Replace string with different strings containing pattern - php

Question

Say you have a string like
$str = "<img src='i12'><img src='i105'><img src='i12'><img src='i24'><img src='i15'>....";
is it possible to replace every i+n by the nth value of an array called $arr
so that for example <img src='i12'> is replaced by <img src='$arr[12]'>.

Answer 1

If I were you, I'd simply parse the markup, and process/alter it accordingly:
$dom = new DOMDocument;
$dom->loadHTML($str);//parse your markup string
$imgs = $dom->getElementsByTagName('img');//get all images
$cleanStr = '';//the result string
foreach($imgs as $img)
{
$img->setAttribute(
'src',
//get value of src, chop of first char (i)
//use that as index, optionally cast to int
$array[substr($img->getAttribute('src'), 1)]
);
$cleanStr .= $dom->saveXML($img);//get string representation of node
}
echo $cleanStr;//echoes new markup
working demo here
Now in the demo, you'll see the src attributes are replaced with a string like $array[n], the code above will replace the values with the value of an array...

Answer 2

I would use preg_replace for this:
$pattern="/(src=)'\w(\d+)'/";
$replacement = '${1}\'\$arr[$2]\'';
preg_replace($pattern, $replacement, $str);
$pattern="/(src=)'\w(\d+)'/";
It matches blocks of text like src='letter + digits'.
This catches the src= and digit blocks to be able to print them back.
$replacement = '${1}\'\$arr[$2]\'';
This makes the replacement itself.
Test
php > $str = "<img src='i12'><img src='i105'><img src='i12'><img src='i24'><img src='i15'>....";
php > $pattern="/(src=)'\w(\d+)'/";
php > $replacement = '${1}\'\$arr[$2]\'';
php > echo preg_replace($pattern, $replacement, $str);
<img src='$arr[12]'><img src='$arr[105]'><img src='$arr[12]'><img src='$arr[24]'><img src='$arr[15]'>....