I need a little help setting up my query. I'm simply trying to get the users from table advertise_jobs who have the same ID in the table applicants or in another meaning I need to get the users who have applied on a job from the advertise_jobs by the id.
this is my query
SELECT DISTINCT applicants.*, advertise_jobs.*, uid
FROM applicants
INNER JOIN advertise_jobs
ON applicants.ads_id=advertise_jobs.id
GROUP BY applicants.ads_id
it's not functioned as expect it gets other jobs that the users didn't apply to
how can I fix my query to be something like
select * from applicants and * from advertise_jobs where applicants.ads_id = uid
I think this will work
SELECT DISTINCT applicants.uid, advertise_jobs.ads_id
FROM applicants,advertise_jobs
WHERE applicants.uid=advertise_jobs.uid
GROUP BY applicants.ads_id
Related
I am working on a project, there has group feature. when I search any group, this time I have to know that am I already join those listed group.
I have group table and another table group user table for adding the user to the group.
I want to get it with SQL query only with one query. How can I do it?
You could try an inner join
SELECT *
FROM Groups
INNER JOIN UserGroup on Groups.Group_ID = UserGroup.Group_ID
I don't know exactly your tables,but it should be something like that.
I am having 3 tables (c19 , c19b2, g26) in a database
I want to write a SQL Query to search and display all fields of the matched record.
I am using following query:
$query = "SELECT * FROM c19,c19b2,g26 WHERE armyno LIKE '%$searchTerm%'";
But it only works for table c19,
Data from the other 2 tables is not fetched.Each table has a field armyno
Please help me with this
Thank you.
Alright, you are not looking for a JOIN, but a UNION.
SELECT * FROM c19 WHERE armyno LIKE '%$searchTerm%'
UNION
SELECT * FROM c19b2 WHERE armyno LIKE '%$searchTerm%'
UNION
SELECT * FROM g26 WHERE armyno LIKE '%$searchTerm%'
That will let you query all three tables at the same time.
Which DB are you using? This would have worked in SQL Server. However, notice you are doing a cross join of every record to every record... usually you only want to match some records by restriction of a matching key, for example:
select
*
from a
left join b on b.somekey = a.somekey
left join c on c.someotherkey = b.someotherkey
In SQL server you can just say *, but I'm taking it that in your DB engine that didn't work, so try specifying which table. This may in some environments require aliasing as well:
select
a.*,
b.*,
c.*
from tableA as a
left join tableB as b on b.somekey = a.somekey
left join tableC as c on c.someotherkey = b.someotherkey
Generally, you should see the columns from the first table, followed by the columns from the second table, followed by columns from the third table for a given row. If you wanted to get all columns from all tables, but separately, then that would be 3 separate selects.
Lastly, if all 3 tables have "armyno" then I'd expect it to throw an ambiguous field error. In such case you'd want to specify which table's "armyno" field to filter on.
I have to make a scores page for a game and one thing it has to display is the number of times the current user has played the game. Basically what i need to select ID and username from one table, link them together and count the corresponding user IDs from another table.
These are the tables I was given: Users --> ID, USERNAME and Times_Played --> ID, USER_ID
Thanks in advance
You want to query something like this:
SELECT Users.USERNAME, Times_Played.User_ID
FROM Users
INNER JOIN Times_Played
ON Users.ID=Times_Played.ID;
EDIT
After re-reading the question and seeing the need to count the times played you could do this via PHP or via your SQL Query. Via PHP:
$result = mysqli_query(
"SELECT Users.USERNAME, Times_Played.User_ID
FROM Users
INNER JOIN Times_Played
ON Users.ID=Times_Played.ID"
);
$timesPlayed = mysqli_num_rows($result);
If it has to be done via the query, Anish has the correct solution.
I hope that helps.
Try this
select count(*) as Times_Played,Users.USERNAME,Users.ID
from Users
inner join Times_Played
on Users.ID = Times_Played.USER_ID
I am trying to query two tables: finished_events and flagged_events. 1st of all I need everything related to the company_id so
SELECT *
FROM finished_events
WHERE company_id=$id
ORDER by schedule, timestamp
I then changed this to:
SELECT * FROM finished_events
INNER JOIN flagged_events
ON finished_events.company_id=flagged_events.company_id
WHERE finished_events.company_id=$id
ORDER by finished_events.schedule, finished_events.timestamp
I have tried using FULL JOIN, LEFT JOIN, and RIGHT JOINs all unsuccessful. Specifically what I want is to get is a combined effort of the following code:
$sql = "SELECT *
FROM finished_events
WHERE company_id=$id
ORDER by schedule, time_stamp";
$flagged_sql = "SELECT *
FROM flagged_events
WHERE company_id=$id
ORDER by schedule, time_stamp";
The tables are a bit different so UNION won't work here. I can post dummy database entries but this won't be of too much help as I need all from both tables. The 2 links between the tables would be the company_id and the schedule columns. Essentially what is going on behind the scenes is timestamps being put into a different table to which I then process either into finished_events or flagged_events. Flagged events will need the user to do something about it until it is a finished event. So this script is generating the data for the GUI, hence why I need to query both tables and create an associative array of customer details then an array of events (from these 2 tables). So creating the assoc_array is no problem I just need to get this query to spit out all the events and order them correctly. Let me know if you need anything specific to solve this one, thanks :)
EDIT
SQL Fiddle: http://sqlfiddle.com/#!2/d4c30/1
this almost fixes it but not quite right, it repeats entries at the bottom
If I understood correctly, this may be useful for you:
SELECT a.* FROM (
SELECT *, 'finished' as event_type FROM finished_events
UNION
SELECT *, 'flagged' as event_type FROM flagged_events) a
ORDER BY a.schedule, a.time_stamp
I have 2 mysql tables
one has a list of user ids that are associated with a city. ie "Fort Lauderdale" but the user id is actually in a column called entity_id and the city is in a field called field_city_value.
This query brings back all of the entity_ids in "Fort Lauderdale"
SELECT entity_id
FROM `field_data_field_city`
WHERE `field_city_value` LIKE 'Fort Lauderdale'
and then this query brings back the mail for the user id
SELECT mail
FROM `users`
WHERE `uid` =42
I want to combine the 2 and get all of the mails for all of the user ids that match Fort Lauderdale.
Use a join statement.
http://dev.mysql.com/doc/refman/5.0/en/join.html
Heres the long winded way of doing it.. Untested, no mysql access on this box.
SELECT field_data_field_city.entity_id,users.mail FROM users,field_data_field_city WHERE field_city_value LIKE 'Fort Lauderdale' AND field_data_field_city.entity_id = users.uid
Or
SELECT * FROM field_data_field_city city INNER JOIN users user on city.entity_id=user.uid
Can we assume that users.uid is the same as field_data_field_city.entity_id? If that's the case you'll want to look into using MySQL joins
You can try a subselect:
SELECT mail FROM users WHERE uid IN (SELECT entity_id FROM field_data_field_city WHERE field_city_value LIKE 'Fort Lauderdale')
This should do it. You might want to change it a little bit for duplicates or similar, but this simple query should work
SELECT u.mail
FROM users u
LEFT JOIN field_data_field_city fdfc ON fdfc.entity_id = u.uid
WHERE fdfc.field_city_value LIKE 'Fort Lauderdale'