Good morning,
I am quite new to php and I am trying to create a connection to a MSSQL server, I've been able to do it through MYSQL php connection but what I thought would be a simply change to MSSQL is proving to be much harder than expected.
The below code is basically what I am using after much googleing and search in this website this is what i've come up with:
<?php
$Server = "127.0.0.1";
$User = "BOB123";
$Pass = "BOBPASS";
$DB = "BOBDB";
//connection to the database
$dbconn = mssql_connect($Server, $User, $Pass)
or die("Couldn't connect to SQL Server on $Server");
//select a database to work with
$selected = mssql_select_db($DB, $dbconn)
or die("Couldn't open database $myDB");
//declare the SQL statement that will query the database
$query = "SELECT CustomerName from tblCustomer ";
//execute the SQL query and return records
$result = mssql_query($query);
$numRows = mssql_num_rows($result);
echo "<h1>" . $numRows . " Row" . ($numRows == 1 ? "" : "s") . " Returned </h1>";
//display the results
while($row = mssql_fetch_array($result))
{
echo "<br>" . $row["name"];
}
//close the connection
mssql_close($dbconn);
?>
As you can see the above script is very basic and there are very similar ones knocking around on the web could anyone help in connecting to the server this script doesn't seem to want to connect. I've changed the log on details as you'd probably know.
Thanks
Kris
You have a typo on:
$dbconn = mssql_connect($Server, $User, $Pass);
Should be:
$dbconn = mysql_connect($Server, $User, $Pass);
You're typing mysql wrong on each mysql_ function you create, change all mssql_ to mysql_
Note:
You shouldn't use mysql_* functions in new code. They are no longer maintained and are officially deprecated. Learn about prepared statements instead, and use PDO or MySQLi.
#Daniel Gelling Doesn't look like a typo, looks like he is trying to connect to Microsoft SQL Server using mssql. You are correct about the API being outdated however.
Related
I'm relatively new to any type of programming or coding. I'm not quite understanding why no matter what adjustments I make to my php file I can't seem to pull any data from a table.
Here is a link to the table: https://i.gyazo.com/4ad5e860895014c49dbe0539c38cdec2.png
Above is the test table I have been trying to use. From what I can understand I'm connecting to the database okay, but all of my problems come after the connection. Also, I'm using php 7.0 so a lot of the information I'm finding online has not been helpful.
If there is something glaringly wrong with my table or in my code, please let me know.
Here is my code:
'''
//Set Variables
$serverName = "localhost";
$userName = "root";
$password = "";
$databaseName = "test";
//Create Connection
$connection = mysqli_connect($serverName,$userName,$password,$databaseName);
//Check Connection
if(!$connection){
die("Connection failed: ".mysqli_connect_error());
}
echo "Connected successfully <br>";
//Fetch Data
$query = "SELECT * from table1";
$result = mysqli_query($connection, $query);
$row = mysqli_fetch_array($result, MYSQLI_NUM);
printf ($row[1], $row[2]);
mysqli_free_result($result);
mysqli_close($connection);
I figured out the issue a few hours ago. The code I had posted would have worked perfectly fine if I was connecting to the port for MySQL rather than MariaDB. Didn't realize that the port that MariaDB was connected to was the default.
MariaDB by default was port 3306, but MySQL was 3308. After specifying 'localhost:3308' I was able to start properly pulling rows from my tables.
So here's the problem, the script I purchase is written on PHP 5.x, and I'm using xampp with PHP7.x installed for development. Now I want to migrate my script to PHP7.x. Now I know this was asked a million times already but do you mind if you could take a look at my code and give your thoughts about it, or simply share your knowledge. I would deeply appreciate it.
Here is the code for my config.php
<?php
// mySQL information
$server = 'localhost'; // MySql server
$username = 'admin'; // MySql Username
$password = 'admin' ; // MySql Password
$database = 'arcade'; // MySql Database
// The following should not be edited
error_reporting(E_ERROR | E_WARNING | E_PARSE | E_NOTICE);
$con = mysql_connect($server, $username, $password);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db($database, $con);
// Get settings
if (!isset($install)) {
$sql = mysql_query("SELECT * FROM ava_settings");
while ($get_setting = mysql_fetch_array($sql)) {
$setting[$get_setting['name']] = $get_setting['value'];
}
}
?>
The deprecated functions are:
mysql_connect()
mysql_error()
mysql_fetch_array()
mysql_query()
mysql_select_db()
Now, I don't want to use the PDO approach, I want to use mysqli instead. Am I suppose to just replace the mysql_* into mysqli_*? So it will become like these? I don't want to hide/surpress the deprecate warnings.
mysqli_connect()
mysqli_error()
mysqli_fetch_array()
mysqli_query()
mysqli_select_db()
I just offer you that migrate to PDO driver. Because every update you may see a lot of deprecation errors.
But if you can not do it the first thing to do would probably be to replace every mysql_* function call with its equivalent mysqli_*, at least if you are willing to use the procedural API -- which would be the easier way, considering you already have some code based on the MySQL API, which is a procedural one.
Note that, for some functions, you may need to check the parameters carefully: Maybe there are some differences here and there -- but not that many, I'd say: both mysql and mysqli are based on the same library (libmysql ; at least for PHP <= 5.2)
Look at difference between mysqli and mysql:
$mysqli = mysqli_connect("example.com", "user", "password", "database");
$res = mysqli_query($mysqli, "SELECT ...");
$row = mysqli_fetch_assoc($res);
echo $row['_msg'];
$mysql = mysql_connect("example.com", "user", "password");
mysql_select_db("test");
$res = mysql_query("SELECT ...", $mysql);
$row = mysql_fetch_assoc($res);
echo $row['_msg'];
I rarely do programming. I only know enough to be dangerous as they say and I simply assemble bits of code to get what I want. My code below seems to die at the $sql query statement. It never returns any data. It should show the 13 records that are present, but it says there is none to return. I'm guessing this is some kind of syntax error?
<?php
$host = 'myipaddress';
$user = 'myuser';
$pass = 'mypass';
$db = 'mydatabase';
$conn = mysql_connect($host, $user, $pass, $db) or die("Can not connect." . mysql_error());
// Create connection
//$conn = mysqli_connect($host, $user, $pass, $db);
// Check connection
if (!$conn) {
die("Connection failed: ");
}
$sql = "SELECT * FROM pages WHERE pid > '5'";
$result = mysql_query($conn, $sql);
if (mysql_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "id: " . $row["pid"]. " - Name: " . $row["title"]. "<br>";
}
} else {
echo "0 results";
}
mysql_close($conn);
?>
Your using the mysql_ API right up until you try to fetch rows here, where you're using mysqli_. That will not work.
while($row = mysqli_fetch_assoc($result)) {
echo "id: " . $row["pid"]. " - Name: " . $row["title"]. "<br>";
}
Your script is at risk for SQL Injection Attacks. Please stop using mysql_* functions. These extensions have been removed in PHP 7. Learn about prepared statements for PDO and MySQLi and consider using PDO, it's really pretty easy.
EDIT: Your connection (Good Eyes Ralph!) string will not work because mysql_connect() doesn't accept the database as part of the connection. You must use the additional function mysql_select_db() to choose your database.
In addition, it is not necessary to specify the connection link in mysql_query() but if you do it should be the second argument:
$result = mysql_query($sql, $conn);
There is quite a bit wrong with your code.
mysql_connect($host, $user, $pass, $db)
mysql_connect() uses 3 parameters, the 4th doesn't do what you think it does.
http://php.net/manual/en/function.mysql-connect.php
You need to use mysql_select_db() http://php.net/manual/en/function.mysql-select-db.php
Then,
$result = mysql_query($conn, $sql);
The connection comes second in mysql_.
http://php.net/manual/en/function.mysql-query.php
Then you're mixing a MySQLi function mysqli_fetch_assoc which doesn't intermix with the mysql_ library.
Read: Can I mix MySQL APIs in PHP?
So, just use the full MySQLi library
http://php.net/manual/en/book.mysqli.php
or PDO:
http://php.net/manual/en/book.pdo.php
Along with a prepared statement:
https://en.wikipedia.org/wiki/Prepared_statement
Check for the real errors, should your query fail:
http://php.net/manual/en/function.mysql-error.php
Add error reporting to the top of your file(s) which will help find errors.
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
// rest of your code
Sidenote: Displaying errors should only be done in staging, and never production.
As you can see, I did not provide you with a full rewrite, as I feel that in "Teaching a person how to fish...", will feed them for life, rather than "Throwing them a fish...", and only feed them for a day (wink).
You need to use mysql_fetch_assoc() in place of mysqli_fetch_assoc(), because your previous functions are based on mysql_*, not mysqli_*
if (mysql_num_rows($result) > 0) {
// output data of each row
while($row = mysql_fetch_assoc($result)) {
echo "id: " . $row["pid"]. " - Name: " . $row["title"]. "<br>";
}
} else {
echo "0 results";
}
For some reason, the following code inside the query works in my MySQL command console, yet when I try to run it as a Query in PHP, something keeps going wrong and I'm not sure what. Here is the code I've done so far.
//2. Perform database query
$query = "SELECT skills.element_id, content_model_reference.element_id, element_name FROM skills, content_model_reference WHERE (skills.element_id = content_model_reference.element_id)";
$result = mysql_query($query);
//Tests if there was a query error
if(!$result){
die("Database query failed.");
}
Is there something preventing the code that worked in MySQL (The line with SELECT) from working, or is my syntax somehow wrong?
EDIT: So it's saying I didn't select a database. Yet I thought I had. Here is the code above it:
//1. Create a database connection
$dbhost = "host"; //Host: Can be either an IP address, or a domain (like google.com).
$dbuser = "user";//User: The user that is connecting to the database.
$dbpass = "pass";//Password: This is the password that the user is using.
$dbname = "db";//Name: This is the name of the database.
$connection = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);//The value, 'handle,' is the connection.
//Test if connection occurred. Die ends the program/php, and in this case, also prints a message
if(mysqli_connect_errno()){
die("Database connection failed: ".
mysqli_connect_error().
" (". mysqli_connect_errno() . ")"
);
}
Like I said, the error message I am getting is pertaining only to the query, the server is fine with my database connection.
You're using mysqli_* for the connection, but you're using mysql_* for the QUERY... don't think you can do that, has to be one or the other (MYSQLI_ preffered). Also the query should be:
$result = mysqli_query($connection,$query);
I need start using the mysqli extension but I'm finding all kinds of conflicting info depending on how all the info is that I'm trying to use.
For example, my header connects to a 'config.php' file that currently looks like this:
<?php
$hostname_em = "localhost";
$database_em = "test";
$username_em = "user";
$password_em = "pass";
$em = mysql_pconnect($hostname_em, $username_em, $password_em) or trigger_error(mysql_error(),E_USER_ERROR);
?>
But when I go to php.net I see that I should be using this but after updating everything I get no database.
<?php
$mysqli = new mysqli("localhost", "user", "password", "database");
if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}
echo $mysqli->host_info . "\n";
$mysqli = new mysqli("127.0.0.1", "user", "password", "database", 3306);
if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}
echo $mysqli->host_info . "\n";
?>
I also went through and added an "i" to the following code in my site and again no luck:
mysql_select_db($database_em, $em);
$query_getReview =
"SELECT
reviews.title,
reviews.cover_art,
reviews.blog_entry,
reviews.rating,
reviews.published,
reviews.updated,
artists.artists_name,
contributors.contributors_name,
contributors.contributors_photo,
contributors.contributors_popup,
categories_name
FROM
reviews
JOIN artists ON artists.id = reviews.artistid
JOIN contributors ON contributors.id = reviews.contributorid
JOIN categories ON categories.id = reviews.categoryid
ORDER BY reviews.updated DESC LIMIT 3";
$getReview = mysql_query($query_getReview, $em) or die(mysql_error());
$row_getReview = mysql_fetch_assoc($getReview);
$totalRows_getReview = mysql_num_rows($getReview);
And here's the only place on my display page that even mentions mysql so far:
<?php } while ($row_getReview = mysql_fetch_assoc($getReview)); ?>
I did see something at oracle that another stackoverflow answer pointed someone to that updates this stuff automagically, but I have so little code at this point it seems like overkill.
Adding an i to any mysql function won't make it a valid mysqli function. Even if such function exists, maybe the parameteres are different. Take a look here http://php.net/manual/en/book.mysqli.php and take some time to check mysqli functions. Maybe try some examples to become familiar with the way things work. I also reccomend you to choose either object oriented code, either procedural. Don't mix them.
I just made the switch to mysqli lately, took me a few hours to wrap my head around it. It works well for me, hope it will help you out a bit.
Here the function to connect to the BD:
function sql_conn(){
$sql_host = "localhost";
$sql_user = "test";
$sql_pass = "pass";
$sql_name = "test";
$sql_conn = new mysqli($sql_host, $sql_user, $sql_pass, $sql_name);
if ($sql_conn->connect_errno) error_log ("Failed to connect to MySQL: (" . $sql_conn->connect_errno . ") " . $sql_conn->connect_error);
return $sql_conn;
}
This will return a Mysqli Object that you can use to make you request afterward. You can put it in your config.php and include it or add it at the top of your file, whatever works the best for you.
Once you have this object, you can use it to make your query against the object like so: (in this case, if an error came up it will be outputted in the error_log. I like having it there, you can echo it instead.
//Use the above function to create the mysqli object.
var $mysqli = sql_conn();
//Create the query string (truncated for the example)
var $query = "SELECT reviews.titl ... ... ted DESC LIMIT 3";
//Launch the query on the mysqli object using the query() method
if(!($results = $mysqli->query($query))){
//It it fails, log the error
error_log(mysqli_error($mysqli));
}else{
//Manipulate your data.
//here it depends on what you retunr, a single value, row or a list of rows.
//Example for a set of rows
while ($record = $results->fetch_object()){
array_push($array, $record);
}
}
//Just to show, this will output the array:
print_r($array);
//Close the connection:
$mysqli->close();
So basically, in mysqli, you create an object and use the method to work your way out.
Hope this helps. Once you figured it out, you will most likely enjoy mysqli more that mysql. I did anyway.
PS: Please note that this was copy/pasted from existing, working code. Might have some typo, and might forgot to change a var somewhere, but it's to give you an idea of how mysqli works. Hope this helps.