How do you select multiple rows from a mysql table? - php

Question

I have a php script that is supposed to get multiple rows from a table and then wrap each row as an array into another array.
$comQy = "SELECT * FROM comments WHERE user = '$user' ORDER BY DESC;";
$comSt = $db->prepare($revQy);
$comRes = $comSt->execute();
$coms = $comSt->fetchAll();
Later in the page, I try to echo one of the elements of the array and then it doesn't work but doesn't return an error.
<div id="comUser">
<?php echo $coms[0]['user'] ?>
</div>
I appreciate all help and I am sorry if I have made a fairly simple mistake in the php script.

Answer 1

This could be the problem of
missing the field name for the ORDER BY clause in the SQL query
missing the variable declaration $revQy
missing the object variable declaration $revSt
$comSt = $db->prepare($revQy);
$comRes = $revSt->execute();
Enabling error reporting is a good practice during development. Add these lines of code at the top of your script.
error_reporting(E_ALL);
ini_set('display_errors',1);
ini_set('display_startup_errors',1);

Answer 2

$comQy = "SELECT * FROM comments WHERE user = :user ORDER BY 1 DESC;";
$comSt = $db->prepare($comQy);
$comRes = $comSt->execute(array( 'user' => $user ));
$comSt->setFetchMode(PDO::FETCH_ASSOC);
$coms = $comSt->fetchAll();

Answer 3

try to use msqli procedural method (im just a newbie too)
$sql = 'SELECT * FROM comments WHERE user = "'.$user.'" ORDER BY fieldname DESC';
$result = mysqli_query($db_connection, $sql);
while($row = mysqli_fetch_assoc($result)){
echo $row['user'];
}