php mysqli prepared statement all ways skipping the first result - php

Question

I have a class which takes data from the database. Everything works but the results 'clips' the first result.
For example I have 15 items in my database so by echoing out the id I should get
1
2
3
4
...
13
14
15
But I get
2
3
4
...
13 14 15
The statement is working as the data is displaying but why is it all ways missing the first result.
CODE:
private function formatResults($data){
while($row = $data->fetch(\PDO::FETCH_ASSOC)){
echo $row['product_id'].'<br/>';
}
}
public function getAllProducts(){
if($this->databaseConnection()){
$stmt = $this->db_connection->prepare("SELECT * FROM products ORDER BY product_id DESC");
$stmt->execute();
$result = $stmt->fetch(\PDO::FETCH_ASSOC);
$this->formatResults($stmt);
}
}
That is the original function which works, (except missing out the first row).
I also tried just targeting one row to see if it made a difference but no nothing gets returned.
public function getAllProducts(){
if($this->databaseConnection()){
$stmt = $this->db_connection->prepare("SELECT * FROM products WHERE product_id = ? ORDER BY product_id ASC");
$a =1;
$stmt->bindParam(1,$a,\PDO::PARAM_INT);
$stmt->execute();
while($row = $stmt->fetch(\PDO::FETCH_ASSOC)){
echo $row['product_id'].'<br/>';
}
}
}
Im not sure what to do here, the function appears to work.

Answer 1

Because you're fetching/throwing away a row:
$result = $stmt->fetch(\PDO::FETCH_ASSOC); // fetch first row
$this->formatResults($stmt); // fetch all the other rows
Simply eliminate that "fetch first row" line.