Return Specific Row From DB - php

Question

I have multiple links on a page where each link is suppose to return a specific row of data from a database. When the link is clicked, the user is forwarded to another page where the info associated with that link is displayed. Here is the code:
//db connection: (using xampp)
mysql_connect('localhost', 'root', '');
mysql_select_db('db_name');
$sql = "SELECT * FROM user_input";
$records = mysql_query($sql);
//code:
<div>
$open_report = mtsql_fetch_assoc($records);
echo "Error Report# {$open_report['id']};
echo "<p>" .$open_report['comments'] . "</p>";
</div>
The problem is it always returns the same row of data. Each row in the db is associated with a link and when that link is clicked I want to return the associated row of data in the db. I think it may have to do with this line: $sql = "SELECT * FROM user_input"; but I'm not sure how to fix it. If anyone can help it would be greatly appreciated.

Answer 1

I have restructured my answer to give it a better flow. I also noticed you are using mysql_ not mysqli_ . You need to use mysqli_ as mysql is depreciated.
EDIT: This would be the page that displays all the error reports. You would want to output them in the form of a hyperlink that passes a GET parameter to the page that shows the details.
$sql = "SELECT ID, Description, etc, etc from reports";
$open_reports = mysqli_query($sql);
//error check here as well if ANY results were returned
while($row = mysqli_fetch_array($open_reports, MYSQLI_ASSOC)) {
echo ''' . $open_reports['Description'] . '';
}
This will give you links that look like
detailspage.php?id=1 detailspage.php?id=2
etc...
On the "detailspage.php" You can capture that ID and display dynamic information on that same page.
if (isset($_GET['ID'])){
$sql = "Select * from user_input where ID='" . $_GET['id'] . "'";
$records = mysqli_query($sql)
while($open_report = mysqli_fetch_array($records, MYSQLI_ASSOC)) {
echo "Error Report# " . $open_report['id'] . "<br/>";
echo "<p>" .$open_report['comments'] . "</p>";
}
}