My PHP codes :
class FrontEndController extends BaseController {
public function Welcome()
{
return View::make('frontend.index');
}
public function Modules($param="")
{
/* convert parameter "$param" be a function */
$prefix = "Mod_"; // func prefix's
if (function_exists($this->$prefix.$param)) {
return $this->$prefix.$param();
}else
{
return $param;
}
}
protected function Mod_product(){
return "You are called CATEGORY";
}
protected function Mod_promo(){
return "You are called PROMO";
}
}
When i use FrontEndController->Modules('product'); i want it return value from Mod_product(), so also when I use FrontEndController->Modules('promo'); it will return value from Mod_promo(). How to do this?
Use method_exists:
$prefix = "Mod_"; // func prefix's
$function = $prefix.$param;
if ( method_exists( $this, $function ) ) {
return $this->$function();
} else {
return $param;
}
You have a few mistakes in your code:
function_exists does not work for classes, use method_exists instead.
if (function_exists($this->$prefix.$param)) {
This does not work either, use call_user_func instead.
return $this->$prefix.$param();
Corrected code:
class FrontEndController extends BaseController {
public function Welcome()
{
return View::make('frontend.index');
}
public function Modules($param="")
{
/* convert parameter "$param" be a function */
$prefix = "Mod_"; // func prefix's
$fcn = $prefix.$param; // save name of function
if (method_exists($this, $fcn)) {
return call_user_func(array($this, $fcn));
}else
{
return $param;
}
}
protected function Mod_product(){
return "You are called CATEGORY";
}
protected function Mod_promo(){
return "You are called PROMO";
}
}
Update your Modules function like this
$this->{$prefix . $params}();
Hope it helps :)
The Reflection Class is the ideal tool for this. It's a Swiss army knife for classes.
public function Modules($param="")
{
/* convert parameter "$param" be a function */
$prefix = "Mod_"; // func prefix's
$reflection = new ReflectionClass(__CLASS__);
if($reflection->hasMethod($prefix.$param)) {
return $this->$prefix.$param();
}else
{
return $param;
}
}
Related
Say I have to similar function :
public function auth(){
return $someResponse;
}
public function collect(){
return $someOtherResponse
}
Question : When one of the response get passed to another class, is there any way to check which function returned the response ?
In a purely object-oriented way, wanting to attach information to a value is akin to wrapping it into a container possessing context information, such as:
class ValueWithContext {
private $value;
private $context;
public function __construct($value, $context) {
$this->value = $value;
$this->context = $context;
}
public value() {
return $this->value;
}
public context() {
return $this->context;
}
}
You can use it like this:
function auth()
{
return new ValueWithContext($someresponse, "auth");
}
function collect()
{
return new ValueWithContext($someotherrpesonse, "collect");
}
This forces you to be explicit about the context attached to the value, which has the benefit of protecting you from accidental renamings of the functions themselves.
As per my comment, using arrays in the return will give you a viable solution to this.
It will allow a way to see what has been done;
function auth()
{
return (array("auth" => $someresponse));
}
function collect()
{
return (array("collect" => $someotherrpesonse));
}
class myClass
{
function doSomething($type)
{
if (function_exists($type))
{
$result = $type();
if (isset($result['auth']))
{
// Auth Used
$auth_result = $result['auth'];
}
else if (isset($result['collect']))
{
// Collect used
$collect_result = $result['collect'];
}
}
}
}
It can also give you a way to fail by having a return array("fail" => "fail reason")
As comments say also, you can just check based on function name;
class myClass
{
function doSomething($type)
{
switch ($type)
{
case "auth" :
{
$result = auth();
break;
}
case "collect" :
{
$result = collect();
break;
}
default :
{
// Some error occurred?
}
}
}
}
Either way works and is perfectly valid!
Letting the two user defined functions auth() & collect() call a common function which makes a call to debug_backtrace() function should do the trick.
function setBackTrace(){
$backTraceData = debug_backtrace();
$traceObject = array_reduce($backTraceData, function ($str, $val2) {
if (trim($str) === "") {
return $val2['function'];
}
return $str . " -> " . $val2['function'];
});
return $traceObject;
}
function getfunctionDo1(){
return setBackTrace();
}
function getfunctionDo2(){
return setBackTrace();
}
class DoSomething {
static function callfunctionTodo($type){
return (($type === 1) ? getfunctionDo1() : getfunctionDo2());
}
}
echo DoSomething::callfunctionTodo(1);
echo "<br/>";
echo DoSomething::callfunctionTodo(2);
/*Output
setBackTrace -> getfunctionDo1 -> callfunctionTodo
setBackTrace -> getfunctionDo2 -> callfunctionTodo
*/
The above function would output the which function returned the response
I'm facing a problem, I want the class Page to know the Variable '$format'.
// class1.php
<?php
include('./class2.php');
echo $format->getTest(); // returns :-) (declared in class2.php)
class Page {
PUBLIC function getText() {
return $format->getTest(); // returns Call to a member function getTest() on null
}
}
$page = new Page;
?>
// class2.php
<?php
class Format {
PUBLIC function getTest() {
return ":-)";
}
}
$format = new Format;
?>
Any suggestions/ideas?
EDIT:
I found a way: return $GLOBALS['format']->getTest();
But I dont like it, its so much to type. Any other way(s)?
Philip
Proper objective solution is to pass variable to constructor, setter or as argument to getText() method. Choose one you find most appropriate for your case.
Constructor
class Page
{
private $format;
public function __construct(Format $format)
{
$this->format = $format;
}
public function getText()
{
return $this->format->getTest();
}
}
$page = new Page($format);
echo $page->getText();
Setter
class Page
{
private $format;
public function setFormat(Format $format)
{
$this->format = $format;
}
public function getText()
{
return $this->format->getTest();
}
}
$page = new Page;
$page->setFormat($format);
echo $page->getText();
Argument
class Page
{
public function getText(Format $format)
{
return $format->getTest();
}
}
$page = new Page;
echo $page->getText($format);
I'm wondering if its possible to switch the visibility in PHP. Let me demonstrate:
class One {
function __construct($id){
if(is_numeric($id)){
//Test function becomes public instead of private.
}
}
private function test(){
//This is a private function but if $id is numeric this is a public function
}
}
Is such thing even possible?
I would use an abstract class with two implementing classes: One for numeric and one for non-numeric:
abstract class One {
static function generate($id) {
return is_numeric($id) ? new OneNumeric($id) : new OneNonNumeric($id);
}
private function __construct($id) {
$this->id = $id;
}
}
class OneNumeric extends One {
private function test() {
}
}
class OneNonNumeric extends One {
public function test() {
}
}
$numeric = One::generate(5);
$non_numeric = One::generate('not a number');
$non_numeric->test(); //works
$numeric->test(); //fatal error
It can be faked up to a point with magic methods:
<?php
class One {
private $test_is_public = false;
function __construct($id){
if(is_numeric($id)){
$this->test_is_public = true;
}
}
private function test(){
echo "test() was called\n";
}
public function __call($name, $arguments){
if( $name=='test' && $this->test_is_public ){
return $this->test();
}else{
throw new LogicException("Method $name() does not exist or is not public\n");
}
}
}
echo "Test should be public:\n";
$numeric = new One('123e20');
$numeric->test();
echo "Test should be private:\n";
$non_numeric = new One('foo');
$non_numeric->test();
I haven't thought about the side effects. Probably, it's only useful as mere proof of concept.
Consider the following class
class myClass {
private $model;
public function update($input) {
return $this->model->update($input);
}
public function find($id) {
$this->model = ORMfind($id);
}
}
How do I prevent
$myClass = new myClass;
$myClass->update($input);
The problem isn't HOW to use the above code but how to make update() a method only callable after find().
EDIT: I changed what my method does so it was more clearly understood that I need to do one method (find()) before another (update())
You could add a flag to your code like so:
class myClass {
private $model;
private $canUpdate = 0;
public function update($input) {
if ($canUpdate === 0) return; // or throw an exception here
return $this->model->update($input);
}
public function find($id) {
$this->model = ORMfind($id);
$canUpdate = 1;
}
}
Setting the flag $canUpdate will caution the update() method to react accordingly. If update() is called, you can throw an exception or exit out of the method if the flag is still 0.
To prevent from returning null value by get :
public function get() {
if (isset($this->value)) return $this->value;
else echo "please give me a value ";
}
You can also create a construct:
function __construct($val){
$this->value=$val;
}
and then give a value to your $value without using set() method:
$myClass=new myClass(10);
Outputting text, returning void, I think all of this is wrong. When you do not expect something to happen, you should throw an exception:
class MyClass {
private $canUpdate = false;
public function find($id) {
// some code...
$this->canUpdate = true;
}
public function canUpdate() {
return $this->canUpdate;
}
private function testCanUpdate() {
if (!$this->canUpdate()) {
throw new Exception('You cannot update');
}
}
public function update($inpjut) {
$this->testCanUpdate();
// ... some code
}
}
Now you can do:
$obj = new MyClass();
try {
$obj->update($input);
} catch (Exception $e) {
$obj->find($id);
$obj->update($input);
}
The proper way to make sure ->update() can only be called when the model has been initialized is to turn it into a dependency:
class myClass
{
private $model;
public function __construct($id)
{
$this->model = ORMfind($id);
}
public function update($input) {
return $this->model->update($input);
}
}
$x = new myClass('123');
Alternatively, if you have multiple find operations, you could introduce them as static constructor methods:
class myClass
{
private $model;
private function __construct($model)
{
$this->model = $model;
}
public function update($input) {
return $this->model->update($input);
}
public static function find($id)
{
return new self(ORMfind($id));
}
}
$x = myClass::find('123');
Update
Tackling your immediate problem can be done by a simple check:
public function update($input) {
return $this->model ? $this->model->update($input) : null;
}
Please look at the following code snipped
class A
{
function __get($name)
{
if ($name == 'service') {
return new Proxy($this);
}
}
function render()
{
echo 'Rendering A class : ' . $this->service->get('title');
}
protected function resourceFile()
{
return 'A.res';
}
}
class B extends A
{
protected function resourceFile()
{
return 'B.res';
}
function render()
{
parent::render();
echo 'Rendering B class : ' . $this->service->get('title');
}
}
class Proxy
{
private $mSite = null;
public function __construct($site)
{
$this->mSite = $site;
}
public function get($key)
{
// problem here
}
}
// in the main script
$obj = new B();
$obj->render();
Question is: in method 'get' of class 'Proxy', how I extract the corresponding resource file name (resourceFile returns the name) by using only $mSite (object pointer)?
What about:
public function get($key)
{
$file = $this->mSite->resourceFile();
}
But this requires A::resourceFile() to be public otherwise you cannot access the method from outside the object scope - that's what access modifiers have been designed for.
EDIT:
OK - now I think I do understand, what you want to achieve. The following example should demonstrate the desired behavior:
class A
{
private function _method()
{
return 'A';
}
public function render()
{
echo $this->_method();
}
}
class B extends A
{
private function _method()
{
return 'B';
}
public function render()
{
parent::render();
echo $this->_method();
}
}
$b = new B();
$b->render(); // outputs AB
But if you ask me - I think you should think about your design as the solution seems somewhat hacky and hard to understand for someone looking at the code.