Fastest way for selecting something like this - php

Question

I want to select faster than this my page load is very slow when executing the script.
$bmw= mysqli_query($con,"SELECT * FROM cars WHERE name='bwm'
ORDER BY date DESC LIMIT 1"); $mercedes= mysqli_query($con,"SELECT * FROM cars
WHERE name='mercedes' ORDER BY date DESC LIMIT 1");
$audi= mysqli_query($con,"SELECT * FROM cars WHERE name='audi'
ORDER BY date DESC LIMIT 1");
$skoda= mysqli_query($con,"SELECT * FROM cars WHERE name='skoda'
ORDER BY date DESC LIMIT 1");
And echo it out like here below, like that the page load is very slow.
while($row = mysqli_fetch_array($bmw)) { echo $row['name'] . " " .
$row['date'];
}
while($row = mysqli_fetch_array($mercedes)) { echo $row['name'] . " "
. $row['date'];
}
while($row = mysqli_fetch_array($audi)) { echo $row['name'] . " " .
$row['date'];
}
Thanks in advance

Answer 1

There is nothing wrong in the queries you wrote, your performance issue may be due to :
missing indexes on name and date : create indexes on name and date
cars database too big for your hardware : new hardware/partitionning/redesign
network link slow : solution provided by Lacy K is interesting as there is only one query sent to mysql
You could also improves performance a bit by selecting only name and date instead of *
select name, date from ...

Answer 2

Why not selecting all make at once like this:
$q= mysqli_query($con,"SELECT * FROM cars WHERE name IN ('bwm', 'mercedes', 'audi', 'skoda') ORDER BY date DESC LIMIT 1");
while($row = mysqli_fetch_array($q)) {
if($row['name'] == 'bmw'){
echo $row['name'] . " " . $row['date'];
}
elsif($row['name'] == 'mercedes'){
echo $row['name'] . " " . $row['date'];
}
elsif($row['name'] == 'audi'){
echo $row['name'] . " " . $row['date'];
}
elsif($row['name'] == 'skoda'){
echo $row['name'] . " " . $row['date'];
}
else{
echo $row['name'] . " " . $row['date'];
}
}