so I am using an HTML template, and have a dynamic table generated by PHP. For whatever reason, when I add the php table in, I can no longer scroll on the page. I am wondering if there is some work around, or there is something I should be looking for in the template CSS to fix this.
Here is my HTML with the embedded PHP:
<div class="block-head">
<h2>Datatable All Features</h2>
</div>
<div class="block-content np">
<table cellpadding="0" cellspacing="0" width="100%" class="table table-bordered table-striped sortable">
<thead>
<tr>
<th><input type="checkbox" class="checkall"/></th>
<th width="25%">Name</th>
<th width="25%">Gender</th>
</tr>
</thead>
<tbody>
<?php
while ($row = mysql_fetch_array($query)) {
echo "<tr>";
echo "<td>" . $row[username] . "</td>";
echo "<td>" . $row[gender] . "</td>";
echo "</tr>";
}
?>
</tbody>
</table>
</div>
Here is my query, which I have above my HTML, for whatever it's worth. I know it's deprecated (just not a top priority right now):
$query = mysql_query("SELECT * FROM markerfollowing WHERE markerID = '$markerid'"); //query
When I remove the php in the table, it scrolls fine. When I put it back, no dice.
Sincere thanks for any help!
Here is my solution:
<?php
while ($row = mysql_fetch_array($query)) {
echo "<tr>";
echo "<td>" . '<input type="checkbox" name="checkbox"/>' . "</td>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['gender'] . "</td>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['gender'] . "</td>";
echo "</tr>";
}
?>
It's probably an error 500 which you cannot see because of your PHP.ini configuration.
change the $row[username] to $row['username'] and do the same with the gender.
This should do the job:
<?php
while ($row = mysql_fetch_array($query)) {
echo "<tr>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['gender'] . "</td>";
echo "</tr>";
}
?>
Related
I am a beginner to PHP. I am looking to highlight or color the values of first and last row in a table fetched using PHP and Mysql.
Below is the code.
<?php
$result_trend = mysql_query("select Week, New_Tickets, Closed_Tickets,
Backlogged, Resolution_Rate, Transactions from table");
while($row = mysql_fetch_array($result_trend))
{
echo "<tr>";
echo "<td>" . $row['Week'] . "</td>";
echo "<td>" . $row['New_Tickets'] . "</td>";
echo "<td>" . $row['Closed_Tickets'] . "</td>";
echo "<td>" . $row['Backlogged'] . "</td>";
echo "<td>" . $row['Resolution_Rate'] . "</td>";
echo "<td>" . $row['Transactions'] . "</td>";
}
echo "</tr>";
?>
I am not really sure how to proceed further. Any suggestion is much appreciated. Thanks in advance.
You can define a CSS style for the first and last rows as below:
.my-table tbody tr:first-child {
background-color: yellow;
}
<table class="my-table">
<thead>
<tr>
<td>Col 1</td>
<td>Col 2</td>
</tr>
</thead>
<tbody>
<tr>
<td>First</td>
<td>Row</td>
</tr>
<tr>
<td>Second</td>
<td>row</td>
</tr>
<tr>
<td>Third</td>
<td>row</td>
</tr>
</tbody>
</table>
You can simply obtain number of results and then count iterations. And if this is 1. row or last, add the style you need or css class that you'll style in your css file. Like this:
<?php
$result_trend = mysql_query("select Week, New_Tickets, Closed_Tickets,
Backlogged, Resolution_Rate, Transactions from table");
$rows_count = mysql_num_rows($result_trend);
$i = 0;
while($row = mysql_fetch_array($result_trend))
{
$i++;
$style = "";
if($i == 1 || $i == $rows_count) {
// $style .= "bgcolor=\"#FF0000\"" //for inline style, bad practise
$style .= "class=\"colorful\""
}
echo "<tr " . $style . ">";
echo "<td>" . $row['Week'] . "</td>";
echo "<td>" . $row['New_Tickets'] . "</td>";
echo "<td>" . $row['Closed_Tickets'] . "</td>";
echo "<td>" . $row['Backlogged'] . "</td>";
echo "<td>" . $row['Resolution_Rate'] . "</td>";
echo "<td>" . $row['Transactions'] . "</td>";
}
echo "</tr>";
?>
The following code adds a Accept/Decline Button per row. But for some reason, the decline button does not appear. I dont know whats wrong. Been stuck for a while now. Help would be appreciated. Thanks!!
<?php
$con=mysqli_connect("localhost","root","","rabco");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM service_request");
echo "<table border='1'>
<tr>
<th>Service ID</th>
<th>Service Type</th>
<th>Schuduled Date</th>
<th>Scheduled Time</th>
<th>Client Reference
<th>Client ID</th>
<th>Admin ID</th>
<th>Special Instructions</th>
<th>Status</th>
<th>Approve</th>
<th>Decline</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['Service_ID'] . "</td>";
echo "<td>" . $row['Service_type'] . "</td>";
echo "<td>" . $row['Sched_date'] . "</td>";
echo "<td>" . $row['Sched_time'] . "</td>";
echo "<td>" . $row['Client_reference'] . "</td>";
echo "<td>" . $row['Client_IDN'] . "</td>";
echo "<td>" . $row['Admin_IDN'] . "</td>";
echo "<td>" . $row['Special_instructions'] . "</td>";
echo "<td>" . $row['Request_status'] . "</td>";
echo "<td>Approve</td>";
echo "<td>Decline</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
You are missing the closing quotes on your href attributes, which is creating malformed HTML output.
You need to change:
echo "<td>Approve</td>";
echo "<td>Decline</td>";
to
echo "<td><a href='approve.php?Service_ID=".$row['Service_ID']."'>Approve</a></td>";
echo "<td><a href='decline.php?Service_ID=".$row['Service_ID']."'>Decline</a></td>";
There is a missing closing quote here:
echo "<td>Approve</td>";
Change to:
echo "<td><a href='approve.php?Service_ID=".$row['Service_ID']."'>Approve</a></td>";
I'm pretty confused about the fact that I have this code:
while($row = mysql_fetch_array($result)) {
echo "<tr href='http://google.com'>";
echo "<td>" . $row['rowname'] . "</td>";
echo "<td>" . $row['rowname2'] . "</td>";
echo "<td>" . $row['rowname3'] . "</td>";
echo "<td>" . $row['rowname4'] . "</td>";
echo "</tr>";
}
and for some reason my link doesn't work. I've tried putting a tag around the tr but with no success. Somebody to have a clue?
Guess you are looking for link to entire row. This can be achieved by having onClick function on the row, instead of using href.
<tr onClick="location.href='target url'">
<td></td>
<td></td>
</tr>
while($row = mysql_fetch_array($result)) {
echo "<tr onclick='window.location.href = \"http://google.com\";'>";
echo "<td>" . $row['rowname'] . "</td>";
echo "<td>" . $row['rowname2'] . "</td>";
echo "<td>" . $row['rowname3'] . "</td>";
echo "<td>" . $row['rowname4'] . "</td>";
echo "</tr>";
}
If you want to make entire row clickable and work like an a tag you should use javascript for this:
echo "<tr onclick='location.href = \"http://google.com\"'>";
And then it would be nice to add CSS cursor pointer to clickable table cells:
tr td {
cursor: pointer;
}
a tr-tag has no href attribute, see here.
you can do something like:
<tr>
<td>
Google
</td>
....
</tr>
Another Solution would be adding javascript if the whole row should be clickable:
<tr onclick="window.location.href = google.com">
<td>
<a href="google.com"</a>
</td>
....
</tr>
Trying to add tablesorter added to a page I am creating. I know very little of jquery, so I'm guessing that's where my fault is. I've added the required code in the <head> area of my page, and made the necessary changes to my table. My table still renders as it would with just HTML. Ideas?
<html>
<head>
<title>Inventory</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/2.0.3/jquery.min.js"></script>
<script type="text/javascript" src="http://tablesorter.com/__jquery.tablesorter.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){ $("table").tablesorter(); });
</script>
</head>
<body>
<?php
$con=mysqli_connect("localhost","user","pass","db_name");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query = "SELECT
products.name,
products.sku,
inventory.quantityfry,
inventory.quantityjuv,
inventory.quantityadult,
inventory.notes,
inventory.location,
inventory.owner
FROM
products
INNER JOIN
inventory
ON
products.sku=inventory.sku";
$result = mysqli_query($con,$query) or die(mysqli_error($con));
echo "<table border='1' id='table' class='tablesorter'>
<thead>
<tr>
<th>Species</th>
<th>SKU</th>
<th>Fry Count</th>
<th>Juvie Count</th>
<th>Adult Count</th>
<th>Notes</th>
<th>Location</th>
<th>Owner</th>
</tr>
</thead>";
while ($row = mysqli_fetch_assoc($result)) {
echo "<tbody>";
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['sku'] . "</td>";
echo "<td>" . $row['quantityfry'] . "</td>";
echo "<td>" . $row['quantityjuv'] . "</td>";
echo "<td>" . $row['quantityadult'] . "</td>";
echo "<td>" . $row['notes'] . "</td>";
echo "<td>" . $row['location'] . "</td>";
echo "<td>" . $row['owner'] . "</td>";
echo "</tr>";
echo "</tbody>";
}
mysqli_free_result($result);
echo "</table>";
mysqli_close($con);
?>
</body>
</html>
Thanks!
Three things:
Don't link directly to tablesorter at tablesorter.com - make a copy to your own server, or use a copy at a CDN (this is of my fork of tablesorter at cdnjs.com).
Include a <!DOCTYPE html> at the top of your HTML otherwise IE will change into quirks mode and pretty much make your site look bad.
As #MikeB mentioned, the above code wraps every row in a tbody, correct the code as follows (this is just a snippet):
echo "<table border='1' id='table' class='tablesorter'>
<thead>
<tr>
<th>Species</th>
<th>SKU</th>
<th>Fry Count</th>
<th>Juvie Count</th>
<th>Adult Count</th>
<th>Notes</th>
<th>Location</th>
<th>Owner</th>
</tr>
</thead><tbody>";
while ($row = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['sku'] . "</td>";
echo "<td>" . $row['quantityfry'] . "</td>";
echo "<td>" . $row['quantityjuv'] . "</td>";
echo "<td>" . $row['quantityadult'] . "</td>";
echo "<td>" . $row['notes'] . "</td>";
echo "<td>" . $row['location'] . "</td>";
echo "<td>" . $row['owner'] . "</td>";
echo "</tr>";
}
mysqli_free_result($result);
echo "</tbody></table>";
im making some application form in PHP.
im putting all info returned from the database into a table.
Now i want to create a button on each line that changes something in the DB of that line.
but i have no idea to do that :S
Thank you!
echo "<table border='1'>
<tr>
<th>Id</th>
<th>Name</th>
<th>Email</th>
<th>age</th>
<th>position</th>
<th>experience</th>
<th>motivation</th>
<th>date</th>
<th>status</th>
<th>test</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['position'] . "</td>";
echo "<td>" . $row['exp'] . "</td>";
echo "<td>" . $row['motivation'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td>" . '<input type="submit" name="submit" value="accept">' . "</td>";
echo "</tr>";
}
echo "</table>";
EDIT: get it working using another script:
echo "<td>Approve</td>";
and edit.php:
<?php
include("dbconnect.php");
$member_id = $_GET['id'];
$status = $_GET['status'];
echo $member_id;
echo $status;
if ($status == 'app')
$query = "update apps set status = 'approved' where id = $member_id";
mysql_query($query) or die (mysql_error());
?>
Create small form with parameters in the cell you want the button to do smth. This is the simpliest approach (approach with refresh).
One more solution is to use AJAX on button click and forward action to some endpoint. This way it would be dynamic and probably what you are want to implement.
echo "<table border='1'>
<tr>
<th>Id</th>
<th>Name</th>
<th>Email</th>
<th>age</th>
<th>position</th>
<th>experience</th>
<th>motivation</th>
<th>date</th>
<th>status</th>
<th>test</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['position'] . "</td>";
echo "<td>" . $row['exp'] . "</td>";
echo "<td>" . $row['motivation'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td>" . '<form type="POST"><input type="hidden" name="whatever" value="$row['id']"><input type="submit" name="submit_btn" value="accept"></form>' . "</td>";
echo "</tr>";
}
echo "</table>";
in this way, you could get a form in each row of the table. Now, you just need to use php POST function.
if(isset($_POST['submit_btn']))
{
//whatever u need to do
}