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This is a code snippet I have and I would like to be able to select the out of PHP. When I try to grab the PHP output and store it into a variable, I receive "undefined".
<h1 id=<?php echo '$test; ?> class="list-name--original">
My last attempt I tried this code:$("h1.list-name--original")[0].outerHTML);
Why not just put all your PHP output in a variable
<script>
var data = '<?=$test?>';
</script>
You can then set the contents of an H1 tag like this
<h1 id="myid"></h1>
<script>
$('h1#myid').text(data);
</script>
Try
<h1 id="<?php echo $test; ?>" class="list-name--original">
in jQuery
$(".list-name--original").html();
or
$("#<?= $test ?>").html();
Try this:
<?php $test = "Hello world!"; ?>
<h1 id="example" class="list-name--original"><?php echo $test; ?></h1>
<script language="javascript">
$("#example").html();
</script>
Related
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If <?php echo $jsonObj->data->image; ?> has a value, like 1234.jpg I want to show this:
<img src="https://www.example.com/img/<?php echo $jsonObj->data->image; ?>" />
If <?php echo $jsonObj->data->image; ?> has no value, then <img src="https://www.example.com/img/<?php echo $jsonObj->data->image; ?>" /> should remain hidden.
Any help please?
Use php if-else statement for that.
<?php
if(!empty($jsonObj->data->image)) {
?>
<img src="https://www.example.com/img/<?php echo $jsonObj->data->image; ?>" />
<?php
}
?>
You can add else part and do whatever you want.
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I have following data in mysql, and I want to echo in this format:
Data:
Name,Image URL,Link
I want to print it dynamically like this : http://screensaver.cf/screensavers.php
I don't know user's screen width, still I want it to appear as much as possible in width.
How can I do this in html and PHP?
My code:
<?php
require("config.php");
?>
<div id="main-wrap">
<div class="container">
<div id="main">
<div id="content"><div id='wsite-content' class='wsite-elements wsite-not-footer'>
<div class="paragraph" style="text-align:left;">
<?php
$sql='SELECT * FROM `games` where 1=1';
$data = mysql_query($sql);
echo '<h4 class="result">Result:</h4>';
while($row = mysql_fetch_row($data)){
$table=WHAT TO DO HERE TO MAKE IT LOOK LIKE THAT???????
echo $table;
echo '<br><br>';
}
?>
</div>
</div>
</div>
</div>
</div>
<?php
include("footer.php");
?>
P.S I know mysql is depreciated and I am constantly working to learn Mysqli, as I am in 8th class, I don't have much time.
<style>.a{float:left;}
</style>
>
in while loop use this
<div class = "a">
<?php <img src='".$row['url']."' width='140' height='140'> ?>
</div>
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I am a newbie in coding etc. so I am trying to get some help from you guys. I have to put every single file (.php) in one .html/php file.
Now I got this code:
<html>
<head>
<style type='text/css'>
span {
text-decoration:underline;
color:blue;
cursor:pointer;
}
</style>
<script>
// show the given page, hide the rest
function show(elementID) {
// try to find the requested page and alert if it's not found
var ele = document.getElementById(elementID);
if (!ele) {
alert("no such element");
return;
}
// get all pages, loop through them and hide them
var pages = document.getElementsByClassName('page');
for(var i = 0; i < pages.length; i++) {
pages[i].style.display = 'none';
}
// then show the requested page
ele.style.display = 'block';
}
</script>
</head>
<body>
<p>
Show page
<span onClick="show('Page1');">1</span>,
<span onClick="show('Page2');">2</span>,
<span onClick="show('Page3');">3</span>.
</p>
<div id="Page1" class="page" style="">
Content of page 1
</div>
<div id="Page2" class="page" style="display:none">
Content of page 2
</div>
<div id="Page3" class="page" style="display:none">
Content of page 3
</div>
</body>
So my question is; how do i put my files into the 'Content of page 1/2/3'?
Thanks in advance!
Try include("[path to your file]"); or include_once("[path to your file]");
http://php.net/manual/en/function.include.php
http://php.net/manual/en/function.include-once.php
If you need to combine other PHP files with this HTML file, simply change the name of this file to .php if it isn't already. Then copy/paste your code (in order each file is processed) into the top of this file. Be sure to surround your php with <?php and ?>. The HTML will still display correctly if it's inside a PHP file.
Note: This is not good practice, but it will accomplish what your teacher is requesting.
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I need the data to have a different style if the sold = 0 in the mysql table
and when i use the code below the website shows a blank white page
(?=$vehicle-> this is the vehicle reference
and sold is the column withing the sql table
<?php
if (?=$vehicle->sold?!= 1)
{
<div class="foo">
<div class="fboverlay"></div>
<a>
<img src="/media.php?productId=<?=$vehicle->vehicle_id?>&file=<?=$vehicle->main_image?>" />
</a>
</div>
}
else {
<img src="/media.php?productId=<?=$vehicle->vehicle_id?>&file=<?=$vehicle->main_image?>" />
}
?>
You need to learn the PHP from the basics. Learn about operators, PHP and HTML secion, etc..
Anyway, i fixed your code. The condition is if $vehicle->sold is not equal to 1. But i think, (in your OP you mentioned it should be 0) you want this: $vehicle->sold == 0
//Use sytnax like this. See php opeartors.
if ($vehicle->sold != 1) {
?> <!-- Close the php -->
<div class = "foo">
<div class = "fboverlay"></div>
<img src = "/media.php?productId=<?= $vehicle->vehicle_id ?>&file=<?= $vehicle->main_image ?>" />
</div>
<?php
//Open the php again
} else {
?> <!-- close the php -->
<img src = "/media.php?productId=<?= $vehicle->vehicle_id ?>&file=<?= $vehicle->main_image ?>" />
<?php //Open again
}
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If I defined some div in a code like this:
if(...)
{
// code
// code again
if(...)
{
// code
<div> first div </div>
//code code
}
}
<div> second div </div>
So "first div" always appears before the "second div", how can I switch the order of div's displaying? Thanks.
how about this (you need div id's)
$('#secondDiv').insertBefore('#firstDiv').remove();
Change your code to:
if(...)
{
// code
// code again
if(...)
{
// code
<div id='firstDiv'> first div </div>
//code code
}
}
<div id='secondDiv'> second div </div>
You can show the second <div> in a predetermined place by appending it to another div. For example:
HTML:
<div id="fake-second"></div>
<div id="first"> first div </div>
<div id="second"> second div </div>
jQuery:
$("#fake-second").append($("#second").html());
$("#second").hide();
JS Fiddle Demo