Check time changing automatic - php

There is a streaming channel which displays for 24 hours per day and I want to display that for certain hours of day in my website. I use a code as bellow:
$now = date('G',time());
$start = 13;
$end = 14;
if($now >= $start && $now <= $end){
echo "streaming video";
}
else{
echo "image";
}
It works when I do refresh/load page. But I want this program to check the time and do reactions without it is needed to do reload the page. So, when the time comes up to 14:00 the video will not being displayed anymore but the image instead of video and when the time comes to 13:00 to display video instead of image. Can be done with php or it is needed ajax or something else?
Waiting for some help.

Create a javascript function that performs an ajax call to a time function which can decide to set the stream or an image:
<div id="stream-content"></div>
setInterval(function() {
$.ajax({
url : "/gettime.php",
type: 'GET',
success: function(data){
//check time, if correct, set video to the div #stream-content otherwise, set an image as the content
}
});
}, 1000);

Related

Counter between 2 values with Daily Reset

I need help creating a counter that starts from 1 value (2000000) and ends at 2nd value (2500000), resets every day and does not restart upon page load.
I was able to get almost exactly what I want with javascript - but this restarts on page load/refresh. I imagine I need to write this in PHP, but I can't figure out how - any help/pointers would be awesome.
Here is the javascript example on JSfiddle and below:
var start = 200000001;
var end = 250000000;
var interval = 578;
var refreshIntervalId = setInterval(function(){
if(start <= end){
$("#start").text(start++);
}else{
stop();
}
},interval);
function stop(){
clearInterval(refreshIntervalId);
}
it's possible to solve you problem with ajax function and get the value from a database.
if you want use Cronjob and php for your probelm and dont work with database , use text file .
save your current number in a text file , i write a function for you a sample below :
function yourfunction($start,$end){
$perv = file_get_contents("num.txt");
if($perv <= $end){
$current = $perv++;
file_put_contents("num.txt","$current");
}
}

jquery countdown changes when user change its system time

i'm using jquery countdown with php. i have given an end date which is going to the countdown. my problem is lets suppose 1 hour left is showing in countdown but when a user change its system time the countdown changes. like if a user back his time 1 hour then the counter will display the 2 hours left. is there any way to get the server time for more accurate time not the user system time. please help.
how can i get server time not user system time?
below is my jquery code
if($(pluginsArray[6]).length){
$(pluginsArray[6]).each(function(){
var $this = $(this),
dateObj = $this.data();
var finalDate = new Date(dateObj.year, dateObj.month, dateObj.day, dateObj.hours, dateObj.minutes);
$this.countdown({
timezone: +4,
until : finalDate,
expiryText: '<div class="over">Closed.</div>',
onExpiry : function(){
setTimeout(function( ) { location.reload(); }, 5000);
},
format :'DHMS',
layout : '<b>{dn}</b> <span class="fs_medium d_inline_b m_right_5">days</span> <b>{hn}</b> <span class="fs_medium d_inline_b m_right_5">hrs</span> <b>{mn}</b> <span class="fs_medium d_inline_b m_right_5">min</span> <b>{sn}</b> <span class="fs_medium">sec</span>'
});
});
}
and here is what i did in php
<div class="countdown color_redc d_inline_m fs_large second_font lh_small f_xs_20" style="font-size:26px;" data-year="<?= $aDate[0] ?>" data-month="<?= ($aDate[1] - 1) ?>" data-day="<?= $aDate[2] ?>" data-hours="<?= $aDate[3] ?>" data-minutes="<?= $aDate[4] ?>"></div>
Solution without PHP
What you can do, without coding any server side is using a public API to get current time.
Found a similar topic on StackoverFlow : Free Rest API to get current time as string (timezone irrelevant)
TimezoneDb provides a free API: http://timezonedb.com/api
GenoNames also has a RESTful API available to get the current time for
a given location: http://www.geonames.org/export/ws-overview.html.
You can use Greenwich, UK if you'd like GMT.
GenoNames looks to be US only, TimezoneDb works you just need to register for a free public key.
Few people recommend timeapi.org but looks like they do not accept CROSS-DOMAIN request in Ajax, and the exemple they provide is no longer available.
Solution with PHP and jQuery Countdown configuration
Also you can ask jQuery CountDown to synchronyze with your server using serverSync option
$(selector).countdown({
until:liftoffTime, serverSync: serverTime});
function serverTime() {
var time = null;
$.ajax({url: 'http://myserver.com/serverTime.php',
async: false, dataType: 'text',
success: function(text) {
time = new Date(text);
}, error: function(http, message, exc) {
time = new Date();
}});
return time;
}
PHP file : serverTime.php
<?php
$now = new DateTime();
echo $now->format("M j, Y H:i:s O")."\n";
?>
BUT
Keep in mind your user will always be able to change your code and fake it ... so if you need to implement some security this is not enough and you will need to code some backend stuff.

change images in my webpage on a particular time interval in php

I created a database for storing the image path and actual image is store in the directory.
Then i want to set a time interval in hour for changing the image randomly inmy webpage(eg: 24 hrs is the time interval i given the image will be changed on every day 12:00) and if i give 12 hrs interval the image change happends in every 12 hrs in a day.
I already made a form to submiting the value for time interval. i have only time interval in hours.
How can be do this in PHP.?.I want to do this change in my server side.. i am new to php
Please give me an example code for doing this .
Thanks.
You can change setInterval(abc, 1000);1000 value as per your time.
and #divname is id of div in which you want to display the image
function abc() {
jQuery.ajax({
url:'random_image.php',
type:'POST',
data:'',
success:function(results){
jQuery("#divname").html(results);
}
});
}
abc();
setInterval(abc, 1000);
In random_image.php
$query="select * from imgtables ORDER BY RAND() LIMIT 1 ";
$q1= mysql_query($query,$sp);
if($q1==FALSE ){ die(mysql_error()); }
while($row = mysql_fetch_array($q1)){
$str="gallery/".$row['imgurl']; echo '<img src="'.$str.'" width=100px height=50px>'; }
}
mysql_close($sp);

show and hide based on server date and time

So here's what I'm trying to do - I have the following code:
<div id="on">
<p>We are: <span class="onair">ON AIR</span></p>
</div>
<div id="off">
<p>We are: <span class="offair">OFF AIR</span></p>
</div>
And what I'd like to do is "show" the "on" div on Tuesday's from 3pm to 4pm (server time), while simultaneously hiding the "off" div - and then switch that around for every other date/time.
?
If you use PHP you can do logic statements on the server-side to render the exact information you need instead of calculating it later on the client side.
(Client side solutions work too if you dont care about where the time is coming from)
(1) You can have the server render javascript for you that you can use in a script
//if you want the server's time you can do this:
<?php $timestamp = time(); ?>
//render variables in javascript instead of html
<?php
echo <<<EOD
<script>
var timestamp = ${timestamp}
//then later in your javascript process the timestamp logic to update the dom
</script>
EOD;
?>
(2) You can also have the server render a className in the body tag based on whether or not a condition is true or false. (This is my preferred method usually)
//onAirClass( min, max, timestamp ) returns className
//this function returns onair or offair class if the timestamp is in range
function onAirClass( timeMin, timeMax, timestamp ){
if( timestamp >= timeMin && timestamp <= timeMax ){
return 'onair';
}
return 'offair'
}
//using onAirClass( min, max, timestamp )
<?php $bodyClass = $bodyClass . ' ' . onAirClass( $timestamp ); ?>
<?php echo "<body class='${bodyClass}'>"; ?>
then in your styles you can have the elements you want to hide or show based on class inheritance from the body tag.
Check out the PHP time function to create new time strings, and do time calculations for your onAirClass() function
How to check the time between a given time range
UPDATED
Corrected PHP syntax errors
#maerics solution is OK, depending on what you want to do, just don't EVER do anything like this:
var timestamp = $('#server-timestamp').text();
Ultimately, there are many ways to do the same thing, but some things are more 'right' than others.
There are reasons to do some calculations on the client side vs the server side, and vice versa. As a newbie developer, just make sure that whatever method you use:
is simple
is efficient (doesnt do anything unnecessary or redundant)
falls in line with best practices
Actually this can be accomplished using just JavaScript without any server-side code, by using your timezone offset.
Here's a function you can use:
var onAir = function (day, start, end, timezone) {
var local, utc, show, days, onAir, startValues, endValues, startTime, endTime, startMinutes, endMinutes, showMinutes;
// by default, we are not on air
onAir = false;
// map day numbers to indexes
days = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Firday', 'Saturday'];
// convert start/end times to date objects
startValues = start.split(':');
endValues = end.split(':');
startTime = new Date();
endTime = new Date();
startTime.setHours(startValues[0], startValues[1]);
endTime.setHours(endValues[0], endValues[1]);
// add the hours minutes together to get total minutes
startMinutes = (startTime.getHours() * 60) + startTime.getMinutes();
endMinutes = (endTime.getHours() * 60) + endTime.getMinutes();
// get the current local time
local = new Date();
// get the current time in the show's timezone
utc = local.getTime() + (local.getTimezoneOffset() * 60000);
show = new Date(utc + (3600000*timezone));
// convert the show hours + minutes to just minutes
showMinutes = (show.getHours() * 60) + show.getMinutes();
// test to see if the show is going on right now
if (days[show.getDay()] === day && (showMinutes >= startMinutes && showMinutes <= endMinutes)) {
onAir = true;
}
return onAir;
}
// example: Air time is Tuesday between 1-2pm Central Time (-6)
var texasShowOnAir = onAir('Tuesday', '13:00', '14:00', '-6'));
// now check if we are on air
if (texasShowOnAir) {
// do stuff here...
}
You can now use this function like this:
var check = onAir('DAY', 'STARTTIME', 'ENDTIME', 'YOURTIMEZONE');
This will return a true/false. Be sure and use 24 hour format.
I would even argue that this is better than using your server's timestamp, because often (especially if you have shared hosting), your server can be set in a different timezone than you.
Here's a demo fiddle: http://jsfiddle.net/stevenschobert/mv54B/
Have the server provide a timestamp when it generates the page and have the client also generate a timestamp when it loads the page so that you can calculate the time offset between the two systems.
Then you can call a function on some interval that checks the current server time to see if it is within the 3pm-4pm period and show/hide the target elements as needed.
From the server:
<div id="server-timestamp" style="display:none">2013-02-12T18:01:19Z</div>
On the client:
$(document).on('load', function() {
var serverTime = new Date($('#server-timestamp').text())
, clientTime = new Date()
, offsetMilliseconds = (clientTime - serverTime);
setInterval(function() {
// If server time is 3pm-4pm then hide/show divs...
}, 1000 /* every second */);
});

How to count time from when user load a page/form until they submit it?

I have a quiz page with some questions (multiple choice, true-false). In the results after the submit of page i want to show something like this:
Started on Tuesday, 1 January 2013, 04:09 AM
Completed on Tuesday, 1 January 2013, 04:10 AM
Time taken 47 secs
Grade 7 out of a maximum of 10 (65%)
i dont know how to count start time and end time to show the above results and how to count the time from when user's load a page until they submit the form.
i'm new and i need your advise. i dont have problem if the problem solved with php or javascript or jquery
You can do something like this and the start and end timestamps will be submitted along with the form. You could then do the calculations with PHP.
var form = document.getElementById("form");
window.onload = function() {
var start = document.createElement("input");
start.type = "hidden";
start.name = "start";
start.value = +new Date()/1000; //unix timestamp
form.appendChild(start);
};
form.onsubmit = function() {
var stop = document.createElement("input");
stop.type = "hidden";
stop.name = "stop";
stop.value = +new Date()/1000;
form.appendChild(stop);
};
Ok here is my solution:
1- user starts the quiz and you put the time in $_SESSION var
$_SESSION['quiztime']=date("Y-m-d H:i:s");
2-User finishes the test and you check the time passed (this example is in minutes you don't have to divide it by 60 if you need seconds)
$to_time = strtotime(date("Y-m-d H:i:s"));
$from_time = strtotime($_SESSION['quiztime']);
echo round(abs($to_time - $from_time) / 60,2). " minutes";
I'd put the time started in a cookie or session, and then once they complete it, just subtract that time from the current time -- That's the time taken!
It may look like this:
Quiz page:
session_start();
$_SESSION['startTime'] = time();
// This is where the quiz would be displayed
Quiz results page:
session_start();
$totalTime = time() - $_SESSION['startTime'];
echo $totalTime;
My "bullet-proofer" solution would be to store the start time on the server, (in the session) associated with a unique id generated per-form and kept in an hidden field.
This way you prevent the user from tampering with it (he might change the unique id, but in that case the form would be invalid) and you don't depend on the client having javascript enabled.
<?php
$form_uuid = uniqid();
$_SESSION['quiz_start_time'][$form_uuid] = time();
Then, in your form, put something like this:
<input type="hidden" name="form_id" value="<?php print $form_uuid; ?>">
And in the form submit handler:
<?php
$form_uuid = $_POST['form_id'];
if (!isset($_SESSION['quiz_start_time'][$form_uuid])) {
// The user is trying to do something nasty (or the session just expired)
// Return something like a 400 error
}
else {
$start_time = $_SESSION['quiz_start_time'][$form_uuid];
// Do other form processing here..
}

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