PHP if with an array SQL - php

Question

I've got a problem here
$resultContLog = mysql_query("SELECT count(*) FROM dailyLogs WHERE data_log > NOW() - INTERVAL 30 MINUTE and server_id_log=".$Fid.";");
$Adata = mysql_fetch_assoc($resultContLog);
if ($Adata > 0)
{
echo 'OK';
}
else
{
echo 'NOT OK';
}
My php function returns the number of rows; i did this to include new logs if it happen later than 10 minutes. The if ($Adata > 0) statement doesn't work properly. Can you guys help me, please?

Answer 1

to check this , use this
Your need to check for count column you are getting from query if it is grater than zero, here it is used as alias of "total"
$resultContLog=mysql_query("SELECT count(*) as total FROM dailyLogs WHERE data_log > NOW() - INTERVAL 30 MINUTE and server_id_log=".$Fid.";");
$Adata=mysql_fetch_assoc($resultContLog);
if($Adata['total'])
{
echo 'OK';
}
else
{
echo 'NOT OK';
}

Answer 2

You fetch the DB result as an array, thus you can count it:
if (count($Adata)) {
echo 'ok';
} else {
echo 'not ok';
}
Your query is a bit of a mess though. Maybe you could place some logic outside of the SQL.
The date function of PHP is flexible and works good with MySql.
// instead of NOW() - INTERVAL 30 MINUTE
date("Y-m-d H:i:s", time() - 60*30);
Regards
*) edit: What #esqew said