Can't pass a variable from php to exec - php

I have some PHP code which gets the contents from "php://input".
if (!isset($HTTP_RAW_POST_DATA)) {
$HTTP_RAW_POST_DATA = file_get_contents("php://input");
Now, I'm trying to remove the XML tags from $HTTP_RAW_POST_DATA using sed, like this:
exec("/usr/bin/sed -e 's/\<3\>//g' -e 's/\<\/3\>//g' $HTTP_RAW_POST_DATA");
Then, I try echoing $HTTP_RAW_POST_DATA like this:
echo("$HTTP_RAW_POST_DATA");
But it still returns it with <3> and </3>. Seems like sed can't read the variable.
What can I do to fix this? I get no error messages.

Just use strip_tags() - http://php.net/manual/en/function.strip-tags.php - does exactly what you want sed to do without the horrible security implications.

Related

How to run file in background by adding variable

Hey PHP developers I am newbie.
Today I want to run my process.php file in the background because it takes too much time to load... Here is the code that I want to use.
$proc=new BackgroundProcess();
$proc->setCmd('exec php <BASE_PATH>/process.php hello world');
$proc->start();
And I want to add this ids=$postid&reaction=$reaction variable instead of hello world.
And want to receive it with post in process.php file like this
$id =$_POST['ids'];
$type = $_POST['reaction'];
I am using this GitHub file
https://github.com/pandasanjay/php-script-background-processer/blob/master/README.md
Before doing downvote answer me I am a newbie in PHP.
You can try exec() for this. If you want to pass parameters then try like this.
//it will store logs to log_data.log
exec("php process.php $id $type >log_data.log &");
Hope this will work for you :)
Try like this
function execInBackground() {
//this will run in background
exec("php process.php $id $type > /dev/null &");
}
As soon as it is not HTTP request at all, you cannot access $_GET and $_POST superglobals. The right way to receive arguments in this case, is to access the array $argv. See official documentation:
http://php.net/manual/en/reserved.variables.argv.php
UPD: And, well, if you really want to pass $_GET/$_POST params to this script executed via shell, here is a dirty trick:
$get_params_as_string = base64_encode(json_encode($_GET));
$proc=new BackgroundProcess();
$proc->setCmd("exec php <BASE_PATH>/process.php {$get_params_as_string}");
$proc->start();
And in your process.php access it like this:
$get_params = json_decode(base64_decode($argv[1]), true);
So, we are just created JSON from $_GET array. Then, as we know that JSON string contains special characters(like ", {, }, etc), and to avoid dealing with problems of escaping and unescaping, we simply encode this string as base64. It guarantees us absence of special characters in result string. Now we can use this string as a single argument, which we will pass to shell command (your BackgroundProcess). And finally, in process.php we can access this string from $args[1], then decode from base64, then decode from JSON to a regular PHP array. Here we go.
This solution is provided only for educational purpose, please don't ever do it in real life.

eval() function in PHP, how to make this work properly on the website?

I have a problem with eval() function. Please do not comment something like "Don't use eval" or anything of this kind of thing, as this is not helpful. I have a very good reason to use eval().
Basically I am getting a value from a text field in html on my web page as input code to be executed, like so:
$code = $_POST['code'];
Then, am passing that value to eval function in the html body, like so:
eval($code);
the results are displayed like this:
<h1>test</h1>
the above is displayed string. I want this to execute the html part of it is well. Funny thing is if I try this in a different file like this:
<?php
$code = "echo '<h1><b>TEST</b></h1>';";
eval($code);
?>
I get the desired result, which is a proper processed html element h1 with "TEST" in it.
Any ideas?
Thanks in advance
$_POST['code'] apparently contains HTML entity codes, e.g.
"echo '<h1>test</h1&gt';"
You need to decode it before calling eval.
eval(html_entity_decode($_POST['code']));

Getting STDOUT of system(); call in PHP

I would like to ask you if i call any application with system(); in PHP5 is it possible to get result of that application directly to php? (instead of doing SomeApp >> file.txt - and reading file in PHP).
For example: system('lynx page.html');
and i'd like to put result of 'lynx page.html' into variable.
Thank you.
The easiest way would be to use the backtick operator:
$out = `ls -a`;
You can also use shell_exec("command"), which is equivalent.

Inline PHP (command line)

I would like to make something like tryruby.org. I take a line from the user (e.g., echo __FILE__) and I want to execute it in PHP and return the output back to the client.
I tried to do exec('php -r ' . $command, $output), but $output always contains the PHP help section.
How can I implement this feature?
To make php -r you have to have to put the code you want to execute between ' .. your code .. '
Example:
php -r ' $var = 34; print_r($var); '
It looks like your problem is that you aren't wrapping your code to be executed with ' '. You also need to be wary of ' in the code, special characters, escape sequences, etc.
In fact, if you insist on using exec(), it might be better to do this (to completely avoid having to worry about escaping and the such):
$command = base64_encode($command);
exec("php -r 'eval(base64_decode(\"$command\"));'", $output);
You could use eval() instead of what you're posting above.
The main issue here (both with eval() and your exec() code) is that taking PHP code from user input simply isn't safe:
The eval() language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand.
Suggestion
Since you want to return the result of the PHP code, you could potentially do something cool with Ajax, where you pass the PHP code to a script (Base64 encoded, perhaps) as a parameter:
$code = base64_decode($_GET['code']);
// Clean the user input here
eval($code);
Ajax example using jQuery:
// assuming `code` contains the PHP code
var encoded = base64_enc(code);
$.get('execute.php?code=' + encoded, function(data) {
var result = new String(data);
// do something with the result here, such as displaying it
}, dataType='text');
For Base64 encoding in JavaScript, see this.
http://tryruby.org seems have an interactive Ruby shell. That seems to be a good starting point.
Here are two projects that provide such a shell for PHP: php_repl and phpsh.
The other part is the web interface for the interactive shell. For that part, I suggest you have a look at repl.it, which provides this service for many languages (but sadly not PHP). Here's a link to it's source code.
With this combination, you should be able to complete cour project.
Look up 'eval()' and more importantly, why eval() and what you're trying to do is very difficult to achieve in a secure manner. Imaging for example the user who inputs:
echo file_get_contents('/etc/passwd');
You'll need quite a bit of work to make this secure, including watching and filtering all system calls being made from the eval'd process.
Cheers

how to eval() a segment of a string

I have a string that has HTML & PHP in it, when I pull the string from the database, it is echo'd to screen, but the PHP code doesn't display. The string looks like this:
$string = 'Hello <?php echo 'World';?>';
echo $string;
Output
Hello
Source Code
Hello <?php echo 'World';?>
When I look in the source code, I can see the php line there. So what I need to do is eval() just the php segment that is in the string.
One thing to consider is that the PHP could be located anywhere in the string at any given time.
* Just to clarify, my PHP config is correct, this is a case of some PHP being dumped from the database and not rendering, because I am echo'ing a variable with the PHP code in it, it fails to run. *
Thanks again for any help I may receive.
$str = "Hello
<?php echo 'World';?>";
$matches = array();
preg_match('/<\?php (.+) \?>/x', $str, $matches);
eval($matches[1]);
This will work, but like others have and will suggest, this is a terrible idea. Your application architecture should never revolve around storing code in the database.
Most simply, if you have pages that always need to display strings, store those strings in the database, not code to produce them. Real world data is more complicated than this, but must always be properly modelled in the database.
Edit: Would need adapting with preg_replace_callback to remove the source/interpolate correctly.
You shouldn't eval the php code, just run it. It's need to be php interpreter installed, and apache+php properly configured. Then this .php file should output Hello World.
Answer to the edit:
Use preg_replace_callback to get the php part, eval it, replace the input to the output, then echo it.
But. If you should eval things come from database, i'm almost sure, it's a design error.
eval() should work fine, as long as the code is proper PHP and ends with a semicolon. How about you strip off the php tag first, then eval it.
The following example was tested and works:
<?php
$db_result = "<?php echo 'World';?>";
$stripped_code = str_replace('?>', '', str_replace('<?php', '', $db_result));
eval($stripped_code);
?>
Just make sure that whatever you retrieve from the db has been properly sanitized first, since you're essentially allowing anyone who can get content into the db, to execute code.

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