Pagination Number of Pages - php

Question

I am creating pagination. I have a pagination class:
class Pagination {
public $current_page;
public $per_page;
public $total_count;
public function __construct($page=1, $per_page=10, $total_count=0){
$this->current_page = (int)$page;
$this->per_page = (int)$per_page;
$this->total_count = (int)$total_count;
}
public function offset(){
// Assuming 20 items per page:
// page 1 has an offset of 0 (1-1) * 20
// page 2 has an offset of 20 (2-1) * 20
// in other words, page 2 starts with item 21
return ($this->current_page - 1) * $this->per_page;
}
public function total_pages(){
return ceil($this->total_count/$this->per_page);
}
public function previous_page(){
return $this->current_page - 1;
}
public function next_page(){
return $this->current_page + 1;
}
public function has_previous_page(){
return $this->previous_page() >= 1 ? true : false;
}
public function has_next_page(){
return $this->next_page() <= $this->total_pages() ? true : false;
}
}
I also am using it like this:
<?php
// 1. the current page number ($current_page)
$page = !empty($_GET['page']) ? (int)$_GET['page'] : 1;
// 2. records per page
$per_page = 8;
// 3. total record count ($total_count)
$total_count = Song::count_all();
$pagination = new Pagination($page, $per_page, $total_count);
// Instead of finding all records, just find the records
// for this page
$sql = "SELECT * FROM songs ";
$sql .= "ORDER BY dopeness DESC ";
$sql .= "LIMIT {$per_page} ";
$sql .= "OFFSET {$pagination->offset()}";
$songs = Song::find_by_sql($sql);
?>
<?php
if($pagination->total_pages() > 1){
if($pagination->has_previous_page()){
echo "<a href=\"all_songs.php?page=";
echo $pagination->previous_page();
echo "\">«Previous </a> ";
}
for($i=1; $i<=$pagination->total_pages(); $i++){
if($i == $page){
echo " <span class=\"selected\">{$i}</span> ";
} else {
echo " {$i} ";
}
}
if($pagination->has_next_page()){
echo "<a href=\"all_songs.php?page=";
echo $pagination->next_page();
echo "\"> Next»</a> ";
}
}
?>
Output is "previous 1 2 3 (however many pages) next".
What I want to do is make it so that if there are more than ten pages there will be "..." for the last link that would take you to page 11-20 ("previous 11 12 13 next") and so on. Can anybody help me to tackle this?

Answer 1

You should not only display the next 10 pages starting with 0, but consider the current page - then walk 10 pages on wards, and break the iteration, once you displayed 10 page-buttons:
$page = 5; //assuming within valid bounds
for($i=$page; $i<=$pagination->total_pages(); $i++){
if ($i > $page+ 10){
echo " ... ";
break;
}
if($i == $page){
echo " <span class=\"selected\">{$i}</span> ";
} else {
echo " {$i} ";
}
}