistake here:[corrected]
userid varchar(50)
type varchar(50)
points int(10)
date date
Case 1:
The working query:
$sql = $Db1->query('Insert into ptcwalllogs (userid, user_earned)
values ('.$credituser.','.$rate.')');
Problem with the query:
$sqlact = $Db1->query('Insert into actcontest (userid, type, points, date)
values ('$username','ptcwall',6,now())');
Case 2:
working query:
$Db1->query("INSERT INTO `likesasapaddon` (user_id, page_id,date)
VALUES('{$thismemberinfo[userid]}', '{$get['pageid']}',NOW())");
Problem with the query:
$Db1->query("INSERT INTO `actcontest` (userid, type, points, date)
VALUES ('$username','facebook',6,now())");
in both the cases I want to store values in same table.
Below is the script file for case 1:
This is postback from one the providers.
<?php
$date1 = date('Y-m-d');
include("config.php");
include("includes/mysql.php");
$Db1 = new DB_sql;
$Db1->connect($DBHost, $DBDatabase, $DBUser, $DBPassword);
$your_pwd = ""; /* Postback Password */
$vip=getenv('REMOTE_ADDR');
$sent_pw = $_GET['pwd'];
$credited = intval($_GET['c']);
$credituser = intval($_GET['usr']);
$rate = trim($_GET['r']);
$type = intval($_GET['t']);
$allowed_ip = array('72.52.253.202');//PTCWall's IPS.
if(in_array($vip, $allowed_ip) && $sent_pw == $your_pwd)
{
if($credited == '1')
{
if($type == '1')
{
$run = $Db1->query('UPDATE user SET balance=balance+'.$rate.' WHERE userid = '.$credituser);
// This line below is used to store clicks locally
$sql = $Db1->query('Insert into ptcwalllogs (userid, user_earned) values ('.$credituser.','.$rate.')');
$sqlact = $Db1->query("Insert into actcontest (userid, type, points, date)
values ('".mysqli_real_escape_string($username)."','ptcwall',6,now())");
// $sqlact = $Db1->query('Insert into actcontest (userid, type, points, date) values ("lorry","ptcwall",6,now())');
if($run)
{
exit('ok');
} else{
exit('issue');
}
}elseif($type == '2'){
$run = $Db1->query('UPDATE user SET points=points+'.$rate.' WHERE userid = '.$credituser);
if($run)
{
exit('ok');
} else{
exit('issue');
}
}
}elseif($credited == '2')
{
if($type == '1')
{
$run = $Db1->query('UPDATE user SET balance=balance-'.$rate.' WHERE userid = '.$credituser);
if($run)
{
exit('ok');
} else{
exit('issue');
}
}elseif($type == '2'){
$run = $Db1->query('UPDATE user SET points=points-'.$rate.' WHERE userid = '.$credituser);
if($run)
{
exit('ok');
} else{
exit('issue');
}
}
}
}
else{
die();
}
//FILE 03302014
?>
After the Var dump:
saved in separate file.
daata.php
<?php
$sqlact = $Db1->query("Insert into actcontest (userid, type, points, date)
values ('".mysqli_real_escape_string($username)."','ptcwall',6,now())");
var_dump($sqlact);
echo " success asdasdasdasdasdasdasdasdas " ;
?>
error:
Warning: mysqli_real_escape_string() expects exactly 2 parameters, 1 given in ./xxxx/daata.php on line 3
bool(true)
Kindly guide.

Warning: mysqli_real_escape_string() expects exactly 2 parameters, 1 given in ./xxxx/daata.php on line 3 bool(true)
This warning means that you need to pass your DB connection to it, that is the second parameter it is expecting.
('".mysqli_real_escape_string($Db1, $username)."','ptcwall',6,now())")
Consult the documentation:
http://php.net/manual/en/mysqli.real-escape-string.php
$sqlact = $Db1->query("Insert into act_contest (userid, type, points, date)
values ('".mysqli_real_escape_string($Db1, $username)."','ptcwall',6,now())");
$Db1->query("INSERT INTO `actcontest` (userid, type, points, date)
VALUES ('".mysqli_real_escape_string($Db1, $username)."','facebook',6,now())");
Also, make sure that all your columns do exist in your table.
Add:
die('There was an error running the query [' . $Db1->error . ']');
This will signal an error, should there be any.
I.e.:
if($run)
{
exit('ok');
} else{
die('There was an error running the query [' . $Db1->error . ']');
}
Follow that same method for all your queries.
It's also a good thing to add error reporting to the top of your file(s) which will help during production testing.
error_reporting(E_ALL);
ini_set('display_errors', 1);
should $username or any other variables be undefined.

Here are working queries:
$sqlact = $Db1->query("Insert into act_contest (userid, type, points, date)
values ('".mysqli_real_escape_string($username)."','ptcwall',6,now())");
$Db1->query("INSERT INTO `actcontest` (userid, type, points, date)
VALUES ('".mysqli_real_escape_string($username)."','facebook',6,now())");
NB: Always use mysqli_real_escape_string (or it equivalent) for strings in SQL query. Or your application will be hacked soon with SQL injection.

Are you sure of your table name "actcontest" ? In the first case, you put an underscore in it and not in the second one.
Are you also sure of this table schema : userid, type, points and date ? Maybe you made a little typo ?
If I were you, I'll first check all of that.

Related

Change an Insert statement to an update statement in PHP/MySQL

I'm making an Android app that connects to a database online and lets the user edit the database from the application, I'm new to PHP and MySql but from my research I think I should be using an UPDATE statement, I've written the code below to register new users on the site from a tutorial, but I'd like to change the INSERT statement to an UPDATE statement so that instead of registering a new user, the App updates existing data that I have entered in PHPMYADMIN, could someone show me how to do this? Also, if you require the code for the app mention it in the comments and I'll add it to the question, I don't want to post too much unneccessary code. Thanks in advance.
<?php
require "conn.php";
$patient_name = $_POST["patient_name"];
$check_in_date = $_POST["check_in_date"];
$room_number = $_POST["room_number"];
$bed_number = $_POST["bed_number"];
$notes = $_POST["notes"];
$mysql_qry = "insert into patients(patient_name, check_in_date, room_number, bed_number, notes) values ('$patient_name', '$check_in_date', '$room_number', '$bed_number', '$notes')";
if($conn->query($mysql_qry) === TRUE) {
echo "Insert successful";
}
else{
echo "Error: " . $mysql_qry . "<br>" . $conn->error;
}
$conn->close();
?>
EDIT
The fixed code is below, it now updates records already in the database rather than adding new data.
<?php
require "conn.php";
$patient_name = $_POST["patient_name"];
$check_in_date = $_POST["check_in_date"];
$room_number = $_POST["room_number"];
$bed_number = $_POST["bed_number"];
$notes = $_POST["notes"];
$mysql_qry = "UPDATE patients SET notes='$notes' WHERE patient_name='$patient_name'";
if($conn->query($mysql_qry) === TRUE) {
echo "Insert successful";
}
else{
echo "Error: " . $mysql_qry . "<br>" . $conn->error;
}
$conn->close();
?>
first of all this PHP code is vulnerable to sql injection you should, no need to update your code to use either mysqli prepared statement or PDO prepared statement
secondly the easiest way I know you accomplish your goal would make a unique constraint on some columns and then use a mysql feature ON DUPLICATE UPDATE
for this example I'll assume that the unique fields determining an update instead of an insert are patient_name, check_in_date, room_number, and bed_number (in case john smith was in the same room as john smith in seprate beds) the query to update the table would be like this
ALTER TABLE `patients` ADD UNIQUE `unique_index`(`patient_name`, `check_in_date`, `room_number`, `bed_number`);
so now to address the sql injection bit and the query, I'll update the example to use mysqli statement and will assume patient_name and notes are strings (varchar/nvarchar), room_number and bed_number are integers, and check_in_date is a date
Edit My original answer had a syntax error in the query and also passing variables to the prepared statement below is the updated answer
$mysqliConn = new mysqli("localhost", "my_user", "my_password", "mydatabase");
$stmt = $mysqliConn->prepare("insert into patients
(patient_name, check_in_date, room_number, bed_number, notes)
values (?, ?, ?, ?, ?)
ON DUPLICATE KEY UPDATE notes=values(notes)");
$patient_name = $_POST["patient_name"];
$check_in_date = $_POST["check_in_date"];
$room_number = $_POST["room_number"];
$bed_number = $_POST["bed_number"];
$notes = $_POST["notes"];
mysqli_stmt_bind_param($stmt, "sdiis",
$patient_name, $check_in_date, $room_number, $bed_number, $notes);
hope this helps
Edit
Regarding the unique key, a unique key means that all fields in the unique key have to be unique when combined so for the example above
if record 1 is
patient_name, check_in_date, room_number, bed_number, notes
'john smith', '3/1/2017' , 413 , 2 , 'patient is sick'
and record two is
'jane doe' , '3/1/2017' , 413 , 2 , 'patient has wound'
these two records will note be duplicates with the above constraint but if you do need to change the constraint you can do the following
DROP the Constraint
ALTER TABLE `patients` DROP INDEX `unique_index`;
Then recreate the constraint like this
ALTER TABLE `patients` ADD UNIQUE `unique_index`(`patient_name`, `check_in_date`, `room_number`);
also if you named your constraint something other than unique_index you can find the key_name by running the following
SHOW INDEX FROM `patients`;
the name will be in the key_name column
additionally you may want to alter the last line of the query to be this in your php if you change the unique constraint so you can change bed number
ON DUPLICATE KEY UPDATE bed_number=values(bed_number), notes=values(notes)
You can also use REPLACE INTO, then you don't have to change the SQL statement. Let MySQL do the work for you.
https://dev.mysql.com/doc/refman/5.7/en/replace.html
<?php
require "conn.php";
$patient_name = $_POST["patient_name"];
$check_in_date = $_POST["check_in_date"];
$room_number = $_POST["room_number"];
$bed_number = $_POST["bed_number"];
$notes = $_POST["notes"];
$mysql_qry = "REPLACE INTO patients(patient_name, check_in_date, room_number, bed_number, notes) VALUES ('$patient_name', '$check_in_date', '$room_number', '$bed_number', '$notes')";
if($conn->query($mysql_qry) === TRUE) {
echo "Insert successful";
}
else{
echo "Error: " . $mysql_qry . "<br>" . $conn->error;
}
$conn->close();
Also, you should really take a look at using PDO with prepared statements and parameters.
https://secure.php.net/manual/en/pdo.prepare.php
Actually I was looking for a small function that converts an INSERT MySQL query to an UPDATE query. So maybe other people were looking for the same and I think this is what the original poster was looking for aswell... I couldnt find any so I made this simple function which works for my needs, ofcourse you will have to make sure your original query is safe from MySQL injection.
It will convert
INSERT INTO aaa (bbb, ccc) VALUES ('111', '222')
to
UPDATE aaa SET ccc='222' WHERE bbb='111'
Use the 2nd variable ($iColumn) to identify the WHERE statement.
function convertInsertToUpdate($sQuery, $iColumn = 1) {
$sNewQuery = "";
$iPos = strpos($sQuery, ' (');
$sTmpTable = substr($sQuery, 0, $iPos);
$iPos = strpos($sTmpTable, 'INSERT INTO ');
$sTmpTable = substr($sTmpTable, $iPos+12);
$iPos = strpos($sQuery, ') VALUES (');
$sTmpValues = substr($sQuery, $iPos+10);
$iPos = strrpos($sTmpValues, ')');
$sTmpValues = substr($sTmpValues, 0, $iPos);
$iPos = strpos($sQuery, '(');
$sTmpColumns = substr($sQuery, $iPos+1);
$iPos = strpos($sTmpColumns, ') VALUES (');
$sTmpColumns = substr($sTmpColumns, 0, $iPos);
$aColumns = explode(', ', $sTmpColumns);
$aValues = explode(', ', $sTmpValues);
if (count($aColumns)>0 && count($aColumns) == count($aValues) && $iColumn < (count($aValues)+1)) {
$sNewQuery = "UPDATE ".$sTmpTable." SET";
$sTmpWhere = "";
$bNotFirst = false;
$iX = 0;
while ($iX<count($aColumns)) {
if ($iColumn == ($iX+1)) {
$sTmpWhere = " WHERE ". $aColumns[$iX]."=".$aValues[$iX];
$iX++;
continue;
}
if ($bNotFirst) {
$sNewQuery .= ",";
}
$sNewQuery .= " ".$aColumns[$iX]."=".$aValues[$iX];
$bNotFirst = true;
$iX++;
}
$sNewQuery .= $sTmpWhere;
}
return $sNewQuery;
}

Mysql INSERT and DELETE in a single statement with dependant on eachother

I have the following two queries. Second query is dependent on first one.
$query1 = mysql_query("Insert into table_one set ---- ");
if($query1)
{
$query2 = mysql_query("delete from table_two where condition---");
if($query2)
{
$message = "both queries executed successfully";
}
else
{
$del = mysql_query("delete record inserted by $query1");
}
}
Can we execute these two queries in a single statement so that both queries depend on each other.If INSERT query fail, DELETE query also fail it's execution as well as if DELETE query fail INSERTION in query first fail.
Thanks
If I good understand what you need, simply use transactions.
Run this query before your insertion:
mysql_query('begin');
And then, if everything went fine, commit the transaction:
mysql_query('commit');
In case of any failures, you may rollback every change you made:
mysql_query('rollback');
Note that in case of MySQL, the MyISAM engine does not support rollback in transactions, so use InnoDB.
Read more about transactions here: https://dev.mysql.com/doc/refman/5.0/en/commit.html
Example with your code:
<?PHP
mysql_query('begin'); //start transaction
$query1 = mysql_query("Insert into table_one set ---- ");
if($query1)
{
$query2 = mysql_query("delete from table_two where condition---");
if($query2)
{
mysql_query('commit'); //both queries went fine, so let's save your changes and end the transaction
$message = "both queries executed successfully";
}
else
{
mysql_query('rollback'); //query2 failed, so let's rollback changes made by query1 and end the transaction
}
}
else
mysql_query('rollback'); //query1 failed, so let's end the transaction
If query2 fails it doesn't check query1.
$query1 = mysql_query("Insert into table_one set ---- ");
$query2 = mysql_query("delete from table_two where condition---");
if( $query2 && $query1)
{
$message = "both queries executed successfully";
}
else if(!$query2)
{
$del = mysql_query("delete record inserted by $query1");
}
You can use transaction, if any query fails then call rollback, otherwise commit
I found a best solution.
Extending idea of #Luki i wrote the following code and it give me too much satisfied answer. First use the following function.
function multi_statement()
{
global $conn;
$total_args = func_get_args();
$args = implode($total_args,";");
$args = "begin;".$args.";commit;";
$number = 0;
if($conn->multi_query($args))
{
do
{
if ($conn->more_results())
{
$number++;
}
}
while($conn->next_result());
}
if($number < (count($total_args)+1))
{
$conn->query('rollback');
echo "Sorry..!!! Error found in Query no:".$number;
}
else
{
echo "All queries executed successfully";
}
}
Then I called the function with number of statements, all these statements are dependent on each other. In-case there is error in any query, no one query occur any changes in database.
$statement1 = "INSERT INTO `pic_gall`.`admin` (`admin_id`, `username`, `password`) VALUES (NULL, 'as1', 'as1')";
$statement2 = "INSERT INTO `pic_gall`.`admin` (`admin_id`, `username`, `password`) VALUES (NULL, 'as2', 'as2')";
$statement3 = "INSERT INTO `pic_gall`.`admin` (`admin_id`, `username`, `password`) VALUES (NULL, 'as3', 'as3')";
$statement4 = "INSERT INTO `pic_gall`.`admin` (`admin_id`, `username`, `password`) VALUES (NULL, 'as4', 'as4')";
$statement5 = "DELETE from user where user_id = '12'";
multi_statement($statement1,$statement2,$statement3,$statement4,$statement5);

Unable to insert into MySQL for select values

I have a web application in which students are divided into "batches".
I am trying to insert student for particular batch and the batch will be chosen by user by select option. After that student is added to the particular batch, he/she will be added to stdhold table. However, it is only inserting for the first selected value of select option.
<?php
function specialCOn() {
$connew = mysqli_connect("localhost","root","");
$db = mysqli_select_db($connew,'mcqs');
return($connew);
}
if (isset($_POST['add']))
{
$namestd=$_POST['std_name'];
$batchstd=$_POST['batch'];
$FNAME=$_POST['f_name'];
$query3 = "INSERT INTO `$batchstd` VALUES('','$namestd','$FNAME')";
$rsq3 = mysqli_query(specialCOn(),$query3);
mysqli_close(specialCOn());
$queryrollno = "select rollno from `$batchstd` order by rollno desc";
$rsqrollno = mysqli_query(specialCOn(),$querrollno);
$getrollno = mysqli_fetch_array($rsqrollno);
$rollnoto = $getrollno[0];
echo "<script>alert('$batchstd')</script>";
echo "<script>alert('$rollnoto')</script>";
mysqli_close(specialCOn());
//Problem is here
$querystdhold = "INSERT INTO stdhold VALUES ($rollnoto, '$namestd', '$FNAME', '$batchstd')";
$rsqhold = mysqli_query(specialCOn(),$querystdhold);
mysqli_close(specialCOn());
if ($rsq3&&$rsqhold)
{
echo "<script> alert('Student Added.');
window.location.assign('addstudent.php');
</script>";
//header('Location:addstudent.php');
}
else
{
echo "<script> alert('You Havenot added Student.');
window.location.assign('addstudent.php');</script>";
}
}
?>
Try use this :
$db = new mysqli("host","user","pw","database");
$stmt = $db->prepare("INSERT INTO ? (col1,col2,col3) VALUES('',?,?)");
$stmt->bind_param('sss', $_POST['batch'], $_POST['std_name'], $_POST['f_name']);
$stmt->execute();
For the detail example you need to read the #Amber Answer how to create secured prepared statement.
Hope this'll help you.
Try specifying the column names in your insert query:
INSERT INTO stdhold (col1, col2, col3, col4) VALUES ($rollnoto, '$namestd', '$FNAME', '$batchstd');
For reference see the MySQL Insert documentation.

Hard coded to Dynamic values

I have been given a task to convert the hardcoded fields into dynamic fields.I have changed it partially to dynamic
Let me explain you the situation ,
We have a lot of databases and each database has a table by name Surveys
By using the DESCRIBE statement we will retrieve the fields in the Surveys table regardless of the database .
I need to know the way where we can loop again and again till all the fields in the survey table appears.
In the below code I have left the for loop blank .
Please let me know the changes that neeeds to be done to get this working
I would really appreciate any kind of help
function insertIntoUserUploadFileds() {
$describe="DESCRIBE surveys";
$sql = "INSERT INTO `userUploadFields` (`fieldName`, `inUse`, `mandatory`, `type`, `mapTo`) VALUES";
$inUse="0";
$type="";
//for(){
if($field=='type'){
$type="N";
}elseif(($field=='fname') || ($field=='lname') || ($field=='phone')){
$inUse="1";
$type="T";
}elseif($field=='email'){
$inUse="1";
$type="E";
}
//$sql .= "('".$field."', '".$inUse."', '0', '
$result1 = mysql_query ($describe);
$result = mysql_query ($sql);
//}
}
$result1 = mysql_query ('DESCRIBE surveys');
//here is how you retieve all field and check
while($row = mysql_fetch_array($result1)) {
$sql = "INSERT INTO `userUploadFields` (`fieldName`, `inUse`, `mandatory`, `type`, `mapTo`) VALUES";
//here you can do if else to check the column name
if($row['field']=='type')
{
$type="N";
}
else if(($row['field']=='fname') || ($row['field']=='lname') || ($row['type']=='phone'))
{
$inUse="1";
$type="T";
}
else ($row['field']=='email')
{
$inUse="1"
$type="E";
}
//build your query
$sql .= "('".$field."', '".$inUse."', '0', '......)
//execute your complete query
$result = mysql_query ($sql);
}//end of while
Instead of using DESCRIBE, if you are trying to retrieve the default type of a particular column you might look into this. It describes how to break down the information from a particular table. Codex

INSERT INTO table1 values FROM table2 WHERE

I've looked around nothing seems to be working for me. I have a button when pushed it INSERTS data into 1 table-1, then it gets values from table-3 to put in table-2 where in they the ID is the same.
if ($movieTime != "") {
$query = "SELECT SchedID FROM tblCinemaSched WHERE TheaterID='$tid' AND CinemaID='$cid' AND MovieDate='$date' AND MovieTime='$movieTime'";
//echo "$query<br>";
$result=$conn->executeUpdate($query);
$numRows=$conn->numRows($result);
if ($numRows<=0) {
$query = "INSERT INTO tblCinemaSched SET TheaterID='$tid', CinemaID='$cid', MovieDate='$date', MovieTime='$movieTime', MovieID='$movieId', PriceAmt='$priceId', CrtBy='$username', CrtDate=NOW()";
//echo "$query<br>";
$result=$conn->executeUpdate($query);
//get seat defaults from tblCSeats
$query = "INSERT INTO tblSSeats SELECT TheaterID, CinemaID, '$date', '$movieTime', SeatID, RowNo, ColumnNo, Handicap, Status, LeftSeat, RightSeat, NULL, NULL,NULL,NULL,NULL,NULL,NULL,'$username',NOW() FROM tblCSeats WHERE TheaterID='$tid' AND CinemaID='$cid'";
//echo "$query<br>";
$result=$conn->executeUpdate($query);
$errorStr = "Succesfully added schedule.";
}
else {
$errorStr = "There's already an existing schedule for the specified time.";
}
You see tableCSeats has more than 1 row that has the same ID meaning I want to insert multiple data from tableCSeats to tableSSeats. tableSSeats is a has no data in it yet.
At a blind guess, it would seem that you are looking for INSERT ... SELECT statement.
check the return values of your queries. You always get "Succesfully added schedule." because you don't check if the queries were succesful. Ex:
if(!$result=$conn->executeUpdate($query)) {
die('error');
}
or something like that.

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