I'm trying to copy from one table to another table and it works fine, however I also need to insert the current user ID in the new table. I haven't yet figured out how. Normally I would do something like SET user_id = :user_id, but i have never worked with this one.
This is my code:
$q = $conn->prepare("INSERT INTO user_themes(title,code_entry,code_home,code_css,code_category,code_archive)
SELECT title, code_entry, code_home, code_css, code_category, code_archive FROM blogy_themes WHERE id = :id");
So my question is:
How can I insert user_id (let's say user_id is 1) into the new table as well?
The basis of your query doesn't change. Just add the value to both the columns and `SELECT statement:
INSERT INTO user_themes(user_id, title,code_entry,code_home,code_css,code_category,code_archive)
SELECT :user_id, title, code_entry, code_home, code_css, code_category, code_archive
FROM blogy_themes WHERE id = :id
Then when you execute, bind both :id and :user_id.
From what I understand you want to have the id of the user that is doing the action in all of the new records, you can do something like:
$q = $conn->prepare("INSERT INTO user_themes(user_id,title,code_entry,code_home,code_css,code_category,code_archive)
SELECT '" . (int) $userid ."' as user_id, title, code_entry, code_home, code_css, code_category, code_archive FROM blogy_themes WHERE id = :id");
This is a workaround in order to keep using the query as it is.
Second option is more "ORM" approach, you can query all the relevant records from the user_themes table, iterate on the result set, clone each row and save it with new user_id.
Related
I have three tables users_tbl, skill_tbl, user_skill_tbl where
users_tbl have 1 to many relations with user_skill_tbl(auto increment)
and skill_tbl have 1 to many relations with the user_skill_tbl.
user_skill_tbl have user_skill_id, skill_id and user_id.
I don't have a problem in inserting the data in the tables.
I have a form where users detail and multiple check option of skill(i get the skill_id only) is there.
when the from is filled, first the user's table is inserted then the last inserted id is taken and the user_skill_tbl is inserted.
But My problem is when I have to update the user_skill_tbl I have used
$skill = $_POST['skill_id'];
for($i=0;$i < count($skill); i++){
$name[$i]= mysqli_escpae_string($con,$skill[$i]);
$query = "update into user_skill_tbl (skill_id)
values ('$skill_id') where user_id = '$user_id'"
after the query is executed the last id of the skill_id is updated on all the skill_id in the user_skill_tbl. I know that I should manipulate along with the user_skill_id but I am not being able to figure it out
I guess you are mixing up the update and insert syntax with "update into". It's "update tablename" or "insert into tablename".
I am not sure how you store your data in user_skill_tbl but if, as I guess, for each user you only store the records related to his/her skills, you need to first delete all the skills for the current user, something like:
$query = "delete from user_skill_tbl where user_id = '$user_id'"
and then add each skill in your for loop:
$query = "insert into user_skill_tbl (skill_id, user_id) values
('$skill_id', '$user_id')
Put everything in a transaction to avoid inconsistencies if something goes wrong during the execution.
I have two tables first called messages and the other called messages_reply.
I used this code to insert into messages table:
$query = "INSERT INTO `messages` VALUES('', '$id', '$otherId', '')";
$query_run = mysqli_query($connect, $query);
I have the first column auto_increment thats why I left it empty by writing ''
Now i want this auto_increment value that i have inserted to be inserted in the other table called messages_reply
Do I have to create another query to return it or there is an instant way to insert it here and there?
you have to select the last id on table messages first, then you can insert that last id + 1 into messages reply
$query_sel_last_id = "SELECT id FROM messages ORDER BY id desc LIMIT 1"; // select the last id
after that, you only need to insert to messages_reply, remember to plus the value
$query_sel_last_id + 1
EDIT: gordon's solution is better and simpler, LAST_INSERT_ID()
I have the following two tables
Table player:
player_id (int)(primary)
player_name (varchar)
player_report_count (int)
Table report:
report_id (int)(primary)
player_id
report_description
report_location
Firstly I ask the user for the player_name and insert it into the player database. From here the player is given an id.
Then I tried to grab the value of the players report count and increment the current value by one (which isn't working).
This is followed by grabbing the playerId from the player table and then inserting into the corresponding column from the report table (also does not work).
When I insert some values into the database, the names, description and report are added to the database however the playerID remains at 0 for all entries and the player_report_count remains at a consistent 0.
What is the correct way to make these two features function? And also is there a more efficient way of doing this?
<?php
$records = array();
if(!empty($_POST)){
if(isset($_POST['player_name'],
$_POST['report_description'],
$_POST['report_location'])){
$player_name = trim($_POST['player_name']);
$report_description = trim($_POST['report_description']);
$report_location = trim($_POST['report_location']);
if(!empty($player_name) && !empty($report_description) && !empty($report_location)){
$insertPlayer = $db->prepare("
INSERT INTO player (player_name)
VALUES (?)
");
$insertPlayer->bind_param('s', $player_name);
$reportCount = $db->query("
UPDATE player
SET player_report_count = player_report_count + 1
WHERE
player_name = $player_name
");
$getPlayerId = $db->query("
SELECT player_id
FROM player
WHERE player_name = $player_name
");
$insertReport = $db->prepare("
INSERT INTO report (player_id, report_description, report_location)
VALUES (?, ?, ?)
");
$insertReport->bind_param('iss', $getPlayerId, $report_description, $report_location);
if($insertPlayer->execute()
&& $insertReport->execute()
){
header('Location: insert.php');
die();
}
}
}
Main issue here is you are getting player details before inserting it. $getPlayerId will return empty result always.
Please follow the order as follows.
Insert player details in to player table and get payerid with mysql_insert_id. After binding you need to execute to insert details to the table.
Then bind and execute insert report .
Then update the player table by incrementing report count with playerid which you got in step 1.
Note : use transactions when inserting multiple table. This will help you to rollback if any insert fails.
MySQL Query will return result object. Refer it from here https://stackoverflow.com/a/13791544/3045153
I hope it will help you
If you need to catch the ID of the last insterted player, This is the function you need if you're using PDO or if it's a custom Mysql Class, you need the return value of mysql_insert_id() (or mysqli_insert_id()) and then directly use it in the next INSERT INTO statement
I have a simple sql query adding a new row to a database and need it to return the a field back to Javascript. The field does Auto_increment but stupildy I called it 'itemId' so mysql_insert_id doesnt work and I don't think I have time to go and amend all the php files that use 'itemId'
Here's my code if it helps:
$addMainItem = "INSERT INTO newsItems (itemId, title, date, tags, location, latitude, longitude, visibleFrontpage, introText, fullDome, liveEvent, customServing, visitorAttraction, retail, digitalCinema, visiblePublic, thumbPath, links, smallDesc) VALUES ('','$title','$date','$tags','$loco','$lat','$long','$visiFront','$intro','$dome ','$live','$custom','$attrac','$retail','$cinema','$public','$thumbPath','$links','$smallDesc')";
$result = mysql_query($addMainItem) or die('error '.mysql_error());
if($result) echo (mysql_insert_id());
I've never heard that naming a column itemId breaking mysql_isert_id().
But you can just select the last inserted record if auto_increment is working.
SELECT * FROM newsItems ORDER BY itemId DESC LIMIT 1
You can put the select statement into a transaction with the insert statement if you're using innoDB and you're worried about a race condition.
mysql_query("SELECT LAST_INSERT_ID()");
Isn't it what are you looking for?
I'm new to php. So, please forgive me if this seems like a dumb question.
Say i have a MySQL insert statement insert into table (a,b) values (1,2),(3,4),(5,6). table 'table' has a auto increment field called 'id'.
how can I retrieve all the ids created by the insert statement above?
It will be great if i get an example that uses mysqli.
You can't. I would suggest that you maintain your own ids (using guid or your own auto-increment table) and use it when you insert into the table.
But it's possible to get the auto-increment value for the last inserted using LAST_INSERT_ID():
http://dev.mysql.com/doc/refman/5.0/en/getting-unique-id.html
AngeDeLaMort's answer is almost right. Certainly, the most appropriate way to deal with the problem is to insert one row at a time and poll the insert_id or generate the sequence elsewhere (which has additional benefits in terms of scalability).
I'd advise strongly against trying to determine the last insert_id and comparing this the most recent insert_id after the insert - there's just too may ways this will fail.
But...an alternative approach would be:
....
"INSERT INTO destn (id, data, other, trans_ref)
SELECT id, data, other, connection_id() FROM source";
....
"SELECT id FROM destn WHERE trans_ref=connection_id()";
....
"UPDATE destn SET trans_ref=NULL where trans_ref=connection_id()";
The second query will return the ids generated (note that this assumes that you use the same connection for all 3 queries). The third query is necessary because connection ids to go back into the pool when you disconnect (i.e. are reused).
C.
In some cases, if you have another identifier of sort such as a UserID, you could filter your query by UniqueID's greater than or equal to mysql_insert_id(), limit by the number of affected rows and only display those by the user. This would really only work inside of a transaction.
$SQL = "INSERT INTO Table
(UserID, Data)
VALUES
(1,'Foo'),
(1,'Bar'),
(1,'FooBar')";
$Result = mysql_query($SQL);
$LastID = mysql_insert_id();
$RowsAffected = mysql_affected_rows();
$IDSQL = "SELECT RecordID
FROM Table
WHERE UserID = 1
AND RecordID >= '$LastID'
LIMIT '$RowsAffected'";
$IDResult = mysql_query($IDSQL);
as a follow up to AngeDeLaMort:
You could seperate your inserts and do it something like this:
$data = array (
array(1,2),
array(3,4),
array(5,6)
);
$ids = array();
foreach ($data as $item) {
$sql = 'insert into table (a,b) values ('.$item[0].','.$item[1].')';
mysql_query ($sql);
$id[] = mysql_insert_id();
}
Now all your new id's are in the $id array.
Maybe I can do this
$insert = "insert into table (a,b) values (1,2),(3,4),(5,6)";
$mysqli->query($insert);
$rows_to_be_inserted=3;
$inserted_id = $mysqli->insert_id // gives me the id of the first row in my list
$last_row_id = ($inserted_id+$rows_to_be_inserted)-1;
$mysql->query("select * from table where id between $inserted_id and $last_row_id");
what to you guys say?