PHP - Search String And Remove Element in Json - php

Question

I want to search string in json and remove it, but my code doesn't work,
this example of json :
{
d: {
results: [
{
name: "first",
Url: "http://example.com/tes.pdf"
},
{
name: "second",
Url: "http://example.com/download/qwdahfvajvlaksjkjdfaklfaf"
}
]
}
}
and this my php code :
$result = file_get_contents("cache.json");
$jsonObj = json_decode($result);
foreach($jsonObj->d->results as $key => $value) {
if(strpos($value->Url, '.pdf') !== true) {
unset($key->$value);
}
}
echo json_encode($jsonObj);
in this case, i want to remove element second is not contain url ".pdf",
anyone can help me?

Answer 1

try this:
$result = '{"d":{"results":[{"name": "first","Url": "http://example.com/tes.pdf"},{"name": "second","Url": "http://example.com/download/qwdahfvajvlaksjkjdfaklfaf"}]}}';
$jsonArr= json_decode($result, true); //this is an array
foreach($jsonArr['d']['results'] as $key => $value) {
if(strpos($value['Url'], '.pdf') !== false) {
continue; //found so not interested in it
} else {
unset($jsonArr['d']['results'][$key]);
}
}
echo json_encode($jsonArr);
When I work with keys and values, I like to convert (if needed) it to an array. It's easier to understand and manipulate.
Hope this helps! :D

Answer 2

Your best bet would be converting it to an array, using json_decode(); from there, you can iterate through your array. If it stays in the same structure, then something like the following should work:
<?php
$a = $array['d']['results'];
foreach($a as $b => $c) {
if(strpos($c['Url'], '.pdf') !== FALSE) {
// Found
} else {
unset($a[$b]); // Unset in original array.
}
}