I want to SELECT the all rows from meeting table even its null. My table structure:
attandance table:
id | meeting_id | person_id | time
1 | 1 | 12 | 02:02
2 | 1 | 15 | 02:05
3 | 1 | 22 | 02:05
4 | 2 | 1 | 02:20
5 | 2 | 12 | 02:01
6 | 3 | 12 | 02:03
and meeting table:
id | date
1 | 15-12-2014
2 | 17-12-2014
3 | 19-12-2014
4 | 21-12-2014
The output should be:
If I SELECT the person_id 12 then it should return:
date |time
15-12-2014 | 02:02
17-12-2014 | 02:01
19-12-2014 | 02:03
21-12-2014 | NULL
If I SELECT the person_id 1 then it should return:
date |time
15-12-2014 | NULL
17-12-2014 | 02:20
19-12-2014 | NULL
21-12-2014 | NULL
It is a pretty straightforward outer join between the tables:
select
m.id,
m.date
a.time,
c.someColumn
from
meetings m
left outer join attendance a
on m.id=a.meeting_id
and a.person_id=:person
left outer join someTable c
on m.id=c.id
I have written a more detailed answer on these sorts of joins in the question and answer: How can an SQL query return data from multiple tables
Edit: As per the comment by Andrew, the clause for the personID is in the join rather than in a normal where clause because it is an outer join. If the condition was put into the where clause as normal, it would in fact negate the outer join completely.
Related
So, as the title says, I think I want to get the SUM of a row in column A (Meta Value) based on matching DATEs in column A (Meta Value) joined from IDs in column B (Item ID).
Essentially, I want to look for a specific date 2017-05-05 in Meta Value. Then, when a date is a match, find the Item ID. In the example below, this would be 2 and 3. Then, get the SUM of the Field ID (11) for both Item ID 2 and Item ID 3 and return the SUM to a variable in PHP.
Here is what my data looks like:
+-----------+------------+------------+
| Meta Value| Field ID | Item ID |
+-----------+------------+------------+
| John | 8 | 1 |
|john#e.com | 10 | 1 |
| 2 | 11 | 1 |
|2016-11-20 | 12 | 1 |
| Mary | 8 | 2 |
|mary#e.com | 10 | 2 |
| **5** | 11 | 2 |
|2017-05-05 | 12 | 2 |
| Mike | 8 | 3 |
|mike#e.com | 10 | 3 |
| **2** | 11 | 3 |
|2017-05-05 | 12 | 3 |
+-----------+------------+------------+
I am after the SUM of 7 from Mike and Mary.
My current wordpress php call looks like this (but only gets me row count):
$bookings = $wpdb->get_var("SELECT COUNT(*) FROM wp_frm_item_metas WHERE field_id=12 AND meta_value='$select_date'");
Any help is appreciated!
seems you need sum on a self join
select sum(a.field_id)
from wp_frm_item_metas a
inner join wp_frm_item_metas b on b.item_id = a.item_id
and b.meta_value = '$select_date'
but if you need the sum for meta_value (11) you should
select sum(a.meta_vale)
from wp_frm_item_metas a
inner join wp_frm_item_metas b on b.item_id = a.item_id
and b.meta_value = '$select_date'
and a.filed_id =11
Facing issue in mysql query, tried with mysql join but not getting expected output.
I want all class, all student record with total ratingscore.Each Class has Many Student. Student has Many or none scholarship
Class table looks like this
+---------------------+
| id classname |
+---------------------+
| 1 10 |
| 2 11 |
| 3 12 |
+---------------------+
Student table looks like, classid is foreign key
+------------------------------------+
| id classid studentname |
+------------------------------------+
| 1 1 xembine |
| 2 1 denial |
| 3 2 suzone |
| 4 3 rosh |
| 5 2 broad |
| 6 1 bell |
| 7 3 martin |
| 8 1 jroff |
+------------------------------------+
rating table looks like, studentid is foreign key
+------------------------------------+
| id studentid ratingscore |
+------------------------------------+
| 1 1 4000 |
| 2 1 10000 |
| 3 5 20000 |
| 4 2 1000 |
| 5 6 2222 |
| 6 1 5000 |
| 7 6 12000 |
| 8 3 3800 |
| 9 5 7500 |
+------------------------------------+
Here : No student from class 3, got any ratingscore yet.so need that student has zero ratingscore.
Expected Output:-
+-------------------------------------------------------------+
| studentname studentid classid classname ratingscore |
+-------------------------------------------------------------+
| xembine 1 1 10 19000 |
| denial 2 1 10 1000 |
| suzone 3 2 11 3800 |
| rosh 4 3 12 0 |
| broad 5 2 11 27500 |
| bell 6 1 10 2222 |
| martin 7 3 12 0 |
| jroff 8 1 10 0 |
+-------------------------------------------------------------+
select s.studentname, s.id as studentid,s.classid,c.classname,sum(ifnull(r.ratingscore,0)) as ratingscore from student s
join class c on c.id=s.classid
left outer join rating r on r.studentid=s.id
group by s.studentname,r.studentid,s.classid,c.classname
Have you try this ?
SELECT s.studentname, s.studentid, c.classid, c.classname, SUM(r.ratingscore)
FROM student as s
INNER JOIN class c on c.classid = s.classid
LEFT OUTER JOIN ratingscore rs ON s.studentid = rs.studentid
GROUP BY s.studentname, s.studentid, c.classid, c.classname
ORDER BY s.studentid
If there is student without class, you have to change inner join to left outer join
SELECT s.studentname AS studentname, s.id AS studentid, c.id AS classid, c.classname AS classname, SUM(r.ratingscore) AS ratingscore
FROM student AS s
INNER JOIN class AS c ON c.id = s.classid
LEFT JOIN rating r ON r.studentid = s.id
GROUP BY s.id
ORDER BY s.id
Category Table
mysql> SELECT * FROM cats;
+------+------+-----------+
| c_id | p_id | c_name |
+------+------+-----------+
| 1 | 1 | cats 1 |
| 2 | 1 | cats 2 |
| 3 | 1 | cats 3 |
+------+------+-----------+
Meta Table
mysql> SELECT * FROM meta;
+------+------+------+---------+-------------+-------+
| m_id | p_id | c_id | name | description | costs |
+------+------+------+---------+-------------+-------+
| 1 | 1 | 1 | Abhijit | description | 100 |
| 2 | 1 | 1 | Abhijit | description | 200 |
| 3 | 1 | 2 | Abhiji2 | description | 500 |
+------+------+------+---------+-------------+-------+
Transaction Table
mysql> SELECT * FROM transactions;
+------+------+------+---------------------+--------+
| t_id | p_id | m_id | date | amount |
+------+------+------+---------------------+--------+
| 1 | 1 | 1 | 2016-02-16 11:17:06 | 50 |
| 2 | 1 | 1 | 2016-02-16 11:17:06 | 50 |
| 3 | 1 | 2 | 2016-02-16 11:17:06 | 50 |
| 4 | 1 | 2 | 2016-02-16 11:17:06 | 150 |
+------+------+------+---------------------+--------+
I want to sum() for each category costs (from meta table) and amount( from transaction table).
I use:
mysql> SELECT c.*, SUM(t.amount), SUM(m.costs)
FROM cats c
LEFT JOIN meta m ON m.c_id=c.c_id
LEFT JOIN transactions t ON t.m_id=m.m_id
GROUP BY c.c_id;
+------+------+-----------+--------+---------------+--------------+
| c_id | p_id | c_name | add_by | SUM(t.amount) | SUM(m.costs) |
+------+------+-----------+--------+---------------+--------------+
| 1 | 1 | Abhijit | 1 | 100 | 400 |
| 2 | 1 | Abhiji2 | 1 | 200 | 500 |
+------+------+-----------+--------+---------------+--------------+
It's wrong. The Costs of cats id 1 is 300 but here I got 400
I Want Get Return From Query Like This:
+------+------+-----------+--------+---------------+--------------+
| c_id | p_id | c_name | add_by | SUM(t.amount) | SUM(m.costs) |
+------+------+-----------+--------+---------------+--------------+
| 1 | 1 | Abhijit | 1 | 100 | 300 |
| 2 | 1 | Abhiji2 | 1 | 200 | 500 |
+------+------+-----------+--------+---------------+--------------+
I think you had a typo (or error) in one of your JOIN conditions. I think you intended your original query to be this:
SELECT c.*, SUM(t.amount), SUM(m.costs)
FROM cats c
LEFT JOIN meta m ON m.c_id = c.c_id
LEFT JOIN transactions t ON t.m_id = m.c_id
GROUP BY c.c_id;
Note carefully ON t.m_id = m.c_id, which agrees with your expected output. In any case, I reworked your query as follows:
SELECT c.c_id, c.p_id, c.c_name, t2.transactionCosts, t1.metaCosts
FROM cats c
LEFT JOIN
(
SELECT c_id, SUM(costs) AS metaCosts
FROM meta
GROUP BY c_id
) t1
ON c.c_id = t1.c_id
LEFT JOIN
(
SELECT m_id, SUM(amount) AS transactionCosts
FROM transactions
GROUP BY m_id
) t2
ON c.c_id = t2.m_id
WHERE t2.transactionCosts IS NOT NULL OR t1.metaCosts IS NOT NULL;
The first subquery computes the meta total for each c_id, and the second subquery computes the transaction total for each m_id. These results are then both joined together with the cats table to get your final result.
Follow the link below for a running demo:
SQLFiddle
the problem is you select c.* but only group by c_id, in this case you have 2 options. window function or subquery.
via over(partition by):
SELECT c.*,
SUM(t.amount)over(partition by c.c_id) as amount,
SUM(m.costs)over(partition by c.c_id) as cost
FROM con_cats c
LEFT JOIN meta m ON m.c_id=c.c_id
LEFT JOIN transactions t ON t.m_id=m.m_id;
via subquery:
select a.*,b.amount,b.costs from con_cats a
inner join
(SELECT c.c_id, SUM(t.amount) as amount, SUM(m.costs) as costs
FROM con_cats c
LEFT JOIN meta m ON m.c_id=c.c_id
LEFT JOIN transactions t ON t.m_id=m.m_id
GROUP BY c.c_id) b
on a.c_id = b.c_id;
See my table(sample_table),
-----------------------------
id | from | to |
-----------------------------
1 | 2 | 1 |
3 | 2 | 1 |
4 | 2 | 4 |
5 | 3 | 2 |
9 | 3 | 1 |
11 | 4 | 1 |
12 | 4 | 3 |
-----------------------------
For each from, I would like the row holding the most recent to, where to = 1
I mean I want only following,
-----------------------------
id | from | to |
-----------------------------
3 | 2 | 1 |
9 | 3 | 1 |
11 | 4 | 1 |
-----------------------------
I Try following Query,
SELECT * FROM sample_table WHERE to = 1 GROUP BY from
It's giving first row of each. Help me.
Thanks,
There are many ways to do it and here is one way
select t1.* from sample_table t1
join(
select max(id) as id,`from` from
sample_table where `to` = 1
group by `from`
)t2
on t1.id= t2.id and t1.`from` = t2.`from`
https://dev.mysql.com/doc/refman/5.0/en/example-maximum-column-group-row.html
Try this
select t1.id, t1.from, t1.to from table as t1 inner join
(
select to, from,min(id) as id from table
where to=1
group by to,from
) as t2
on t1.to=t2.to and t1.id=2.id and t1.from=t2.from
My previous problem and solution:
Get max and min from fields
This working OK, but i would like skip 0 and NULL in this examples.
For example:
First:
id | title
1 | aaa
2 | bbb
3 | ccc
Second:
id | first_id | one | two | three | four
1 | 1 | 3 | 0 | 4 | 6
2 | 2 | 4 | 4 | 1 | 2
3 | 3 | 1 | NULL | 3 | 4
this should show me:
id | title | min | max
1 | aaa | 3 | 6
2 | bbb | 1 | 4
3 | ccc | 1 | 4
and not:
id | title | min | max
1 | aaa | 0 | 6
2 | bbb | 1 | 4
3 | ccc | 0 | 4
In which example from my previous question is the best way to implement skip 0 and NULL?
Pop these into your clause
SELECT
f.id,
f.title
MIN(LEAST(greatest(coalesce(s.one,0),1), greatest(coalesce(s.two,0),1), greatest(coalesce(s.three,0),1), greatest(coalesce(s.four,0),1))) as min,
MAX(GREATEST(greatest(coalesce(s.one,0),1), greatest(coalesce(s.two,0),1), greatest(coalesce(s.three,0),1), greatest(coalesce(s.four,0),1))) as max
FROM
First f
INNER JOIN Second s
on f.id = s.first_id
GROUP BY
f.id,
f.title
You can use coalesce(fieldName, 1) to turn a null into a 1.
Again, as said in your previous question, this is HORRIBLE use of a query to force an answer. You should be changing the layout of the database.
Edit: I have nutted out the data you want, but before you look at it, be aware that if one of my colleagues wrote a script like this, he would be sacked on the spot. This is HIDEOUS and should NOT BE USED.
select
f.id,
f.title,
(select min(z.myVal) from
(
select
b.id,
b.first_id,
b.one as myVal
from
second b
where
b.one is not null
and b.one > 0
union
select
b.id,
b.first_id,
b.two as myVal
from
second b
where
b.two is not null
and b.two > 0
union
select
b.id,
b.first_id,
b.three as myVal
from
second b
where
b.three is not null
and b.three > 0
union
select
b.id,
b.first_id,
b.four as myVal
from
second b
where
b.four is not null
and b.four > 0
) z
where
f.id=z.first_id) as miniVal,
greatest(
coalesce(s.one,0),
coalesce(s.two,0),
coalesce(s.three,0),
coalesce(s.four,0)
) as maxiVal
from
first f,
second s
where
f.id=s.first_id
output Data
+------+-------+---------+---------+
| id | title | miniVal | maxiVal |
+------+-------+---------+---------+
| 1 | aaaa | 3 | 6 |
| 2 | bbbb | 1 | 4 |
| 3 | cccc | 1 | 4 |
+------+-------+---------+---------+
3 rows in set (0.00 sec)
Running this query made me throw up a little in my mouth. That's how wrong it is to write SQL like this.
While seemingly clunky, this solution should work:
SELECT
a.id, a.title, MIN(b.num) AS min, MAX(b.num) AS max
FROM
first a
LEFT JOIN
(
SELECT first_id, one AS num FROM second UNION ALL
SELECT first_id, two FROM second UNION ALL
SELECT first_id, three FROM second UNION ALL
SELECT first_id, four FROM second
) b ON
a.id = b.first_id AND
b.num IS NOT NULL AND
b.num > 0
GROUP BY
a.id, a.title
What this does is it actually gets each number column into its own row, but only the numbers that are not null and > 0. Before the GROUP BY, the result of the LEFT JOIN would look something like:
id | title | num
---------------------
1 | aaa | 3
1 | aaa | 4
1 | aaa | 6
2 | bbb | 1
2 | bbb | 2
2 | bbb | 4
2 | bbb | 4
3 | ccc | 1
3 | ccc | 3
3 | ccc | 4
Then by the groupings of each first (GROUP BY a.id, a.title), we can use the MIN() and MAX() aggregate functions on the num column to extract minimum and maximum values per first group:
id | title | min | max
----------------------------
1 | aaa | 3 | 6
2 | bbb | 1 | 4
3 | ccc | 1 | 4
In the case that a first_id had all four columns having NULL's or 0's, the min and max values would show up as NULL due to using a LEFT JOIN instead of an INNER JOIN as I believe this is would be a better behavior for your situation:
id | title | min | max
----------------------------
4 | ddd | NULL | NULL
USE:
WHERE COLUMN IS NOT NULL AND COLUMN <> 0;
I think you just need to nest the LEAST expressions:
LEAST(
NULLIF(one,0),
LEAST(
NULLIF(two,0),
LEAST(
NULLIF(three,0),
LEAST(
NULLIF(four,0),
null ))))
Edit I just looked it up. The LEAST function takes multiple arguments:
LEAST( NULLIF(one,0), NULLIF(two,0), NULLIF(three,0), NULLIF(four,0))
Edit 2 I see you want both min and max. Obviously you'd just change LEAST to GREATEST or MIN to MAX as needed.
This may be more straightforward or you may not have a handy least function.
SELECT
f.id, f.title,
(
SELECT MIN(NULLIF(val, 0))
FROM
(
SELECT one AS val UNION ALL
SELECT two UNION ALL
SELECT three UNION ALL
SELECT four
) AS vals
)
) as minval
FROM First f INNER JOIN Second s on f.id = s.first_id
You haven't specified if it's possible for all four columns to be null/0. We may need to tweak for that case.
You can use IFNULL():
WHERE IFNULL(fieldname, 0) != 0