add data to json (php) - php

Question

can someone please help me to add data to following json.
$temp='{
"custId": 123,
"data": [
{
"code": "abc1"
},
{
"code": "abc2"
}
],
"id": 102
}';
data to be added
$data1='{
"code": "abc3"
}';
Desired result
$temp='{
"custId": 123,
"data": [
{
"code": "abc1"
},
{
"code": "abc2"
},
{
"code": "abc3"
}
],
"id": 10
}';
I can append data to $temp, but can someone please help to add data to specific position with php. Thank you in advance. (I've tried json_decode($temp, true) and then finding the location where data1 is to be added but failed).

Answer 1

You can convert your data to a normal PHP array:
$array = json_decode($temp, true);
then just add or change anything you want:
$array["data"][] = array(["code"] => "abc3");
and re-encode to json:
$temp = json_encode($array);// encode to json
http://php.net/manual/en/function.json-decode.php

Answer 2

first, you need to convert the JSON into PHP array like this:
$array = json_decode($temp, true);
Then, it's as simple as:
$array['data']['code'] = 'abc3';
If the string that you want to add is still a JSON, you have to convert that one in an array as well so:
$arr_to_add = json_decode($data1, true);
$array['data'][] = $arr_to_add;
In the end, of course, encode again like this:
$final_json = json_encode($array);
Hope this helps! :D

Answer 3

First you need to decode the json with json_decode. This returns a PHP variable.
Add desired values.
Use json_encode to get the json with new values. Returns a string containing the JSON.

Answer 4

you can try this:
<?php
$temp='{
"custId": 123,
"data": [
{
"code": "abc1"
},
{
"code": "abc2"
}
],
"id": 102
}';
$data1='{
"code": "abc3"
}';
$jarr=json_decode($temp,true);
$appArr=json_decode($data1,true);
$desire=array_merge($jarr,$appArr);
//print_r($desire);
echo json_encode($desire);